2021年2019年普通高等学校招生全国统一考试理科数学(北京卷)解析版.pdf
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1、2019 年普通高等学校招生全国统一考试(北京卷)理科数学本试卷共 5 页,150 分。考试时长 120 分钟。考生务必将答案答在答题卡上,在试卷上作答无效。考试结束后,将本试卷和答题卡一并交回。第一部分(选择题共 40 分)一、选择题共 8 小题,每小题 5 分,共 40 分。在每小题列出的四个选项中,选出符合题目要求的一项。1.已知复数z=2+i,则z zA.3B.5C.3 D.5【答案】D【解析】【分析】题先求得z,然后根据复数的乘法运算法则即得.【详解】z2i,z z(2i)(2i)5故选 D.【点睛】本容易题,注重了基础知识、基本计算能力的考查.2.执行如图所示的程序框图,输出的s值
2、为A.1 B.2 C.3 D.4|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 19 页【答案】B【解析】【分析】根据程序框图中的条件逐次运算即可.【详解】运行第一次,=1k,22 123 12s,运行第二次,2k,2222322s,运行第三次,3k,2222322s,结束循环,输出=2s,故选 B.【点睛】本题考查程序框图,属于容易题,注重基础知识、基本运算能力的考查.3.已知直线l 的参数方程为13,24xtyt(t 为参数),则点(1,0)到直线l 的距离是A.15B.25C.45D.65【答案】D【解析】【分析】首先将参数方程
3、化为直角坐标方程,然后利用点到直线距离公式求解距离即可.【详解】直线l的普通方程为41320 xy,即 4320 xy,点1,0到直线l的距离22|402|6543d,故选 D.【点睛】本题考查直线参数方程与普通方程转化,点到直线的距离,属于容易题,注重基础知识?基本运算能力的考查.4.已知椭圆22221xyab(a b0)的离心率为12,则A.a2=2b2B.3a2=4b2C.a=2bD.3a=4b|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 19 页文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B
4、9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1
5、Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9
6、L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A
7、5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9
8、B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5
9、N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V
10、6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9【答案】B【解析】【分析】由题意利用离心率的定义和,a b c的关系可得满足题意的等式.【详解】椭圆的离心率2221,2cecaba,化简得2234ab,故选 B.【点睛】本题考查椭圆的标准方程与几何性质,属于容易题,注重基础知识?基本运算能力的考查.5.若 x,y 满足|1|xy,且 y-1,则 3x+y 的最大值为A.-7B.1 C.5
11、D.7【答案】C【解析】【分析】首先画出可行域,然后结合目标函数的几何意义确定其最值即可.【详解】由题意1,11yyxy作出可行域如图阴影部分所示.设3,3zxy yzx,|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 19 页文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7
12、P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:
13、CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10
14、HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 Z
15、E7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编
16、码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U1
17、0 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7
18、 ZE7P3V6A5B9当直线0:3lyzx经过点2,1时,z 取最大值5.故选 C.【点睛】本题是简单线性规划问题的基本题型,根据“画?移?解”等步骤可得解.题目难度不大题,注重了基础知识?基本技能的考查.6.在天文学中,天体的明暗程度可以用星等或亮度来描述.两颗星的星等与亮度满足212152lgEmmE,其中星等为m1的星的亮度为E2(k=1,2).已知太阳的星等是26.7,天狼星的星等是1.45,则太阳与天狼星的亮度的比值为A.1010.1B.10.1 C.lg10.1 D.1010.1【答案】D【解析】【分析】先求出12lgEE,然后将对数式换为指数式求12EE,再求12EE.【详解】
19、两颗星的星等与亮度满足12125lg2EmmE,令21.45m,126.7m,1212221g(1.4526.7)10.155EmmE,10.110.112211010EEEE,故选 D.【点睛】考查考生的数学应用意识、信息处理能力、阅读理解能力以及指数对数运算.7.设点 A,B,C 不共线,则“AB与AC的夹角为锐角”是“|ABACBC”的A.充分而不必要条件B.必要而不充分条件C.充分必要条件D.既不充分也不必要条件【答案】C【解析】|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 4 页,共 19 页文档编码:CF6A9B1Q3U10 HT7
20、X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P
21、3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:C
22、F6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 H
23、T7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE
24、7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码
25、:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10 HT7X5N9L5V7 ZE7P3V6A5B9文档编码:CF6A9B1Q3U10
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