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2021年2021年2019-2020学年安徽省芜湖市第一中学高一上学期期中数学试题(含答案解析).pdf

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1、2019-2020 学年安徽省芜湖市第一中学高一上学期期中数学试题一、单选题1设全集0,1,2,3,4,5U,集合1,2A,0,2,3B,则UABI e()A4,5B2,3C1D2【答案】C【解析】根据集合的交集定义和补集定义,即可求得答案.【详解】Q0,1,2,3,4,5U,0,2,3B1,4,5UBe1,21,4,51UABe故选:C.【点睛】本题考查了集合交集运算和补集运算,解题关键是掌握交集定义和补集定义,考查了分析能力,属于基础题.2下列四组函数,表示同一函数的是()A3()2f xx与()2g xxxB2(),()xfxx g xxC2(),()ln2lnf xg xxxD33()

2、log(0,1),()xaf xa aag xx【答案】D【解析】根据两个函数的定义域相同,对应关系也相同,逐项验证即可判断它们是否为同一个函数.【详解】对于 A,3()2f xx与()2g xxx对应关系不同,故二者不是同一个函数,故 A 错误;对于 B,()fxx的定义域为R,而2()xg xx的定义域为(,0)(0,)U,二者定义域不同,所以二者不是同一个函数,故 B 错误;对于C,2()lnfxx定义域为(,0)(0,)U,()2lng xx定义域为(0,),二者定义域不相同,所以二者不是同一个函数,故C错误;对于 D,()logxafxxa,33()g xxx,二者的定义域和对应法则

3、都相同,所以二者是同一个函数,故 D 正确.故选:D.【点睛】本题考查判断两个函数是否为同一函数,注意要从二个方面来分析:定义域、对应法则,只有二要素完全相同,才能判断两个函数是同一个函数,这是判定两个函数为同一函数的标准.3已知5.10.9m，0.90.95.1,log5.1np，则这三个数的大小关系是()Amnp B mpn Cpmn Dpnm【答案】C【解析】利用指数函数与对数函数的性质即可比较大小.【详解】设函数 f（x）=0.9x，g（x）=5.1x，h（x）=log0.9x 则 f（x）单调递减，g（x）单调递增，h（x）单调递减 0f（5.1）=0.95.10.90=1，即0m1

4、 g（0.9）=5.10.95.10=1，即 n1 h（5.1）=log0.95.1log0.91=0，即 p0 pmn 故选：C【点睛】本题考查对数值比较大小，可先从范围上比较大小，当从范围上不能比较大小时，可借助函数的单调性数形结合比较大小属基础题4函数 f(x)lnx的零点所在的大致区间是()A(1,2)B(2,3)C(1，)和(3,4)D(e，)【答案】B【解析】试题分析：由于,所以选 B【考点】函数的零点文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N

5、1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O

6、6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8

7、J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK

8、4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR

9、5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9

10、K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:

11、CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D45已知二次函数2fxaxbxc,且函数3yfx为偶函数,则在函数值1f、2f、5f、7f中最大的一个不可能是()A1fB2fC5fD7f【答案】C【解析】根据函数3yfx为偶函数,它的图像关于y轴对称,而函数fx的图像可由函数3fx的图像向右平移三个单位得到,二次函数fx关于3x轴对称,对抛物线的开口方向进行分类讨论结合单调性,即可求得答案.【详解】Q函数3yfx为偶函数,它的图像关于y轴对称,而函数fx的图像可由函数3fx的图像向右平移三个

12、单位得到二次函数fx关于3x轴对称当0a时,此时fx是以3x轴对称,开口向下二次函数由二次函数图像可知:在函数值1257ffff、中,最大的一个是2f;当0a时,此时fx是以3x轴对称,开口向上二次函数由二次函数图像可知:在函数值1257ffff、中,最大的是(1)f或(7)f;综上所述,5f不可能成为最大值.故选:C.【点睛】本题考查了比较二次函数值的大小,解题关键是掌握偶函数性质和二次函数图像特征,考查了分析能力,属于中档题.6已知fx的定义域为2 2,，则函数(1)()21f xg xx,则()g x的定义域为（）A1(,32B(1,)C1(,0)(0,3)2D1(,3)2【答案】A

13、文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K

14、10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O

15、6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3

16、D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E

17、3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z

18、9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5

19、A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4【解析】212210 xx，则132x，即定义域为1,32，故选 A。7若2()2f xxax与1()(1)xg xa(1a且0)a在区间1,2上都是减函数,则a的取值范围是()A(1,0)B(0,1C（0，1）D(1,0)(0,1)【答案】B【解析】【详解】因为

