大学物理第二版习题答案罗益民北邮出版社第二章答案.pdf
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1、优秀学习资料欢迎下载第二章质点动力学2-1(1)对木箱,由牛顿第二定律,在木箱将要被推动的情况下如图所示,x 向:0cosmaxminfFy 向:0sinminMgFN还有Nfsmax解以上三式可得要推动木箱所需力F 的最小值为sincosssminMgF在木箱做匀速运动情况下,如上类似分析可得所需力F 的大小为sincoskkminMgF(2)在上面minF的表示式中,如果0sincoss,则minF,这意味着用任何有限大小的力都不可能推动木箱,不能推动木箱的条件是0sincoss由此得的最小值为s1arctan2-2(1)对小球,由牛顿第二定律x 向:maNTsincosy 向:0coss
2、inmgNT联立解此二式,可得N)(32.3)30sin8.930cos2(5.0)sincos(gamTN)(74.3)30sin230cos8.9(5.0)sincos(agmN由牛顿第三定律,小球对斜面的压力N)(74.3NN(2)小球刚要脱离斜面时N=0,则上面牛顿第二定律方程为mgTmaTsin,cos习题 2-1 图习题 2-2 图-第 1 页,共 16 页精品p d f 资料 可编辑资料-优秀学习资料欢迎下载由此二式可解得2m/s0.1730tan/8.9tan/ga2-3 要使物体A 与小车间无相对滑动,三物体必有同一加速度a,且挂吊 B 的绳应向后倾斜。作此时的隔离体受力图如
3、图所示三物体只有水平方向的运动,只须列出水平方向的牛顿方程及相关方程:)4(:)3(0cos)2(sin:)1(:322211MaNFMgmTamTmamTm水平水平3N为绳中的雨拉力在水平向的合力)5(sin3TTN水平联立(1),(2),(3),(4),(5)解得)N(78480)(2221212gmmgmmmmF(因为三个物体有同一加速度a,且在水平方向只受外力F 的作同,所以,可将三个物体看作一个物体:aMmmF)(21再与(1),(2),(3)式联立求解即可。)2-4 由图写出力函数用积分法求解。)75(355)50(2ttttF(1)由tvmFdd得tFmvd1d(2)在s50内2
4、001d21tmttmvvtt(3)当 t=5 时:)sm(3025105mvv习题 2-3 图-第 2 页,共 16 页精品p d f 资料 可编辑资料-文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1
5、C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档
6、编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1
7、C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档
8、编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1
9、C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档
10、编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8优秀学习资料欢迎下载在 5-7s 内再用(2)式5.1123525d)355(1255ttttmvvtt(4)当 t=7 时:)sm(4010157vv再用积分法:tvxtxvdd,dd(5)在 0-5s
11、 内,由(3)式积分ttmvxxd)1(502005即)m(326831252505xx再由(4)式5.112352525tttvv求 5 得752557d)5.1123525(tttvxx得)m(142317357xx2-5 设两物体未用绳连接则由牛顿第二定律,沿x 方向,对A,有AAAAammggmcossink对于 B,有BBBBammggmcossink由此得2kAm/s63.3)30cos15.030(sin8.9)cos(singaA2kBm/s12.3)30cos21.030(sin8.9)cos(singaB(1)如图所示,A 在下,B在上。由于BAaa。所以绳被拉紧,二者一起
12、下滑,而aaaBA。以TT和分别表示绳对A 和 B的拉力)(TT,则由牛顿第二定律,沿 x 方向对 A:amTmggmAAAcossink对 B:amTmggmBBBcossink习题 2-5 图-第 3 页,共 16 页精品p d f 资料 可编辑资料-文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9
13、I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2
14、K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9
15、I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2
16、K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9
17、I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2
18、K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8优秀学习资料欢迎下载由此得)m/s(29.330cos8.985.25.185.221.05.115.0
19、30sin8.9cossin2kkgmmmmagaBABBAA(2)图中绳中张力为N)(51.029.35.130cos8.95.115.030sin8.95.1cossinkamgmgmTAAAA(3)如果互换位置,A 在上,B 在下,则由于BAaa,连接绳子将松弛,因而T=0,此时 AB 的加速度即)m/s(12.3),m/s(63.322BBAAaaaa2-6 当漏斗转速较小时,m 有下滑趋势,小物体受最大静摩擦力mf方向向上,如图所示。对小物体,由牛顿第二定律x 向:rmfNmmin2cossiny 向:0sincosmgfNm还有Nfms联立解以上各式,可得rg)sin(cos)co
20、s(sinssmin或rg)sin(cos)cos(sin21ssmin当 n 足够大时,小物体将有上滑趋势,它将受到向下的静摩擦力,即mf的方向与图2.6 中所示的方向相反。与上类似分析可得最大转速为rgn)sin(cos)cos(sin21ssmax总起来讲,小物体在漏斗壁上不动,转速n 应满足的条件是minmaxnnn2-7 设圆柱与绳索间的摩擦力为f,绳对重物m1的拉力 T1,m1和 m2对地加速度分别为a1、a2,对 m1、m2列出方程习题 2-6 图-第 4 页,共 16 页精品p d f 资料 可编辑资料-文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H
21、7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3
22、HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H
23、7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3
24、HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H
25、7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3 HF4M1C8M1X6 ZX2K9P8H7E8文档编码:CT4X4W9I9L3
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