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2016-2017学年高二数学上册同步练习题10.pdf

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1、章末综合检测(一)(时间：120分钟，满分：150分)一、选择题(本大题共 12 小题，每小题5 分，共 60 分在每小题给出的四个选项中，只有一项是符合题目要求的)1函数 ytan x2是()A最小正周期为4的奇函数B最小正周期为 2的奇函数C最小正周期为 4的偶函数D最小正周期为2的偶函数解析：选 B该函数为奇函数，其最小正周期 T122.2简谐运动 y4sin 5x3的相位与初相是()A5x3，3B5x3，4 C5x3，3D4，3解析：选 C.相位是 5x3，当 x0 时的相位为初相即3.3设 a0，角的终边与单位圆的交点为P(3a，4a)，那么sin 2cos 的值等于()A.25B

2、25C.15D15解析：选 A.因为点 P 在单位圆上，则|OP|1.即（3a）2（4a）21，解得 a15.因为 a0，所以 a15.所以 P 点的坐标为35，45.所以 sin 45，cos 35.所以 sin 2cos 4523525.4设为第二象限角，则sin cos 1sin21()A1 Btan2Ctan2D1 解析：选 D.sin cos 1sin21sin cos cos2sin2sin cos cos sin.因为为第二象限角，所以 cos 0，sin 0.所以原式sin cos cos sin sin cos cos sin 1.5已知函数 f(x)sin x2(xR)

3、，下列结论错误的是()A函数 f(x)的最小正周期为 2B函数 f(x)在区间 0，2上是增函数C函数 f(x)的图象关于直线x0 对称D函数 f(x)为奇函数文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:

4、CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码

5、:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编

6、码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档

7、编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文

8、档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9

9、文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E

10、9文档编码:CZ10Z3E6T6E10 HR6X3S10P9Q9 ZO7I2U1W6E9解析：选 D.因为 f(x)sin x2cos x，所以 T2，故 A 选项正确；因为 ycos x 在 0，2上是减函数，所以 ycos x 在 0，2上是增函数，故 B 选项正确；因为f(0)sin 21，所以 f(x)的图象关于直线 x0 对称，故 C 选项正确；f(x)cos x 是偶函数，故 D 选项错误6sin 600 tan 240 的值等于()A32B32C123 D.123 解析：选 Bsin 600 sin(360 240)sin 240 sin(180 60)sin 60 32，tan

11、 240 tan(180 60)tan 60 3，因此 sin 600 tan 240 32.7已知为锐角，且 2tan()3cos250，tan()6sin()1，则 sin 的值是()A.3 55B3 77C.3 1010D.13解析：选 C.由已知可得 2tan 3sin 50，tan 6sin 文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3

12、A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8

13、T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K

14、10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3

15、A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8

16、T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K

17、10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3

18、A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T101，解得 tan 3，故 sin 3 1010.8设 g(x)的图象是由函数f(x)cos 2x 的图象向左平移3个单位得到的，则 g6等于()A1 B12C0 D1 解析：

19、选 D.由 f(x)cos 2x 的图象向左平移3个单位得到的是 g(x)cos 2 x3的图象，则 g6cos 263cos 1.故选 D.9设 0，函数 ysin x32 的图象向右平移43个单位后与原图象重合，则的最小值是()A.23B43C.32D3 解析：选 C.法一：函数 ysin x32 的图象向右平移43个单位后得到函数ysin x4332sin x43 32 的图象因为两图象重合，所以 x3 x43 32k，k Z，解得 32k，k Z.又 0，所以的最小值是32.文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7

20、I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

21、X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M

22、9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7

23、I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

24、X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M

25、9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7

26、I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

27、X8T10法二：由题意可知，43是函数 ysin x32(0)的最小正周期 T 的正整数倍，即43kT2k(kN*)，所以 32k，所以的最小值为32.10如果函数 y3cos(2x)的图象关于点43，0 中心对称，那么|的最小值为()A.6B4C.3D.2解析：选 A.由 y3cos(2x)的图象关于点43，0 中心对称，知 f430，即 3cos830，所以83 k 2(kZ)，所以 k 283(kZ)，|的最小值为6.11如果函数 f(x)sin(x)(0 2)的最小正周期为T，且当 x2 时，取得最大值，那么()AT2，2BT1，CT2，DT1，2解析：选 A.因为 T22，f(x)

28、sin(x)，文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J

29、7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6

30、K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10

31、V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J

32、7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6

33、K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10

34、V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J

35、7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10所以 f(2)sin(2 )sin 1，又 0 2，则 2.故选 A.12已知函数ysin(2x)0 2图象的一条对称轴在区间6，3内，则满足此条件的一个值为()A.12B6C.3D.4解析：选 A.令 2x k 2(kZ)，解得 xk242(kZ)，因为函数 ysin(2x)0 2图象的一条对称轴在区间6，3内，所以令6k2423(kZ)，解得 k 6 k 6(kZ)，四个选项中只有A 符合，故选 A.二、填空题(本大题共 4 小题，每小题 5 分，共 20

36、分把答案填在题中横线上)13已知 cos(45 )513，则 cos(135)_解析：cos(135)cos180(45 )cos(45 )513.答案：513文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

37、X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M

38、9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7

39、I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

40、X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M

41、9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7

42、I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1

43、X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T1014函数 f(x)2sinx26，当 f(x)取最大值时，x 的取值集合为_解析：由x262k 2，k Z，得 x4k 43，k Z.答案：x|x4k 43，kZ15若 f(x)2sin x(0 1)在区间 0，3上的最大值为2，则 _解析：因为 0 1，x0，3，所以 x 0，30，2，所以 f(x)max2sin

44、32，所以 sin 322，所以 34，34.答案：3416有下列说法：函数 ycos 2x 的最小正周期是；终边在 y 轴上的角的集合是|k2，kZ；把函数 y3sin 2x3的图象向右平移6个单位长度得到函数y文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A

45、4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T

46、10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K1

47、0B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A

48、4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T

49、10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K1

50、0B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A4H10 HR10J7M9K10B3 ZN5Y10V1X8T10文档编码:CV6K7I3A

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