2018年广州市有关中考数学真题和详细解析.pdf
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1、2018年广州市有关中考数学真题和详细解析(纯word 版)2011 年广州市初中毕业生学业考试一、选择题(每小题3 分,共 30 分)1.四个数-5,21,3中为无理数的是()A.-5 B.C.21 D.32.已知ABCD 的周长为32,AB=4,则 BC=()A.4 B.121 C.24 D.283.某车间 5 名工人日加工零件数分别为6,10,4,5,4,则这组数据的中位数是()A.4 B.5 C.6 D.104.将点 A(2,1)向左平移2 个单位长度得到点A,则点A的坐标是()A.(0,1)B.(2,-1)C.(4,1)D.(2,3)5.下列函数中,当x0 时,y 值随 x 值增大而
2、减小的是()A.2xy B.1xy C.xy43 D.xy16.若 ac0b,则 abc 与 0 的大小关系是()A.abc0 D.无法确定7.下面的计算正确的是()A.2221243xxx B.1553xxx C.34xxx D.725)(xx8.如图所示,将矩形纸片先沿虚线AB 按箭头方向向右对折,接着对折后的纸片沿虚线CD向下对折,然后剪下一个小三角形,再将纸片打开,则打开后的展开图是()9.当实数 x 的取值使得2x有意义时,函数y=4x+1 中 y 的取值范围是()-7 B.y9 C.y9 D.y910.如图,AB切 O于点 B,OA=23,AB=3,弦 BC33 B.23 C.D.
3、23二、填空题:(每小题3 分,共 18 分)的相反数是 _(12.已知=260,则的补角是 _度。13.方程231xx的解是 _14.如图,以点O为位似中心,将五边形ABCDE 放大后得到五边形EDCBA,已知 OA=10cm,AO=20cm,则五边形ABCDE的周长与五边形EDCBA的周长的比值是_15.已知三条不同的直线a、b、c 在同一平面内,下列四条命题:如果 a 其中真命题的是_。(填写所有真命题的序号)16.定义新运算“”,baba431,则)1(12=_。三、解答题(本大题共9 大题,满分102 分)17.(9 分)解不等式组01231xx18.(9 分)如图,AC是菱形 AB
4、CD 的对角线,点E、F 分别在边AB、AD上,且 AE=AF。求证:ACE ACF19.(10 分)分解因式:8(x2-2y2)-x(7x+y)+xy20.(10 分)5 个棱长为1 的正方体组成如图的几何体。(1)该几何体的体积是_(立方单位)表面积是 _(平方单位)(2)画出该几何体的主视图和左视图。21.(12分)某商店 5月 1 日举行促销优惠活动,当天到该商店购买商品有两种方案,方案一:用 168 元购买会员卡成为会员后,凭会员卡购买商店内任何商品,一律按商品价格的8折优惠;方案二:若不购买会员卡,则购买商店内任何商品,一律按商品价格的折优惠。已知小敏 5 月 1 日前不是该商店的
5、会员。(1)若小敏不购买会员卡,所购买商品的价格为120 元时,实际应支付多少元(2)请帮小敏算一算,所购买商品的价格在什么范围时,采用方案一更合算ADFEBC正面文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 H
6、U2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3
7、W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 H
8、U2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3
9、W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 H
10、U2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3
11、W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W122.(12 分)某中学九年级(3)班 50 名学生参加平均每周上网时间的调查,由调查结果绘制了频数分布直方图,根据图中信息回答下列问题:(1)求 a的值;(2)用列举法求以下事件的概率:从上网时
12、间在610 小时的 5 名学生中随机选取2 人,其中至少有 1 人的上网时间在810 小时。23.(12 分)已知RtABC的斜边 AB在平面直角坐标系的x 轴上,点C(1,3)在反比例函数y=xk的图象上,且sin BAC=53。(1)求 k 的值和边AC的长;(2)求点 B的坐标。24.(14 分)已知关于x 的二次函数y=ax2+bx+c(a0)的图象经过点C(0,1),且与 x 轴交于不同的两点A、B,点 A的坐标是(1,0)(1)求 c 的值;(2)求 a的取值范围;(3)该二次函数的图象与直线y=1 交于 C、D两点,设A、B、C、D四点构成的四边形的对角线相交于点P,记 PCD的
13、面积为S1,PAB的面积为S2,当 0a1 时,求证:S1-S2为常数,并求出该常数。25.(14 分)如图 7,O中 AB是直径,C是 O上一点,ABC=450,等腰直角三角形DCE中 DCE是直角,点D在线段 AC上。(1)证明:B、C、E三点共线;文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R
14、3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A
15、5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R
16、3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A
17、5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R
18、3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A
19、5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1(2)若 M是线段 BE的中点,N是线段 AD的中点,证明:MN=2OM;(3)将 DCE绕点 C逆时针旋
20、转(00900)后,记为 D1CE1(图 8),若 M1是线段 BE1的中点,N1是线段 AD1的中点,M1N1=2OM1是否成立若是,请证明:若不是,说明理由。2011 年广州市中考数学试题答案一、选择题文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z
21、3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7
22、HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z
23、3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7
24、HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z
25、3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7 HU2G7I8B7X6 ZI4A5O6Z3W1文档编码:CR7G3I8R3M7
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