2015年上海中考长宁区初三数学二模试卷及答案.pdf
《2015年上海中考长宁区初三数学二模试卷及答案.pdf》由会员分享,可在线阅读,更多相关《2015年上海中考长宁区初三数学二模试卷及答案.pdf(8页珍藏版)》请在淘文阁 - 分享文档赚钱的网站上搜索。
1、初三数学共 4 页第1页ABCDEO第 6 题图2015 年初三数学教学质量检测试卷考试时间100 分钟,总分值150 分考生注意:1本试卷含三个大题,共25 题答题时,考生务必按答题要求在答题纸规定的位置上作答,在草稿纸、本试卷上答题一律无效2除第一、二大题外,其余各题如无特别说明,都必须在答题纸的相应位置上写出证明或计算的主要步骤一、单项选择题:本大题共6 题,每题4 分,总分值24 分1.将抛物线2xy向右平移 3个单位得到的抛物线表达式是()A.23xy;B.23xy;C.32xy;D.32xy.2.以下各式中,与3是同类二次根式的是()A.13;B.6;C.9;D.12.3.一组数据
2、:5,7,4,9,7的中位数和众数分别是()A.4,7;B.7,7;C.4,4;D.4,5.4.用换元法解方程:253322yyyy时,如果设32yyx,那么原方程可化为()A.02522xx;B.0152xx;C.02522xx;D.01522xx.5.在以下图形中,等边三角形,正方形,正五边形,正六边形.其中既是轴对称图形又是中心对称的图形有()A.1个;B.2个;C.3个;D.4个.6.如图,在四边形ABCD 中,ABC=90,对角线AC、BD 交于点 O,AO=CO,AOD=ADO,E 是 DC 边的中点.以下结论中,错误的选项是()A.ADOE21;B.OBOE21;C.;OCOE2
3、1;D.BCOE21.二、填空题:本大题共12 题,每题4 分,总分值48 分7.计算:219=初三数学共 4 页第2页中年?老年20%青年60%第 12 题图MFEDCBA第 18 题图8.计算:23nm=9.方程132x的解是 10.假设关于x 的二次方程032aaxx有两个相等的实数根,则实数a=11.从数字 1,2,3,4中,任意取两个数字组成一个两位数,这个数是素数的概率是 12.2015年1月份,某区体委组织“迎新春长跑活动”,现将报名的男选手分成:青年组、中年组、老年组.各组人数所占比例如下图,已知青年组 120人,则中年组的人数是 13.已知akb,如果2a,6b,那么实数k=
4、14.已知1O和2O的半径分别是 5和3,假设21OO=2,则两圆的位置关系是 15.已知在离地面 30米的高楼窗台A 处测得地面花坛中心标志物C 的俯角为60,那么这一标志物C 离此栋楼房的地面距离BC 为 米16.已知线段AB=10,P 是线段 AB 的黄金分割点(AP PB),则 AP=17.请阅读以下内容:我们在平面直角坐标系中画出抛物线12xy和双曲线xy2,如图所示,利用两图像的交点个数和位置来确定方程xx212有一个正实数根,这种方法称为利用函数图像判断方程根的情况.请用图像法判断方程xx2432的根的情况 填写根的个数及正负18.如图,ABC DEF 点 A、B 分别与点D、E
5、 对应,AB=AC=5,BC=6,ABC 固定不动,DEF 运动,并满足点E 在 BC 边从 B 向 C 移动点E 不与 B、C 重合,DE 始终经过点A,EF 与 AC边交于点M,当 AEM 是等腰三角形时,BE=.三、解答题:本大题共7 题,总分值78 分19 此题总分值10 分解不等式组325,5)5.1(2mmm,并将解集在数轴上表示出来.BCA第 15 题图xyO第 17 题图文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M
6、5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:
7、CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M
8、5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:
9、CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M
10、5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:
11、CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M
12、5D3 ZT6B2T4X8Q2初三数学共 4 页第3页20 此题总分值10 分先化简,再求代数式的值:aaaaa112122,其中13a.21 此题总分值10 分在一次运输任务中,一辆汽车将一批货物从甲地运往乙地,到达乙地卸货后返回甲地.设汽车从甲地出发xh时,汽车与甲地的距离为ykm,y 与 x 的关系如下图.根据图像答复以下问题:1汽车在乙地卸货停留h;2求汽车返回甲城时y 与 x 的函数解析式,并写出定义域;3求这辆汽车从甲地出发4 h 时与甲地的距离.22 此题总分值10 分如图,AD 是等腰 ABC 底边上的高,且AD=4,54sin B.假设 E 是 AC 边上的点,且满足 AE:
13、EC=2:3,联结 DE,求ADEcot的值.23 此题总分值12 分如图,正方形ABCD 中,点 E、F 分别在边BC、CD 上,AE=AF,AC 和 EF 交于点 O,延长 AC 至点 G,使得 AO=OG,联结 EG、FG.1求证:BE=DF;2求证:四边形 AEGF 是菱形.DFGCOEBA第 23 题图第 22 题图EDCBA第 21 题图xy(km)(h)521202.5O文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5
14、D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:C
15、M4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5
16、D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:C
17、M4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5
18、D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:C
19、M4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5
20、D3 ZT6B2T4X8Q2初三数学共 4 页第4页24 此题总分值12 分如图,已知抛物线2222ttxxy的顶点 A 在第四象限,过点A 作 ABy 轴于点 B,C 是线段 AB 上一点(不与 A、B 重合),过点 C 作 CDx 轴于点 D,并交抛物线于点P.1假设点C 的横坐标为1,且是线段AB 的中点,求点P 的坐标;2假设直线AP 交 y 轴负半轴于点E,且 AC=CP,求四边形OEPD 的面积 S关于 t 的函数解析式,并写出定义域;3在 2的条件下,当ADE 的面积等于2S时,求 t 的值.25 此题总分值14 分如图,已知矩形ABCD,AB=12 cm,AD=10 cm,O
21、与 AD、AB、BC 三边都相切,与DC交于点 E、F。已知点P、Q、R 分别从 D、A、B 三点同时出发,沿矩形ABCD 的边逆时针方向匀速运动,点P、Q、R 的运动速度分别是1 cm/s、x cm/s、cm/s,当点 Q 到达点 B 时停止运动,P、R 两点同时停止运动.设运动时间为t单位:s.1求证:DE=CF;2设 x=3,当 PAQ 与 QBR 相似时,求出t 的值;3设 PAQ 关于直线PQ 对称的图形是PAQ,当 t 和 x 分别为何值时,点A与圆心 O 恰好重合,求出符合条件的t、x 的值.第 24 题图xyOEPDCBA第 25 题图OFEDCBAPQR文档编码:CM4C1F
22、1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT
23、6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F
24、1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT
25、6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F1T7O8 HG4X7H1M5D3 ZT6B2T4X8Q2文档编码:CM4C1F
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 2015 上海 中考 长宁区 初三 数学 试卷 答案
限制150内