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(完整word版)2016年文数高考试题全国卷2(含答案),推荐文档.pdf

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1、1 2016 年普通高等学校招生全国统一考试(卷 2)文科数学注意事项：1本试卷分第卷（选择题）和第卷（非选择题）两部分。答卷前，考生务必将自己的姓名、准考证号填写在本试卷和答题卡相应位置上。2回答第卷时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号框涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号框。写在本试卷上无效。3答第卷时，将答案写在答题卡上，写在本试卷上无效。4考试结束，将试题卷和答题卡一并交回。第卷一、选择题：本大题共12 小题。每小题5 分，在每个小题给出的四个选项中，只有一项是符合要求的。（1）已知集合123A，2|9Bx x，则 ABID（A）21 0 1 2 3，

2、（B）21 0 1 2，（C）1 2 3，（D）1 2，（2）设复数 z 满足i3iz，则 z=（A）12i（B）12i（C）32i（D）32i(3)函数=sin()y Ax的部分图像如图所示，则A（A）2sin(2)6yx（B）2sin(2)3yx（C）2sin(2+)6yx（D）2sin(2+)3yx(4)体积为 8 的正方体的顶点都在同一球面上，则该球面的表面积为精品资料-欢迎下载-欢迎下载名师归纳-第 1 页，共 10 页 -2（A）12（B）323（C）（D）(5)设 F 为抛物线 C：y2=4x 的焦点，曲线y=kx（k0）与 C 交于点 P，PFx 轴，则 k=（A）12（B）

3、1（C）32（D）2(6)圆 x2+y2-2x-8y+13=0 的圆心到直线ax+y-1=0 的距离为 1，则 a=（A）-43（B）-34（C）3（D）2(7)如图是由圆柱与圆锥组合而成的几何体的三视图，则该几何体的表面积为（A）20（B）24（C）28（D）32(8)某路口人行横道的信号灯为红灯和绿灯交替出现，红灯持续时间为40 秒.若一名行人来到该路口遇到红灯，则至少需要等待15 秒才出现绿灯的概率为学.科网（A）710（B）58（C）38（D）310(9)中国古代有计算多项式值得秦九韶算法，右图是实现该算法的程序框图执行该程序框图，若输入的a 为 2，2，5，则输出的s=（A）7（B）

4、12（C）17（D）34(10)下列函数中，其定义域和值域分别与函数y=10lgx的定义域和值域相同的是（A）y=x（B）y=lgx（C）y=2x（D）1yx(11)函数()cos26cos()2fxxx的最大值为（A）4（B）5（C）6（D）7 精品资料-欢迎下载-欢迎下载名师归纳-第 2 页，共 10 页 -文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2

5、X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档

6、编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2

7、X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档

8、编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2

9、X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档

10、编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P6文档编码:CX8L9L8C3R4 HB3W2X1Y9O6 ZR1Q1R7K4P63(12)已知函数 f(x)（xR）满足 f

11、(x)=f(2-x)，若函数 y=|x2-2x-3|与 y=f(x)图像的交点为（x1,y1），(x2,y2)，（xm,ym），则1=miix(A)0(B)m(C)2m(D)4m 二填空题：共4 小题，每小题5 分.(13)已知向量 a=(m,4)，b=(3,-2)，且 a b，则 m=_.(14)若 x，y 满足约束条件103030 xyxyx，则 z=x-2y 的最小值为 _（15）ABC 的内角 A，B，C 的对边分别为a，b，c，若4cos5A，5cos13C，a=1，则 b=_.（16）有三张卡片，分别写有1 和 2，1 和 3，2 和 3.学.科网甲，乙，丙三人各取走一张卡片，甲看

12、了乙的卡片后说：“我与乙的卡片上相同的数字不是2”，乙看了丙的卡片后说：“我与丙的卡片上相同的数字不是 1”，丙说：“我的卡片上的数字之和不是5”，则甲的卡片上的数字是_.三、解答题：解答应写出文字说明，证明过程或演算步骤（17）(本小题满分12 分)等差数列 na 中，34574,6aaaa（I）求 na的通项公式；(II)设nb=na，求数列 nb的前 10 项和，其中 x 表示不超过x 的最大整数，如0.9=0,2.6=2（18）(本小题满分12 分)某险种的基本保费为a（单位：元），继续购买该险种的投保人称为续保人，续保人本年度的保费与其上年度出险次数的关联如下：学科.网随机调查了该险

13、种的200 名续保人在一年内的出险情况，得到如下统计表：（I）记 A 为事件：“一续保人本年度的保费不高于基本保费”。求 P(A)的估计值；精品资料-欢迎下载-欢迎下载名师归纳-第 3 页，共 10 页 -文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M

14、5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10

15、M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A1

16、0M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A

17、10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1

18、A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL

19、1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 H

20、L1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H54(II)记 B 为事件：“一续保人本年度的保费高于基本保费但不高于基本保费的160”.求 P(B)的估计值；（III）求续保人本年度的平均保费估计值.（19）（本小题满分12 分）如图，菱形 ABCD 的对角线 AC 与 BD 交于点 O，点 E、F 分别在 AD，CD 上，AE=CF，EF 交 BD 于点 H，将DEFV沿 EF 折到D EFV的位置.（I）证明：ACHD；(II)若55,6,2 24ABACAEOD,求五棱锥 ABCEFD体积.（20）（

