2016-2017学年安徽省合肥市七年级(下)期末数学试卷.pdf

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1、第1页共 20页2016-2017 学年安徽省合肥市七年级下期末数学试卷一、选择题每题3 分，共 24 分1 3 分以下方程是一元一次方程的是A B3x2y=6 CDx2+2x=02 3 分以下四组数中，是方程4xy=10的解的是ABCD3 3 分如果 xy，则以下变形中正确的选项是Axy ByC3x5y Dx3y34 3 分解方程时，为了去分母应将方程两边同时乘以A12 B10 C 9 D45 3 分已知等腰三角形的两边的长分别为3和 6，则它的周长为A9 B12 C 15 D12 或 156 3 分以下标志中，可以看作是轴对称图形的是ABC D7 3 分如图，EADF，AE=DF，要使 A

2、EC DFB，只要AAB=CD BEC=BF CA=D DAB=BC8 3 分如图，在 ABC中，BC边上的高是第2页共 20页ACE BAD C CF DAB二、填空题每题3 分，共 18 分9 3 分已知方程 2a5=x+a 的解是 x=6，那么 a=10 3 分一个数 x 的 2 倍减去 7 的差，得 36，列方程为11 3 分装修大世界出售以下形状的地砖：1正三角形；2正五边形；3正六边形；4正八边形；5正十边形，假设只选购一种地砖镶嵌地面，你有种选择12 3 分如图，在ABC中，ACB=120 ，将它绕着点 C旋转 30 后得到 DEC，则ACE=13 3 分如下图，请将 A、1、2

3、 按从大到小的顺序排列14 3 分如图，在 RtABC中，D，E为斜边 AB上的两个点，且 BD=BC，AE=AC，则DCE的大小为度 三、解答题每题18 分，共 24 分15 18 分解以下方程或方程组：1x4=322x1=3x+43 x3=325x文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3

4、A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7

5、N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3

6、A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7

7、N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3

8、A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7

9、N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第3页共 20页45616 6 分解以下不等式或等式组：1103x+512四、解答题共54分17 5 分解不

10、等式：并在数轴上表示出它的解集18 5 分如果一个多边形的内角和是它的外角和的6 倍，那么这个多边形是几边形19 6分学校准备用 2000 元购买名著和词典作为艺术节奖品，其中名著每套65 元，词典每本 40 元，现已购买名著20 套，问最多还能买词典多少本？20 6 分如图，AC=AE，C=E，1=2求证：ABC ADE 21 7 分一批货物要运往某地，货主准备租用汽车运输公司的甲、乙两种货车，已知过去租用这两种货车情况如下：第一次第二次甲种货车数量2 辆5 辆乙种货车数量3 辆6 辆累计运货重量14 吨32 吨1分别求甲、乙两种货车载重多少吨？文档编码:CD4Y5A4H3A1 HR3J5Q

11、2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编

12、码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q

13、2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编

14、码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q

15、2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编

16、码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q

17、2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第4页共 20页2现在租用该公司5 辆甲货车和 7 辆乙货车一次刚好运完这批货物，如果按每吨付费 50 元计算，货主应付运费多少元？22 7 分如图，它是一个 810 的网格，每个小正方形的边长均为1，每个小正方形的顶点叫格点，ABC的顶点均在格点上1画出 ABC关于直线 OM 对称的 A1B1C12画出 ABC关于点 O 的中心对称图形 A2B2C23 A1B1C1与A2B2C2组成的图形是轴对称图形

18、吗？如果是，请画出对称轴A1B1C1与A2B2C2组成的图形填“是”或“不是”轴对称图形23 8 分如图，已知点 B、E、F、C依次在同一条直线上，AFBC，DE BC，垂足分别为 F、E，且 AB=DC，BE=CF 试说明 ABDC 24 10 分如图，已知 ABC中，AB=AC=12cm，BC=9cm，点 D为 AB的中点1如果点 P在线段 BC上以 3cm/s 的速度由点 B 向点 C运动，同时点 Q在线段 CA上由点 C向点 A 运动文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

19、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

20、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

21、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

22、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

23、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

24、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

25、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第5页共 20页假设点 P的运动速度与点 Q 的运动速度相等，1 秒钟时，BPD与CQP是否全等，请说明理由？假设点 Q 的运动速度与点 P的运动速度不相等，当点 Q 的运动速度为多少时，能够使 BPD与CQP全等？2假设点 Q 以1中的运动速度从点C出发，点 P 以原来的运动速度从点 B同时出发，都逆时针沿 ABC的三边运动，直接写出经过多长时间点P与点Q第一次相遇文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1

