2014年四川省达州市中考化学试卷.pdf

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1、2014年四川省达州市中考化学试卷参考答案与试题解析一、选择题本大题26 个小题，1-18题每题 3 分，19-26题每题 2 分，1 3 分2014?达州 以下现象与物质的化学性质无关的是 A 绿色植物光合作用 B 铜丝导电 C 固体氢氧化钠露置在空气中质量增加 D 着火点 40 左右的白磷保存在水中考点：化学性质与物理性质的差异及应用专题：物质的变化与性质分析：物质在化学变化中表现出来的性质叫化学性质，化学性质有：可燃性、复原性、氧化性、稳定性、不稳定性、酸碱性、金属的活泼性等；物质不需要发生化学变化就表现出来的性质，叫物理性质；物理性质经常表现为：颜色、状态、气味、密度、硬度、熔点、沸点

2、、导电性、导热性、溶解性、挥发性、延展性等；性质是物质表现出来的特性解答：解：A、绿色植物光合作用生成氧气，与化学性质有关，故选项错误；B、铜丝导电，导电性属于物理性质，与化学性质无关，故选项正确；C、固体氢氧化钠露置在空气中质量增加，是因为二氧化碳与氢氧化钠反应生成了碳酸钠和水的缘故，与化学性质有关，故选项错误；D、着火点40 左右的白磷保存在水中，是因为白磷的着火点低，易自然，与化学性质有关，故选项错误；故选 B 点评：本考点考查了物理性质和化学性质的区分，要记忆有关物质的化学性质和物理性质，并能够在比较的基础上进行应用，本考点的基础性比较强，主要出现在选择题和填空题中 2 3 分 201

3、4?达州以下有关物质的鉴别方法不正确的选项是 A 用燃烧的方法鉴别羊毛和塑料 B 用碘液鉴别淀粉和白糖 C 用肥皂水鉴别硬水和软水 D 用观察颜色的方法鉴别一氧化碳和二氧化碳考点：物质的鉴别、推断；常见气体的检验与除杂方法；硬水与软水；棉纤维、羊毛纤维和合成纤维的鉴别；鉴别淀粉、葡萄糖的方法与蛋白质的性质专题：物质的鉴别题分析：A、依据两者燃烧时产生的气味不同分析判断；B、依据碘液遇淀粉变蓝可判断；C、依据软硬水与肥皂水混合后的现象判断；D、依据二者都是无色无味的气体判断解答：解：A、因为羊毛的主要成分是蛋白质，灼烧时能产生烧焦羽毛的气味；而常见的塑料燃烧一般有刺激性气味，冒黑烟故选项正确；B

4、、碘液遇淀粉变蓝，遇白糖无明显现象选项正确；C、用肥皂水可以鉴别硬水和软水，因为硬水和肥皂水混合能产生大量的浮渣，软水与肥皂水混合能产生大量的泡沫故选项正确；D、一氧化碳和二氧化碳都是无色无味的气体，可以用点燃的木条或澄清石灰水来检验故选项不正确故选 D 点评：在解此类题时，首先分析需要鉴别的物质的性质，然后选择适当的试剂和方法，出现不同的现象即可鉴别3 3 分 2014?达州以下措施或方法不能到达目的是 A 铵态氮肥与熟石灰混合使用，增强肥效 B 用 10mL的量筒量取9.5mL的水 C 用 pH 试纸测得某溶液的 pH 为 7 D 油锅着火，用锅盖盖灭考点：常见化肥的种类和作用；测量容器-

5、量筒；溶液的酸碱度测定；灭火的原理和方法专题：常见的盐化学肥料；化学与生活；常见仪器及化学实验基本操作分析：A、铵态氮肥与熟石灰混合使用，会放出氨气；B、可以用10mL的量筒量取9.5mL的水；C、pH 测得的结果是整数；D、盖上锅盖把空气氧气隔绝了从而使火熄灭解答：解：A、熟石灰是碱，铵态氮肥与熟石灰混合使用，会放出氨气，降低肥效，所以符合题意；B、可以用10mL的量筒量取9.5mL的水，所以不符合题意；文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5

6、F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B

7、4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1

8、D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10

9、R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V

10、1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7

11、V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E

12、10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3C、pH 测得的结果是整数，因此可用pH 试纸测得某溶液的pH 为 7，所以不符合题意；来源:Zxxk.Com D、盖上锅盖把空气 氧气 隔绝了从而使火熄灭，所以不符合题意；故选：A 点评：此题考查了碱的性质和用途，灭火的原理，量筒的选择以及pH试纸的使用等，难度不大 43分2014?达州以下属于 复合肥料的是 A NH4HCO3 B KNO3 C K2SO4 D Ca3 PO42 考点：常见化肥的种类和作用专题：常见的盐化学肥料分析：含有氮元素的肥

