2021年初中常用数学模型.pdf
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1、.word.zl.【1】中点+平行模型如图,如果ABDE,且 C 为 AE 中点,那么有ABC EDC 很好证的,当然十 分实用,经常 需要添加辅助线例如延长【例 题1】2021 某 模 拟【例题2】2021 答案:1.32;2.D【2】一线三等角模型如图,假设 B=C=DEF=0 90)那么一定有 BDE 与 CEF相 似。十 分 好 证 外 角 和 什 么 一 大 堆 ,并 且 也 很 实 用。经 常 在 矩 形 里 出 题。|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 11 页.word.zl.【例题1】2021【例题2】20
2、06【例题 3】原创答案:1.2或3-24或252.(5453-,)【3】巧造旋转模型在某些几何题中,往往有一些奇怪的结论,此时可以通过几何三大变换之 一【旋 转】求 解。巧 造 旋 转 往 往 要 有 一 定 的 等 量 关 系 和 特 殊 角 度,如 下 题:|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 11 页文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 Z
3、G8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6
4、K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 Z
5、G8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6
6、K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 Z
7、G8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6
8、K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 Z
9、G8N5O2K4R6.word.zl.通 过 观 察 可 得 ABC=C=45,AB=AC。我们可以将ACD 绕 A 顺时针旋转90得到 ABE,使得 AC与 AB 重合。那么就有EBBC,而在RT AED 中,DE2=2AD2等腰直角三角形所以BE2+BD2=DE2,即 BD2+CD2=2AD2是不是赶脚很难想到?要学会判断,这种感觉是要练出来的!【例题1】2021【例题 2】【例题 3】2021 改编|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 11 页文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4
10、R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 H
11、O3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4
12、R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 H
13、O3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4
14、R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 H
15、O3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4
16、R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6.word.zl.答案:1.412.9 3.(1.)2,(2.)直角三角形,旋转后证全等,证明略【4】等腰模型这是一个很根底的模型什么样的构造会生成等腰三角形首先:平行+角平分线,如图,假设 AD BE,BC 平分 ABE,那么 AB=AC,很好证的,导角即可。其次:垂直+角平分这个不难理解,因为等腰三角形三线合一。这种模型很常用,常常需要做辅助线延长之类【例题1】原创|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*
17、|*|欢.|迎.|下.|载.第 4 页,共 11 页文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5
18、O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5
19、C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5
20、O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5
21、C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5
22、O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5
23、C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6.word.zl.ABCD【例题2】原创【例题3】改编1.11 2.3 3.延长 CD 交 AB 于 M,利用中位线,证明略【5】倍长中线法常考,选填大证明都可能会用。是的!又是中点,中点用的很多啊=这个模型怎么用?先要判断。做题的时候看见中点,先找有没有可以直接用的,没有就找就没有平行+中点,再没有就要想
24、了没事摆个中点在这里有啥用?这时试试倍长中线。记住一 句 话:“倍 长 中 线,定 得 全 等 先 来 举 一 个 例 子,吧 里 很 经 典 的 一 题。_解:延长 AD,使DE=AD,连接 CE做这种题不变的辅助线说明AD=DE,BD=CD,ADB=CDE ADB EDC CE=AB=3 4-3AE4+3故 1/2AD7/2这样就迎刃而解了,还有好多好多题,需要用到这个【例题1】改编|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 5 页,共 11 页文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT
25、1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G7 ZG8N5O2K4R6文档编码:CT1I6K6P5C8 HO3A2N5X4G
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