26、L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4

27、H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1

28、L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4

29、H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1

30、L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4

31、H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1

32、L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第6页共 20页2016-2017 学年安徽省合肥市七年级下期末数学试卷参考答案与试题解析一、选择题每题3 分，共 24 分1 3 分以下方程是一元一次方程的是A B3x2y=6 CDx2+2x=0【分析】依据分式方程、二元一次方程、一元一次方程、一元二次方程的定义解答即可【解答】解：A、2x+5=是分式方程，故 A 错误；B、3x2y=6是二元一次方程，故B错误；C、=5x 是一元一次方程，故C正确；D、x2+2x=0是一元二次方程，故D错误故选：C【点评】此题主要考查的是分式方程、二元一次方程、

33、一元一次方程、一元二次方程的定义，熟练掌握相关定义是解题的关键2 3 分以下四组数中，是方程4xy=10的解的是ABCD【分析】将各选项代入即可得结果【解答】解：将 A 选项代入得 40 10=10，所以此选项正确；将 B选项代入得 43.54=18，所以此选项错误；将 C选项代入得 4154=56，所以此选项错误；将 D 选项代入得 416=2，所以此选项错误，故选：A【点评】此题主要考查了二元一次方程的解，利用代入法是解答此题的关键3 3 分如果 xy，则以下变形中正确的选项是文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

34、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

35、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

36、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

37、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

38、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C

39、9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1

40、HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第7页共 20页Axy ByC3x5y Dx3y3【分析】根据不等式的性质：不等式两边加或减同一个数或式子，不等号的方向不变；不等式两边乘或除以同一个正数，不等号的方向不变不等式两边乘或除以同一个负数，不等号的方向改变【解答】解：A、两边都乘以，故 A 错误；B、两边都乘以，故 B 错误；C、左边乘 3，右边乘 5，故 C错误；D、两边都减 3，故 D正确；故选：D【点评】主要考查了不等式的基本性质，“0”是很特殊的一个数，因此，解答不等式的问题时，应密切关注“0”存在

41、与否，以防掉进“0”的陷阱不等式的基本性质：不等式两边加或减同一个数或式子，不等号的方向不变；不等式两边乘或除以同一个正数，不等号的方向不变不等式两边乘或除以同一个负数，不等号的方向改变4 3 分解方程时，为了去分母应将方程两边同时乘以A12 B10 C 9 D4【分析】找出各分母的最小公倍数，即可得到结果【解答】解：解方程1=时，为了去分母应将方程两边同时乘以12，故选：A【点评】此题考查了解一元一次方程，熟练掌握运算法则是解此题的关键5 3 分已知等腰三角形的两边的长分别为3和 6，则它的周长为A9 B12 C 15 D12 或 15【分析】分两种情况：当 3 为底时和 3 为腰时，再根据

42、三角形的三边关系定理：两边之和大于第三边去掉一种情况即可【解答】解：当 3 为底时，三角形的三边长为3，6，6，则周长为 15；当 3 为腰时，三角形的三边长为3，3，6，则不能组成三角形；文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:

43、CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H

44、2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:

45、CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H

46、2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:

47、CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H

48、2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7第8页共 20页故选：C【点评】此题考查了等腰三角形的性质以及三角形的三边关系定理，是基础知识要熟练掌握注意分类讨论思想的应用6 3 分以下标志中，可以看作是轴对称图形的

49、是ABC D【分析】根据轴对称图形的概念，可得答案【解答】解：A、是中心对称图形，故A错误；B、是中心对称图形，故B正确；C、是轴对称图形，故C正确；D、是中心对称图形，故D 错误；故选：C【点评】此题考查了轴对称图形，轴对称图形的关键是寻找对称轴，图形两部分折叠后可重合7 3 分如图，EADF，AE=DF，要使 AEC DFB，只要AAB=CD BEC=BF CA=D DAB=BC【分析】四项分别一试即可，要判定AEC DFB，已知 AE=DF、A=D，要加线段相等，只能是AC=DB，而 AB=CD即可得【解答】解：AB=CDAC=DB又 AE=DF、A=DAEC DFB文档编码:CD4Y5

50、A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 ZN1L7N9C9X7文档编码:CD4Y5A4H3A1 HR3J5Q2H2O9 Z