2015江苏中考数学试题分类汇编:反比例函数(纯word).pdf
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1、1.2015 江苏淮安3 分 假设点 P 1,2 在反比例函数xky的图像上,则k。【答案】2【分析】点 P 1,2在反比例函数xky的图像上,122k【考点】反比例函数【点评】对于填空题和选择题,可以直接利用kxy来求解。2 2015 江苏苏州3 分 假设点Aa,b在反比例函数2yx的图像上,则代数式ab-4的值为A0 B-2 C 2 D-6【答案】B【分析】点 Aa,b在反比例函数2yx的图像上,2ab,4242ab故选 B。【考点】反比例函数3 2015 江苏无锡2 分 假设点 A3,4、B 2,m在同一个反比例函数的图象上,则 m 的值为A6 B6C12 D12【答案】A【分析】点 A
2、3,4、B 2,m在同一个反比例函数的图象上,342 mk,6m故选 A【考点】反比例函数【点评】对于填空题和选择题,可以直接利用kxy来求解。4.2015 江苏宿迁3 分 在平面直角坐标系中,点A、B 的坐标分别为3,0、3,0,点 P 在反比例函数xy2的图像上,假设PAB 为直角三角形,则满足条件的点P 的个数为A、2 个B、4 个C、5 个D、6 个【答案】D【分析】PAB 为直角时,有一个点;作图法:过A 作 APx轴;PBA 为直角时,有一个点;作图法:过B 作 APx轴;APB 为直角时,有四个点;作图法:以AB 为直径画圆,与抛物线有四个交点。以 AB 为直径的圆的方程为229
3、xy,与反比例函数xy2联立,得2292xyyx,即2229xx,42940 xx,29652x,有 4 个解,19652x,29652x,39652x,49652x有 4 个交点。【考点】反比例函数图像;直角三角形;圆【点评】碰到直角时画圆是常规做法,一定要熟练应用。5 2015 江苏连云港3 分如图,O 是坐标原点,菱形OABC的顶点 A 的坐标为3,4,顶点 C 在x轴的负半轴上,函数(0)kyxx的图象经过顶点B,则 k 的值为A12B27C32D36【答案】C【分析】A 的坐标为3,4,OA=2234=5,OABC 为菱形,AB=OA=5,B 点坐标为8,4,8432k。【考点】反比
4、例函数;菱形的性质6.2015 江苏扬州3 分 已知一个正比例函数的图像与一个反比例函数的图像的一个交点坐标为 1,3,则另一个交点坐标是【答案】1,3【分析】解法一:正比例函数与反比例函数都关于原点对称,文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C
5、7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H
6、7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H
7、4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:
8、CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6
9、P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V
10、7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C
11、8Y8Y5C7 ZT4H7U8E5H4一个交点坐标为1,3,另一个交点关于原点对称,点1,3关于原点的对称点为1,3。解法二:设正比例函数为yax,反比例函数为kyx,两个函数的交点为1,3,3a,1 33k,正比例函数为3yx,反比例函数为3yx,联立两个函数,得33yxyx,即33xx,1x,当1x时,3y,另一个交点为1,3。【考点】反比例函数;正比例函数;函数图象7.2015 江苏泰州3 分 点1,1 ya、2,1 ya在反比例函数0kxky的图像上,假设21yy,则a的范围是【答案】11a【分析】反比例函数0kxky,函数递减21yy,假设两个点都在同一象限,则11aa,无解;假设两
12、个点在不同象限,则1010aa,解得11a。【考点】反比例函数;图像;分类讨论8 2015 江苏南京2 分 如图,过原点O 的直线与反比例函数y1、y2的图像在第一象限内分别交于点A、B,且 A 为 OB 的中点假设函数11yx,则 y2与 x的函数表达式是文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编
13、码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10
14、Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F
15、6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU
16、5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y
17、5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT
18、4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E
19、5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4【答案】24yx【分析】设 A 点坐标为a,1a,A 为 OB 中点,B 点坐标为2a,22a,设2kyx,将 B 点代入,得22kaa,解得,4k,y2与 x 的函数表达式是24yx。【考点】反比例函数;平面直角坐标系【点评】对于填空题和选择题,可以直接利用kxy来求k。9 2015 江苏苏州8 分 如图,已知函数kyx x0的图像经过点A、B,点 B 的坐标为 2,2 过点 A 作 ACx 轴,垂足为C,过点 B 作 BD y 轴,垂足为D,AC 与 BD交于点 F一次函数y=ax+b 的图像经过点A
20、、D,与 x 轴的负半轴交于点E1假设 AC=32OD,求 a、b 的值;2假设 BCAE,求 BC 的长文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U
21、8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文
22、档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF
23、10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P1
24、0F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7
25、HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y8Y5C7 ZT4H7U8E5H4文档编码:CF10Q6P10F6V7 HU5C8Y
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