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2019年江苏省盐城市中考数学试卷(word解析版).pdf

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1、盐城市二 O一九年初中毕业与升学考试数学试卷本次考试时间为120 分，卷面总分150 分.一、选择题（本大题共有8 小題，每小题3 分，共 24 分，在每小题所给出的四个选项，只有一项符合题目要求的.1如图，数轴上点A表示的数是()A.-1B.0C.1D.2【答案】C【解析】考查对数轴的理解，A 点在 1 的位置，故选C 2下列图形中，既是轴对称图形又是中心对称图形的是()【答案】B【解析】考查对轴对称和中心对称的理解，故选B.3若2x有意义，则x 的取值范围是()Ax2Bx 2C x2D x 2【答案】A【解析】二次根式里面不能为负数，所以x-2d 0，解得 x2，故选 A.4如图，点D、E

2、分别是 ABC边 BA、BC的中点，AC 3，则 DE的长为()A2 B34 C3 D23【答案】D【解析】中位线的性质，DE=21AC，故选 D.第 1 页，共 18 页5如图是由6 个小正方体搭成的物体，该所示物体的主视图是()【答案】C【解析】考查对三视图的理解.所以主视图是，故选 C.6下列运算正确的是()【答案】B【解析】725aaa，故 A错；aaa32，故 C错；632)(aa，故 D 错。故选B 7正在建设中的北京大兴国际机场划建设面积约1400000 平方米的航站极，数据1400000 用科学记数法应表示为【答案】C【解析】1400000=1.4 106，故选 C.8关于 x

3、的一元二次方程022kxx（k 为实数）根的情况是A有两个不相等的实数根B有两个相等的实数根C没有实数根D不能确定【答案】A.【解析】方程022kxx根的判别式08)2(14)(22kk，所以有两个不相等的实数根。第 2 页，共 18 页文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K1

4、0U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2

5、HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S

6、10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6

7、 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6

8、R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9

9、文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:CT8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9文档编码:C

10、T8Y7K10U1N2 HB5M2S10R8R6 ZN2I6R4C8A9二、填空题（本大题共有8 小题，每小题3 分，共 24 分，不需写出解答过程，请将答案直接写在答题卡的相应位置上）9如图，直线ab，150，那么 2_.【答案】50【解析】根据“两直线平行，同位角相等”得1=2=5010分解因式：12x_.【答案】（x+1）(x-1)【解析】由平方差公式可得：)1)(1(11222xxxx.11如图，转盘中6 个扇形的面积都相等任意转动转盘1 次，当转盘停止转动时，指针落在阴影部分的概率为_.【答案】21。【解析】因为6 个扇形的面积都相等，阴影部分的有3 个扇形，所以指针落在阴影部分的概

11、率是21.12甲、乙两人在100 米短跑训练中，某5 次的平均成绩相等，甲的方差是0.142s，乙的方差是0.062s，这 5 次短跑训练成绩较稳定的是_（填“甲”或“乙”）【答案】乙【解析】方差越小越稳定，故乙的训练成绩比较稳定.13设21xx、是方程0232xx的两个根，则_2121xxxx.【答案】1【解析】根据韦达定理可知：212,3132121xxxx，所以12-32121xxxx.14如图，点A、B、C、D、E在 O上，且弧AB为 50，则 E C _【答案】155【解析】如图，因为弧AB 为 50，则弧AB 所对的圆周角为25，E+C=180-25=155.第 3 页，共 18

12、页文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:

13、CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P

14、10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5

15、 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7

16、P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W1

17、0 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I

18、3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J215如图，在ABC中，BC 26，C45，AB 2AC，则 AC的长为 _.【答案】2【解析】过A 作 AD BC于 D点，设 AC=x2，则 AB=x2，因为 C=

