2021年第3部分命题区间3.pdf

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1、第三部分突破高考计算题的4 个命题区间命题区间三电磁场中的计算题课时跟踪检测(二十一)电磁场中的计算题1.如图所示，一个带正电的粒子以平行于x 轴正方向的初速度v0从 y 轴上 a点射入第一象限内，为了使这个粒子能经过x 轴上定点 b，可在第一象限的某区域内加一方向沿 y 轴负方向的匀强电场已知所加电场的场强大小为E，电场区域沿 x 方向的宽度为s，OaL，Ob2s，粒子的质量为m，带电量为 q，重力不计，试讨论电场的左边界与b 的可能距离解析：设电场左边界到 b 点的距离为 x，已知电场宽度为 s，Ob2s，分以下两种情况讨论：若粒子在离开电场前已到达b 点，如图甲所示，即 xs，则 xv0

2、tyLqE2mt2联立解得 x2mv20LqE.若粒子离开电场后做匀速直线运动到达b 点，如图乙所示，即s x2s，精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 1 页，共 8 页则 sv0t，yqE2mt2 由几何关系知 tan qEmtv0Ly xs联立解得 xmv20LqEss2.答案：见解析2(2019 全国卷)如图，在直角三角形 OPN 区域内存在匀强磁场，磁感应强度大小为 B、方向垂直于纸面向外 一带正电的粒子从静止开始经电压U 加速后，沿平行于 x 轴的方向射入磁场；一段时间后，该粒子在OP 边上某点以垂直于 x 轴的方向射出已知O 点为坐标原点，N 点在 y

3、 轴上，OP 与 x 轴的夹角为30，粒子进入磁场的入射点与离开磁场的出射点之间的距离为d，不计重力求：(1)带电粒子的比荷；(2)带电粒子从射入磁场到运动至x 轴的时间解析：(1)设带电粒子的质量为m，电荷量为 q，加速后的速度大小为v.由动能定理有 qU12mv2精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 2 页，共 8 页文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文

4、档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8

5、Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10

6、L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V

7、3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9

8、S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G

9、10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J

10、7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3设粒子在磁场中做匀速圆周运动的半径为r，运动轨迹如图所示由洛伦兹力公式和牛顿第二定律有qvBmv2r由几何关系知 d2r联立式得qm4UB2d2.(2)由几何关系知，带电粒子射入磁场后运动到x 轴所经过的路程为 s r2rtan 30 带电粒子从射入磁场到运动至x 轴的时间为 tsv联立式得tBd24U233.答案：(1)4UB2d2(2)Bd24U2333(2019 陕西省汉中市高三模拟)如图所示，在 xOy 平面直角坐标系中，直角三角形 ACD 内存在垂直纸面向里、磁感应强度大小为 B 的匀强磁场线段

11、COODl，30.在第四象限正方形ODEF 内存在沿 x 轴正方向、大小 EB2el3m的匀强电场，在第三象限沿AC 放置一平面足够大的荧光屏，屏与y 轴平行一个电子 P 从坐标原点 O 沿 y 轴正方向射入磁场，恰好不从AD 边射出磁场已知电子的质量为 m，电量为 e，不计电子的重力精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 3 页，共 8 页文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1

12、F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:

13、CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 H

14、J9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 Z

15、L1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编

16、码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9

17、 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9

18、 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3(1)求电子 P 射入磁场时的速度大小；(2)求电子 P 经过 y 轴时的 y 坐标；(3)若另一电子 Q 从 x坐标轴上某点(x0)以相同的速度仍沿y轴正方向射入磁场，且 P、Q 打在荧光屏上同一点，求电子Q 在电场中运动的时间解析：电子恰好不从 AD 边射出磁场得出半径，电子运动轨迹与AD 边相切，如图所示，设半径为r.(1)由几何关系可得rrsin l粒子在磁场中做匀速圆周运动，洛伦兹力提供向心力：ev0Bmv20r，解得 rl3，v0eBl3m.(2)假设电子从 OE 边离开，则电

19、子做类平抛运动中，有2r12at21，yPv0t1，eEma解得 t12meB，yP23l由于 yP23l0)A 从 O 点发射时的速度大小为v0，到达 P 点所用时间为 t；B 从 O 点到达 P 点所用时间为t2.重力加速度为 g，求：(1)电场强度的大小；(2)B 运动到 P 点时的动能解析：(1)设电场强度的大小为E，小球 B 运动的加速度为a.根据牛顿第二定律、运动学公式和题给条件，有mgqEma12at2212gt2解得 E3mgq.(2)设 B 从 O 点发射时的速度为v1，到达 P 点时的动能为 Ek，O、P 两点的高度差为 h，根据动能定理有Ek12mv21mghqEh且有