13、料称为氮肥，含有磷元素的肥料称为磷肥，含有钾元素的肥料称为钾肥，同时含有氮、磷、钾三种元素中的两种或两种以上的肥料称为复合肥解答：解：A、NH4HCO3中含有氮元素，属于氮肥；故选项错误 B、KNO3 中含有钾元素和氮元素，属于复合肥；故选项正确C、K2SO4 中含有钾元素，属于钾肥；故选项错误D、Ca3 PO4 2 中含有磷元素，属于磷肥；故选项错误故选：B 点评：此题主要考查化肥的分类方面的知识，解答时要分析化肥中含有哪些营养元素，然后再根据化肥的分类方法确定化肥的种类5 如图表示X、Y、Z 三种物质的溶解度曲线，以下说法错误的选项是 A Y 中含有少量X，用海水晒盐的原理提纯Y B t1

14、 时，三种物质的饱和溶液升温到 t2，溶液中溶质质量分数的大小关系是YXZ C t3 时，X、Y 的饱和溶液降温到 t2，析出晶体较多的是X D t3 时，等质量的X、Y 分别配成该温度下的饱和溶液，所得溶液质量XY 考点：固体溶解度曲线及其作用；结晶的原理、方法及其应用；晶体和结晶的概念与现象；溶质的质量分数、溶解性和溶解度的关系专题：溶液、浊液与溶解度分析：A、根据溶解度曲线可知物质的溶解度随温度变化情况，并分析提纯物质的方法；文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3

15、文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5

16、F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B

17、4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1

18、D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10

19、R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V

20、1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7

21、V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3B、根据三种物质的溶解度随温度变化解答；C、根据不知饱和溶液的质量关系解答；D、根据 t3 时，X、Y 的溶解度解答解答：解：A、由图可知：x 的溶解度随温度升高而增大，y 的溶解度受温度影响不大，所以当y 中含有少量 x 时，可以用用海水晒盐的原理提纯Y，故对；B、饱和溶液的溶质质量分数与溶解度有关，在t1 时 x、y、z 三种物质的溶解度大小是：yx=z；所以 t1 时 A、B、C 三种物质饱和溶液的溶质质量分数大小关系

22、是：yx=z；升温后，x 和 y 溶解度变大，都变为不饱和溶液，溶质质量分数不变，所以升温后还是yx，z 物质升温后，溶解度减小，溶质质量分数减小，由于升温后z 物质的溶解度与升温前x 和 y 的溶解度大小关系是：yx=z，所以升温后溶质质量分数大小是：yx z，故对；C、t3 时，X、Y 的饱和溶液的质量关系无法确定，析出晶体的多少无法确定，故错；D、t3 时，X 的溶解度大于Y的溶解度，等质量的X、Y 分别配成该温度下的饱和溶液，所得溶液质量XY，故对答案：C 点评：此题较好考查了学生对于溶解度曲线的意义的掌握和运用，培养了学生分析、解决问题的能力6 3 分 2014?达州以下图象分别与选

23、项中的操作相对应，合理的是 A 向一定质量的稀盐酸中加水 B 一定条件下，一定质量的碳和氧气在密闭容器中反应 C 等质量的镁和铁分别与足量的稀硫酸反应 D 一定温度下，向一定质量的饱和石灰水中加入氧化钙考点：酸碱溶液的稀释；金属的化学性质；生石灰的性质与用途；质量守恒定律及其应用专题：元素化合物知识型分析：A、溶液呈酸性时，溶液的pH 小于 7；B、根据质量守恒定律进行判断；文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4

24、 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文

25、档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F

26、9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4

27、V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D

28、3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R

29、5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1

30、B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3C、等质量两金属完全反应后，根据反应的化学方程式可知，铁产生氢气质量小于镁；D、氧化钙溶于水时会发生反应生成氢氧化钙，把其溶于饱和的氢氧化钙溶液中是会因为其吸水而使溶质析出解答：解：A、向一定量稀硫酸中滴入水，溶液的溶质质量分数变小，即溶液变稀了，但是溶液仍然呈酸性，所以溶液的pH 仍然小于 7，故 A 错误；B、一定条件下，一定质量的碳和氧气在密闭容器中反应，参加化学反应的各物质的质量总和，等于反应后生成各物质的质量总和，即物质的总质量不变，故B 正确；C、镁的相对原子质量小于铁

31、的相对原子质量，在质量相等时，产生的气体多，故 C 错误；D、一定温度时向一定量饱和石灰水中加入氧化钙，氧化钙会与水反应生成氢氧化钙，水被消耗，则氢氧化钙会析出，导致溶液质量减小，不会保持不变，故D 错误；故选：B 点评：此题考查了化学知识与图象的结合，完成此题，可以依据题干提供的信息结合物质的性质进行 7 3 分 2014?达州除去以下物质中的少量杂质，所选用试剂及操作方法均正确的选项是 选项 物质括号内为杂质选用试剂操作方法 A CO2 CO 过量O2 点燃 B CaO CaCO3 足量蒸馏水过滤、蒸发 C NaCl溶液 MgSO4溶液适量BaCl2 溶液 过滤 D FeCl2溶液 CuC