19、45，所以AD=AC=x，则由勾股定理得 BD=xADAB322，因为 AB=26，所以 AB=263xx,则 x=2.则 AC=2.16如图，在平面直角坐标系中，一次函数y2x1 的图像分别交x、y 轴于点 A、B，将直线 AB绕点 B按顺时针方向旋转45，交 x 轴于点 C，则直线BC的函数表达式是_.【答案】131xy【解析】因为一次函数y2x1 的图像分别交x、y 轴于点 A、B，则 A（21，0），B（0,-1），则 AB=25.过 A作 AD BC于点 D，因为 ABC=45，所以由勾股定理得AD=410，设 BC=x，则 AC=OC-OA=2112x，根据等面积可得：AC OB=

20、BC AD，即2112x=410 x，解得 x=10.则 AC=3，即 C（3，0），所以直线 BC的函数表达式是131xy.三、解答题（本大题共有11 小题，共 102 分，请在答鹽卡指定区域内作答，解答时应写出文字说明、推理过程或演算步骤）17（本题满分6 分）计算：45tan4)2136(sin20第 4 页，共 18 页文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T

21、1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7

22、L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1

23、G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8

24、W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM

25、8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M

26、9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编

27、码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J218（本题满分6 分）解不等式组：xxx21322119（本题满分8 分）如图，一次函数yx1 的图像交y 轴于点 A，与反比例函数)0(xxky的图像交于点B(m,2).（1）求反比例函数的表达式：（2）求 AOB的面积.20（本题满分8 分）在一个不透明的布袋中，有2 个红球，1 个白球，这些球除颜色外都相同（1）搅匀后从中任意摸出1 个球，摸到红球的概率是_；（2）搅匀后先从中任意摸出1 个球（不放回），再从余下的球中任意摸出1

28、个球求两次都摸到红球的概率（用树状图或表格列出所有等可能出现的结果）第 5 页，共 18 页文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文

29、档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT

30、5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10

31、E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 H

32、P1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6

33、B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10

34、ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J221（本题满分8 分）如图，AD是 ABC的角平分线（1）作线段AD的垂直

35、平分线EF，分别交AB、AC于点 E、F；（用直尺和圆规作图，标明字母，保留作图痕迹，不写作法.）（2）连接 DE、DF，四边形AEDF是_形.（直接写出答案）22.(本题满分10 分)体育器材室有A、B两种型号的实心球，1 只 A型球与 1 只 B型球的质量共7 千克，3 只 A型球与 1 只 B型球的质量共13 千克.(1)每只 A型球、B型球的质量分别是多少千克?(2)现有 A型球、B型球的质量共17 千克，则A型球、B型球各有多少只?第 6 页，共 18 页文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7

36、P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W1

37、0 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I

38、3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J

39、2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:

40、CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P

41、10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5

42、 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J223，(本题满分10 分)某公司其有400 名销售人员，为了解该公司销售人员某季度商品销售情况，随机抽取部分销售人员该季度的销售数量，并把所得数据整理后绘制成如下统计图表进行分析.请根据以上信息，解决下列问题：(1)频数分布表中，a_、b_：(2)补全频数分布直方图；(3)如果该季度销量不低于80

43、件的销售人员将被评为“优秀员工”，试估计该季度被评为“优秀员工”的人数.24.(本题满分10 分)如图，在Rt ABC中，ACB 90，CD是斜边 AB上的中线，以CD为直径的 O分别交 AC、BC于点 M、N，过点 N作 NE AB，垂足为E(1)若 O的半径为25，AC 6，求 BN的长；(2)求证：NE与 O相切.第 7 页，共 18 页文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2

44、文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:C

45、T5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P1

46、0E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5

47、HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P

48、6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10

49、 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3

50、F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J2文档编码:CT5T1P10E7L5 HP1G7P6B8W10 ZM8I3F7M9J225（本题满分10 分）如图是一张矩形纸片，按以下步骤进行操作：（）将矩形纸片沿DF折叠，使点A落在 CD边上点 E处，如图；（）在第一次折叠的基础上，过点C再次折叠，使得点B落在边 CD上点 B处，如图，两次折痕交于点O；（）展开纸片，分别连接OB、OE、OC、FD，如图【探究】（1）证明：OBC OED：（2）若 AB 8，设 BC为 x，OB为 y，求 y 关于 x 的关系式.第 8 页，共 18 页文档编码:

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