21、本小题满分12 分）已知函数()(1)ln(1)f xxxa x.（I）当4a时，求曲线()yf x在1,(1)f处的切线方程；(II)若当1,x时，()0f x，求a的取值范围.（21）（本小题满分12 分）已知 A 是椭圆 E：22143xy的左顶点，斜率为0k k的直线交E 于 A，M 两点，点 N 在 E 上，MANA.（I）当AMAN时，学.科网求AMNV的面积(II)当 2AMAN时，证明：32k.请考生在第2224 题中任选一题作答，如果多做，则按所做的第一题计分.（22）（本小题满分10 分）选修 4-1：几何证明选讲如图，在正方形ABCD 中，E，G 分别在边 DA，DC 上

22、（不与端点重合），且 DE=DG，过 D 点作 DFCE，垂足为 F.精品资料-欢迎下载-欢迎下载名师归纳-第 4 页，共 10 页 -文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3

23、 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S

24、3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5

25、S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U

26、5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6

27、U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I

28、6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8

29、I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H55（）证明：B，C，G，F 四点共圆；（）若 AB=1，E 为 DA 的中点，求四边形BCGF 的面积.（23）（本小题满分10 分）选修 4-4：坐标系与参数方程在直角坐标系xOy 中，圆 C 的方程为22(+6)+=25xy.（）以坐标原点为极点，x 轴的正半轴为极轴建立极坐标系，学.科网求 C 的极坐标方程；（）直线 l 的参数方程是cossinxt,yt,=?=?（t 为参数），l 与 C 交于 A，B 两点，10AB=,求 l 的斜率.（24）（本小题满分10 分）选修 4-5：不等式选讲已知函数11()22f xxx

30、=-+，M 为不等式()2f x 的解集.学科.网（）求 M；（）证明：当a，bM?时，1abab+.精品资料-欢迎下载-欢迎下载名师归纳-第 5 页，共 10 页 -文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5

31、文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H

32、5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6

33、H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H

34、6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1

35、H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V

36、1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8

37、V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H56 2016年普通高等学校招生全国统一考试文科数学答案第卷一.选择题（1）D（2）C(3)A(4)A(5)D(6)A(7)C(8)B(9)C(10)D(11)B (12)B 二填空题(13)【答案】6(14)【答案】5（15）【答案】2113（16）【答案】1 和 3三、解答题（17）(本小题满分12 分)试题分析：()根据等差数列的性质求1a，d，从而求得na；（）根据已知条件求nb，再求数列nb的前 10 项和.试题解析：()设数列na的公差为 d，学.科网由题意有11254,53adad，解

38、得121,5ad，所以na的通项公式为235nna.（）由()知235nnb，当 n=1,2,3 时，2312,15nnb；当 n=4,5 时，2323,25nnb；当 n=6,7,8 时，2334,35nnb；当 n=9,10 时，2345,45nnb，所以数列nb的前 10 项和为1 3223 34224.考点：等茶数列的性质，数列的求和.（18）(本小题满分12 分)()事件A 发生当且仅当一年内出险次数小于2.由所给数据知，一年内险次数小于2 的频率为60500.55200，故 P(A)的估计值为0.55.（）事件B发生当且仅当一年内出险次数大于1 且小于 4.由是给数据知，学.科网一

39、年内出险次数大于1精品资料-欢迎下载-欢迎下载名师归纳-第 6 页，共 10 页 -文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H

40、5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6

41、H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H

42、6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1

43、H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V

44、1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8

45、V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B

46、8V1H6H57 且小于 4 的频率为30300.3200，故 P(B)的估计值为0.3.()由题所求分布列为：保费0.85a a 1.25a 1.5a 1.75a 2a 频率0.30 0.25 0.15 0.15 0.10 0.05 调查 200 名续保人的平均保费为0.850.300.25 1.250.15 1.50.15 1.750.3020.101.1925aaaaaaa，因此，续保人本年度平均保费估计值为1.1925a.考点：样本的频率、平均值的计算.（19）（本小题满分12 分）（I）由已知得，,.ACBD ADCD又由AECF得AECFADCD，故/.ACEF由此得,EFHD E

47、FHD，所以/.ACHD.（II）由/EFAC得1.4OHAEDOAD由5,6ABAC得224.DOBOABAO所以1,3.OHD HDH于是22222(22)19,ODOHD H故.ODOH由（I）知ACHD，又,IACBD BDHDH，所以AC平面,BHD于是.ACOD又由,IODOH ACOHO，所以，OD平面.ABC又由EFDHACDO得9.2EF五边形ABCFE的面积11969683.2224S所以五棱锥ABCEFD体积16923 22 2.342V（20）（本小题满分12 分）（I）()f x的定义域为(0,).当4a时，精品资料-欢迎下载-欢迎下载名师归纳-第 7 页，共 10

48、页 -文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V

49、1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8

50、V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B8V1H6H5文档编码:CG9O8I6U5S3 HL1A10M5M10G3 ZK10B

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