32、l2溶液足量铁粉过滤 来源学科网 A A B B C C 来源:Zxxk.Com D D 考点：物质除杂或净化的探究；常见气体的检验与除杂方法；盐的化学性质专题：物质的别离、除杂、提纯与共存问题分析：根据原物质和杂质的性质选择适当的除杂剂和别离方法，所谓除杂提纯，是指除去杂质，同时被提纯物质不得改变除杂质题至少要满足两个条件：加入的试剂只能与杂质反应，不能与原物质反应；反应后不能引入新的杂质解答：解：A、除去二氧化碳中的一氧化碳不能够通氧气点燃，这是因为当除去气体中的气体杂质不能使用气体，否则会引入新的气体杂质氧气，故选项所采取的方法错误B、CaO 能与水反应生成氢氧化钙，碳酸钙难溶于水，反而

33、会把原物质除去，不符合除杂原则，故选项所采取的方法错误文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4

34、V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D

35、3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R

36、5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1

37、B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V

38、1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E1

39、0R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3C、MgSO4 溶液能与适量BaCl2 溶液反应生成硫酸钡沉淀和氯化镁，能除去杂质但引入了新的杂质氯化镁，不符合除杂原则，故选项所采取的方法错误D、足量铁粉能与CuCl2溶液反应生成氯化亚铁溶液和铜，再过滤除去

40、不溶物，能除去杂质且没有引入新的杂质，符合除杂原则，故选项所采取的方法正确故选：D 点评：物质的别离与除杂是中考的重点，也是难点，解决除杂问题时，抓住除杂质的必需条件加入的试剂只与杂质反应，反应后不能引入新的杂质是正确解题的关键 8 3 分 2014?达州某城市有甲、乙两工厂排放污水，污水中各含有以下6 种离子中的3 种两厂不含相同离子：H+、Ba2+、Na+、OH、CO32、NO3 两厂单独排放都会造成严重的水污染，假设将两厂的污水按一定比例混合，便会变成无色澄清只含硝酸钠的溶液关于污染源的分析，你认为正确的选项是 A CO32 和 NO3 来自同一工厂B OH 和 NO3 一定不在同一工厂

41、 C H+和 Ba2+一定不在同一工厂 D Na+和 NO3 来自同一工厂考点：离子或物质的共存问题专题：物质的别离、除杂、提纯与共存问题分析：根据钡离子和碳酸根离子会生成沉淀，氢离子和氢氧根离子能结合成水，氢离子与碳酸根离子能结合成水和二氧化碳，所有的钠、硝酸根离子形成的化合物都易溶于水，溶液中必须存在阴阳离子进行分析解答：解：因为氢氧根离子不能与氢离子共存，则假设氢离子在甲厂污水中，则氢氧根离子应该在乙厂；氢离子不能喝碳酸根离子共存，则碳酸根离子应该在乙厂；碳酸根离子不能与钡离子共存，则钡离子存在于甲厂污水中，溶液中必须同时存在阴阳离子，故甲厂污水中含有硝酸根离子；乙厂污水中含有钠离子；即

42、H+Ba2+、NO3 应该在一个厂；OH、CO32、Na+应该在一个厂，因此：A、CO32 和 NO3 一定不在同一工厂，故错误；B、OH和 NO3 一定不在同一工厂，故选项正确；C、H+和 Ba2+一定在同一工厂，故选项错误；文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J

43、2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9

44、D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW

45、7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF

46、2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6

47、E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:

48、CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3D、Na+和 NO3 一定不在同一工

49、厂，故选项错误；故选项为：B 点评：此题考查了离子共存的问题，在解此类题时，首先分析选项中离子的性质，只要会生成沉淀、气体、水中的一种，就不能共存烷，并检验甲烷燃烧后的气体产物1小王用无水醋酸钠化学式为CH3COONa 和碱石灰固体混合加热制取甲烷，发生装置应选择上图中的 A 填字母，并写出无水醋酸钠与碱石灰中的氢氧化钠反应生成甲烷和碳酸钠的化学方程式 CH3COONa+NaOH CH4+Na2CO3 2小李用一定溶质质量分数的过氧化氢溶液和二氧化锰固体制取并收集一瓶干燥的氧气，请从上面选择装置图，正确的组装顺序为 CFD 填字母3下面是小张对甲烷在氧气中燃烧后的气体产物进行验证的实验假定每步

50、均完全反应 温馨提示：无水硫酸铜吸水后变蓝，常用于吸收水和验证水的存在；丁装置中酒精灯的网罩起集中火焰升高温度的作用请答复：如果将甲、乙装置顺序进行交换，则不能验证燃烧产物中的 H2O；完成实验报告实验操作 实验现象实验结论 来源:Zxxk.Com 将燃烧后的气体产物进行验证甲中的白色固体变蓝燃烧产物中有H2O 乙装置质量增加 燃烧产物中有CO2 丁中玻璃管内固体颜色变化是红色变成黑色、戊中澄清石灰水变浑浊 燃烧产物中有CO 写出丁中玻璃管内反应的化学方程式 Fe2O3+3CO2Fe+3CO2 文档编码:CW7E10R5F9V7 HF2J2V1B4V4 ZK6E9D7V1D3文档编码:CW7E