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2017年浙江中考数学真题分类汇编--三角形(解析版).pdf

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1、2017年浙江中考真题分类汇编数学三角形一、单项选择题共4 题；共 8 分1、2017金华以下各组数中，不可能成为一个三角形三边长的是 )A、2，3，4 B、5，7，7 C、5，6，12 D、6，8，10 2、2017台州如图，已知ABC，AB=AC，假设以点B 为圆心，BC长为半径画弧，交腰AC于点 E，则以下结论一定正确的选项是A、AE=EC B、AE=BE C、EBC=BAC D、EBC=ABE 3、2017?杭州如图，在ABC中，点 D，E分别在边AB，AC 上，DE/BC，假设 BD=2AD，则A、B、C、D、4、2017?杭州如图，在ABC中，AB=AC，BC=12，E为 AC边的

2、中点，线段BE的垂直平分线交边BC于点 D设 BD=x，tanACB=y，则A、xy2=3 B、2xy2=9 C、3xy2=15 D、4x y2=21 二、填空题共4 题；共 5 分5、2017衢州如图，正ABO的边长为2，O 为坐标原点，A 在轴上，B 在第二象限。ABO 沿轴正方向作无滑动的翻滚，经第一次翻滚后得A1B1O，则翻滚3 次后点 B的对应点的坐标是_；翻滚 2017 次后 AB中点 M 经过的路径长为_.6、2017?绍兴如图，AOB=45 ，点 M，N 在边 OA上，OM=x，ON=x+4，点 P是边 OB 上的点.假设使点 P，M，N 构成等腰三角形的点P恰好有三个，则x

3、的值是 _.7、一副含和角的三角板和叠合在一起，边与重合，如图 1，点为边的中点，边与相交于点现将三角板绕点按顺时针方向旋转如图 2，在从到的变化过程中，点相应移动的路径长为_结文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文

4、档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ

5、7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10

6、U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 H

7、E6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2

8、J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10

9、ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G

10、1O7R6果保留根号8、2017?杭州如图，在RtABC中，BAC=90，AB=15，AC=20，点 D 在边 AC上，AD=5，DE BC于点 E，连结 AE，则 ABE的面积等于 _三、解答题共5 题；共 53 分9、2017衢州问题背景如图 1，在正方形ABCD的内部，作DAE=ABF=BCG=CDH，根据三角形全等的条件，易得DAEABF BCG CDH，从而得到四边形EFGH是正方形。类比研究如图 2，在正 ABC的内部，作BAD=CBE=ACF，AD，BE，CF两两相交于D，E，F三点 D，E，F三点不重合。(1)ABD，BCE，CAF是否全等？如果是，请选择其中一对进行证明；(

11、2)DEF是否为正三角形？请说明理由；(3)进一步探究发现，ABD 的三边存在一定的等量关系，设，请探索，满足的等量关系。文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K1

12、0 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A

13、1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R

14、6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:

15、CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z

16、10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8

17、 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R610、2017?绍兴已知 ABC，AB=AC，

18、D 为直线 BC上一点，E为直线 AC上一点，AD=AE，设 BAD=，CDE=.(1)如图，假设点D 在线段 BC上，点 E在线段 AC上.如果 ABC=60 ，ADE=70 ，那么 =_ ，=_ .求，之间的关系式._(2)是否存在不同于以上中的，之间的关系式？假设存在，请求出这个关系式求出一个即可；假设不存在，说明理由.11、2017台州如图，已知等腰直角ABC，点 P是斜边 BC上一点不与B，C重合，PE是 ABP的外接圆 O 的直径(1)求证：APE是等腰直角三角形；(2)假设 O 的直径为2，求的值12、2017?杭州如图，在锐角三角形ABC中，点 D，E分别在边AC，AB 上，

19、AGBC于点 G，AFDE于点 F，EAF=GAC(1)求证：ADE ABC；(2)假设 AD=3，AB=5，求的值文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 Z

20、C8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1

21、O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档

22、编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7

23、O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U

24、1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE

25、6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R613、2017?温州如图，在五边形ABCDE中，BC

26、D=EDC=90 ，BC=ED，AC=AD(1)求证：ABC AED；(2)当 B=140 时，求 BAE的度数文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8