20、v1t2v0th12gt2联立式得精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 5 页，共 8 页文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V

21、2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3

22、X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G

23、1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F

24、1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:C

25、X3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ

26、9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3Ek2m(v20g2t2)答案：(1)3mgq(2)2m(v20g2t2)5(2019 广东省潮州市高三调研)如图甲所示，A、B 两板竖直放置，两

27、板之间的电压 U1100 V，M、N 两板水平放置，两板之间的距离d0.1 m，板长 L0.2 m一个质量 m21012 kg、电荷量 q1108 C 的带电粒子(不计重力)从靠近 A 板处由静止释放，经加速电场加速后从B 板的小孔穿出，沿着M、N 两板的中轴线垂直进入偏转电场，如果在 M、N 两板之间加上如图乙所示的偏转电压，当 tT4时，带电粒子刚开始进入偏转电场，则：(1)带电粒子从 B 板的小孔穿出时的速度为多大？(2)要使带电粒子能够从M、N 两板之间(不沿中轴线)穿出，并且穿出后的速度方向保持水平，则交流电U2的周期 T 为多少？(3)在满足(2)条件的情况下，它在偏转电场中的最大

28、偏移量是多少？(结果保留一位有效数字)解析：(1)由动能定理得 qU112mv20，解得 v02qU1m1103m/s.(2)要使带电粒子能够从M、N 两板之间穿出，并且穿出后速度方向不变，则带电粒子穿过偏转电场的时间t n12T(n0,1,2，)带电粒子沿水平方向做匀速直线运动，则Lv0t所以 T41042n1s(n0,1,2，)精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 6 页，共 8 页文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X

29、1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1

30、G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1

31、V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX

32、3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9

33、G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1

34、F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:

35、CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3带电粒子进入偏转电场时的加速度aqEm偏转电场强度 EU2d带电粒子在进入偏转电场后的前T4内沿竖直方向的位移y12aT42要使带电粒子能够从M、N 两板之间穿出，需满足2yd2联立式解得n4.5 所以 T41042n1s(n5,6,7，)(3)要使总偏移量最大，则n 应取值最小，故n5，由此解得，最大偏移量y2y0.04 m.答案：(1)1103 m/s(2)41042n1s(n5,6,7，)(3)0.04 m 6.(2017 全国卷)如图

36、，两水平面(虚线)之间的距离为 H，其间的区域存在方向水平向右的匀强电场自该区域上方的A 点将质量均为 m、电荷量分别为 q和q(q0)的带电小球 M、N 先后以相同的初速度沿平行于电场的方向射出小球在重力作用下进入电场区域，并从该区域的下边界离开，已知N 离开电场时的速度方向竖直向下；M 在电场中做直线运动，刚离开电场时的动能为N 刚离开电场时动能的 1.5 倍不计空气阻力，重力加速度大小为g.求：(1)M 与 N 在电场中沿水平方向的位移之比；(2)A 点距电场上边界的高度；(3)该电场的电场强度大小精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 7 页，共 8 页文档编

37、码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9

38、 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9

39、 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文

40、档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8

41、Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10

42、L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V

43、3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3解析：(1)设小球 M、N 在 A 点水平射出时的初速度大小为v0，则它们进入电场时的水平速度仍然为v0.M、N 在电场中运动的时间t 相等，电场力作用下产生的加速度沿水平方向，大小均为 a，在电场中沿水平方向的位移分别为s1和 s2.由题给条件和运动学公式得v0at0

44、s1v0t12at2s2v0t12at2联立式得s1s231.(2)设 A 点距电场上边界的高度为h，小球下落 h 时在竖直方向的分速度为vy，由运动学公式得v2y2ghHvyt12gt2M 进入电场后做直线运动，由几何关系知v0vys1H联立式可得h13H.(3)设电场强度的大小为E，小球 M 进入电场后做直线运动，则v0vyqEmg设 M、N 离开电场时的动能分别为Ek1、Ek2，由动能定理得Ek112m(v20v2y)mgHqEs1Ek212m(v20v2y)mgHqEs2?由已知条件 Ek11.5Ek2?联立?式得 Emg2q.答案：(1)31(2)13H(3)mg2q精品w o r

45、d 学习资料 可编辑资料-精心整理-欢迎下载-第 8 页，共 8 页文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9

46、G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1

47、F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:

48、CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 H

49、J9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 Z

50、L1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编码:CX3X1T9S8Y9 HJ9G1G4G10L9 ZL1F1V2J7V3文档编