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2018年北京高考试卷(文科)—含答案.pdf

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1、2018 年普通高等学校招生全国统一考试数学（文）（北京卷）本试卷共5 页，150 分。考试时长120 分钟。考生务必将答案答在答题卡上，在试卷上作答无效。考试结束后，将本试卷和答题卡一并交回。第一部分（选择题共40 分）一、选择题共8 小题，每小题5 分，共 40 分。在每小题列出的四个选项中，选出符合题目要求的一项。（1）已知集合A=(?|?|2),B=-2,0,1,2,则ABI（A）0,1（B）-1,0,1（C）-2,0,1,2（D）-1,0,1,2（2）在复平面内，复数11i的共轭复数对应的点位于（A）第一象限（B）第二象限（C）第三象限（D）第四象限（3）执行如图所示的程序框图，输出

2、的s值为第 1 页，共 11 页（A）12（B）56（C）76（D）712（4）设 a,b,c,d 是非零实数，则“ad=bc”是“a,b,c,d 成等比数列”的（A）充分而不必要条件（B）必要而不充分条件（C）充分必要条件（D）既不充分也不必要条件（5）“十二平均律”是通用的音律体系，明代朱载堉最早用数学方法计算出半音比例，为这个理论的发展做出了重要贡献.十二平均律将一个纯八度音程分成十二份，依次得到十三个单音，从第二个单音起，每一个单音的频率与它的前一个单音的频率的比都等于122.若第一个单音的频率为f，则第八个单音的频率为学科#网（A）32 f（B）322 f（C）1252 f（D）12

3、72 f（6）某四棱锥的三视图如图所示，在此四棱锥的侧面中，直角三角形的个数为（A）1（B）2（C）3（D）4（7）在平面直角坐标系中，?,AB CD EF GH是圆221xy上的四段弧（如图），点P在其中一段上，角以 O?为始边，OP 为终边，若tancossin，则 P 所在的圆弧是第 2 页，共 11 页文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8

4、HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T

5、5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5

6、 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4

7、L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9

8、文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:C

9、Y10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V

10、5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9（A）?AB（B）?CD（C）?EF（D）?GH（8）设集合(,)|1,4,2,Ax yxyaxyxay则（A）对任意实数a，(2,1)A（B）对任意实数a，（2,1）A（C）当且仅当a1，则当1(,1)xa时，()0fx；当(1,)x时，()0fx.所以()f x在 x=1 处取得极小值.第 8 页，共 11 页文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10

11、T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4

12、S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7

13、V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码

14、:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G

15、2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B

16、8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G

17、1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9若1a，则当(0,1)x时，110axx，所以()0fx.所以 1 不是()f x的极小值点.综上可知，a 的取值范围是(1,).方法二：()(1)(1)exfxaxx.（1）当 a=0 时，令()0fx得 x=1.(),()fxfx随 x 的变化情况如下表：x(,1)1(1,)()fx+0-()f x极大

18、值()f x在 x=1 处取得极大值，不合题意.（2）当 a0 时，令()0fx得121,1axx.当12xx，即 a=1 时，2()(1)e0 xfxx，()f x在R上单调递增，学科&网()f x无极值，不合题意.当12xx，即 0a1 时，(),()fxf x随 x 的变化情况如下表：x 1(,)a1a1(,1)a1(1,)第 9 页，共 11 页文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9

19、G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档

20、编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY1

21、0G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A

22、1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR

23、4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S

24、10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 Z

25、B4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9()fx+0-0+()f x极大值极小值()f x在 x=1 处取得极小值，即a1 满足题意.（3）当 a0 时，令()0fx得121,1axx.(),()fxfx随 x 的变化情况如下表：x 1(,)a1a1(,1)a1(1,)()fx-0+0-()f x极小值极大值()f x在 x=1 处取得极大值，不合题意.综上所述，a 的取值范围为(1,).20（共14分）【解析】（）由题意得22 2c，所以2c，又

26、63cea，所以3a，所以2221bac，所以椭圆M的标准方程为2213xy（）设直线AB的方程为yxm，由2213yxmxy消去y可得2246330 xmxm，则2223644(33)48120mmm，即24m，设11(,)A xy，22(,)B xy，则1232mxx，212334mx x，则222212121 264|1|1()42mABkxxkxxx x，第 10 页，共 11 页文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR

27、4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S

28、10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 Z

29、B4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9

30、G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档

31、编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY1

32、0G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A

33、1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9易得当20m时，max|6AB，故|AB的最大值为6（）设11(,)A x y，22(,)B xy，33(,)C xy，44(,)D xy，则221133xy，222233xy，又(2,0)P，所以可设1112PAykkx，直线PA的方程为1(2)ykx，由122(2)13yk xxy消去y可得2222111(13)121230kxk xk，则2113211213kxxk，

34、即2131211213kxxk，学科*网又1112ykx，代入式可得13171247xxx，所以13147yyx，所以1111712(,)4747xyCxx，同理可得2222712(,)4747xyDxx故3371(,)44QCxyuuu r，4471(,)44QDxyuuu r，因为,Q C D三点共线，所以34437171()()()()04444xyxy，将点,C D的坐标代入化简可得12121yyxx，即1k第 11 页，共 11 页文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S

35、4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V

36、9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:

37、CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2

38、V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8

39、 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1

40、T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9文档编码:CY10G2V5A1B8 HR4G1T5S10T5 ZB4S4L9G7V9

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关键词：: 2018 北京高考试卷文科答案

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