27、A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7

28、R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码

29、:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6

30、Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I

31、8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X

32、2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6答案解析部分一、单项选择题1、【答案】C【考点】三角形三

33、边关系【解析】【解答】解：A.2+34，故能组成三角形；B.5+77，故能组成三角形；C.5+612，故不能组成三角形；D.6+810，故能组成三角形；故答案为C。【分析】根据三角形的三边关系：三角形任意两边的和大于第三边，对各个选项进行逐一分析判断，即可得出答案。2、【答案】C【考点】三角形的外角性质，等腰三角形的性质【解析】【解答】解：AB=AC,ABC=C,又 BE=BC,BEC=C,ABC=BEC,又 BEC=A+ABE,ABC=ABE+EBC,A=EBC,故答案选C.【分析】根据AB=AC,BE=BC，可以得出ABC=C,BEC=C,从而得出 ABC=BEC,A=EBC,可得出正确答

34、案。3、【答案】B【考点】相似三角形的判定与性质【解析】【解答】解：DE/BC，ADE ABC，BD=2AD，=，则=，A，C，D 选项错误，B选项正确，故选：B【分析】根据题意得出ADE ABC，进而利用已知得出对应边的比值4、【答案】B【考点】线段垂直平分线的性质，等腰三角形的性质，勾股定理，锐角三角函数的定义文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I

35、8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X

36、2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K

37、10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8

38、A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7

39、R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码

40、:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6

41、Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6【解析】【解答】解：过 A 作 AQBC于 Q，过 E作 EMBC于 M，连接 DE，BE的垂直平分线交BC于 D，BD=x，BD=DE=x，AB=AC，BC=12，tanACB=y，=y，BQ=CQ=6，AQ=6y，AQBC，EMBC，AQEM，E为 AC中点，CM=QM=CQ=3，EM=3y，DM=123x=9x，在 RtEDM 中，由勾股定理得：x2=3y2+9x2，即 2xy2=9，故选 B【分析】过 A作 AQBC于 Q，过 E作 EMB

42、C于 M，连接 DE，根据线段垂直平分线求出DE=BD=x，根据等腰三角形求出BD=DC=6，求出 CM=DM=3，解直角三角形求出EM=3y，AQ=6y，在 RtDEM 中，根据勾股定理求出即可二、填空题5、【答案】5，；【考点】弧长的计算，图形的旋转【解析】【解答】解：1正 ABO 的边长为 2，第一次翻滚之后为OA1B1,第二次翻滚之后为B1O1A2,第三次翻滚之后为A2B2O2,作 BD x 轴，D 为 A2O2中点，OD=2+2+1=5，B2D=，B25，；文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X

43、2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K

44、10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8

45、A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7

46、R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码

47、:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6

48、Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I

49、8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R6文档编码:CQ7O6Z10U1I8 HE6X2D2J1K10 ZC8A1G1O7R62 M 为 AB 中点M 经过的路径是第一次翻滚是以O 为圆心，OM 长为半径，圆心角为120 的扇形;第二次翻滚是以B1为圆心，B1M1长为半径，圆心角为120 的扇形;第三次翻滚是以A2为圆心，A2M2长为半径，圆心角为120 的扇形;这样三个一循环的出现。2017 里面有 672 个 3

50、余 1，M 经过的路径为：672+=【分析】1 由题可得：第一次翻滚之后为OA1B1,第二次翻滚之后为B1O1A2,第三次翻滚之后为A2B2O2,作 BD x 轴，正 ABO的边长为2，从而得出B2坐标.2题可得：中点M 经过的路径是第一次翻滚是以O 为圆心，OM 长为半径，圆心角为120 的扇形;第二次翻滚是以B1为圆心，B1M1长为半径，圆心角为120 的扇形;第三次翻滚是以A2为圆心，A2M2长为半径，圆心角为 120 的扇形;这样三个一循环的出现。由于2017 里面有 672 个 3 余 1，M 经过的路径为：672+=6、【答案】x=0 或 x=或 4 x4【考点】相交两圆的性质【解

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关键词：: 2017 浙江中考数学分类汇编三角形解析

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本文标题：2017年浙江中考数学真题分类汇编--三角形(解析版).pdf
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