20、2()2f xxax与1()(1)xg xa(1a且0)a在区间1,2上都是减函数，所以111aa，解得01a.故选：B.8定义在R上的函数fx满足()()()2,(,)f xyf xf yxy x yR,12f,则3f()A2B1C 0D6【答案】D【解析】根据()()()2,(,)f xyf xf yxy x yR,12f,依次求出(0)f,(1)f,(2)f,即可求得答案.【详解】Q()()()2,(,)f xyf xf yxy x yR(1)(01)(0)(1)20 1(0)(1)ffffff即(0)(1)(1)fff故(0)0f又Q(0)(1 1)(1)(1)2(1)1(1)(1)2

21、ffffff即(0)(1)(1)2fff,故0(1)22f(1)0f又Q(1)(21)(2)(1)2(2)1(2)(1)4ffffff文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X

22、9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4

23、文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K

24、10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O

25、6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3

26、D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E

27、3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4即(1)(2)(1)4fff,故0(2)24f(2)2f又Q(2)(3 1)(3)(1)2(3)1(3)(1)6ffffff即(2

28、)(3)(1)6fff,2(3)26f(3)6f故选:D.【点睛】本题考查了根据函数关系式求解函数值,解题关键是灵活利用所给关系式,利用赋值法,进行求解,考查了分析能力和计算能力,属于中档题.9关于函数21()lg(0,)|xf xxxRx下列命题错误的是()A函数yfx的图像关于y轴对称B在区间,0上，函数yfx是减函数C函数yfx的最小值为lg 2D在区间1,上，函数yfx是增函数.【答案】B【解析】因为21()lg(0,)|xf xxxRx,证明函数()f x 的奇偶性和单调性,即可求得答案.【详解】奇偶性证明:Q21()lg(0,)|xf xxxRx,2211()lglg()|xxfx

29、f xxx()f x 为偶函数单调性证明:Q21()lg(0,)|xf xxxRx文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K

30、10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O

31、6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3

32、D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E

33、3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z

34、9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5

35、A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4当0 x时,211()lglgxf xxxx根据对数函数单调性可知:lgyx单调增函数,令1yxx当0 x时,根据对号函数图像可知:当1x时,1yxx是单调递增;当01x时,1yxx

36、是单调递减.根据复合函数单调性同增异减可知:当1x时,1()lgf xxx是单调递增当01x时,1()lgf xxx是单调递减.当1x时,1()lgf xxx取得最小值,即(1)lg2f.偶函数图像关于y轴对称可知:当1x时,1()lgf xxx是单调递减当10 x时,1()lgfxxx是单调递增.综上所述,对于 A,函数yfx的图像关于y轴对称,故 A 正确;对于 B,当1x时,1()lgf xxx是单调递减当10 x时,1()lgfxxx是单调递增.故 B 错误;对于 C,函数yfx的最小值为lg 2,故 C 正确;对于 D,在区间1,上,函数yfx是增函数,故 D 正确.故选:B.【点睛

37、】本题考查了判断函数奇偶性和单调性,及其求函数的最值,解题关键是掌握函数奇偶性的判断方法和偶函数图像性质,考查了分析能力和计算能力,属于中档题.文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6

38、Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J

39、5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4

40、N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5

41、O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K

42、8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:C

43、K4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D410已知函数()log(21)(01)xaf xbaa，的图象如图所示，则ab，满足的关系是（）A101abB101ba

44、C101baD1101ab【答案】A【解析】本小题主要考查正确利用对数函数的图象来比较大小由图易得1a，101a；取特殊点01log0axyb，11logloglog 10aaaba，101ab选 A11已知2,522,g xfxg xfxxg xxxF xfxg xfx若，若，则 F（x）的最值是（）A最大值为3，最小值B最大值为，无最小值C最大值为3，无最小值D既无最大值，又无最小值【答案】C【解析】【详解】试题分析：由fxg x得2522xxx，若0 x时，2522xxx等价为2522xxx，即25x，解得5x（舍去负根）若0 x时，2522xxx等价为2522xxx，即，解得1x或5x

45、（舍去）即当1x时，52F xfxx，当15x时，22F xg xxx，当5x时，52F xfxx，作出函数图象，如下图文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8

46、J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK

47、4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR

48、5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9

49、K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:

50、CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6 HR5O6Z9O6X9 ZH9K8J5A3D4文档编码:CK4N1E3K10J6

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关键词：: 2021 2019 2020 学年安徽省芜湖市第一中学高一上学期期中数学试题答案解析

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