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各地市高考数学联考试题分类大汇编排列组合二项式定理概率.pdf

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1、江苏省各地市20XX年高考数学最新联考试题分类大汇编第 11 部分:排列组合二项式定理、概率一、填空题：7(20XX 年 3 月苏、锡、常、镇四市高三数学教学情况调查一)某所学校有小学部、初中部和高中部，在校小学生、初中生和高中生人数之比为5：2：3，且已知初中生有800人，现采用分层抽样的方法从这所学校抽取一个容量为80的学生样本以了解学生对学校文体活动方面的评价，则每个高中生被抽到的概率是；7150【解析】由题知2108014000,800400050 xPx.5.(江苏省苏州市20XX年 1 月高三调研)已知集合2,5A,在A中可重复的依次取出三个数,a b c，则“以,a b c为边恰

2、好构成三角形”的概率是.5.58【解析】“在A中可重复的依次取出三个数,a b c”的基本事件总数为328，事件“以,a b c为边不能构成三角形”分别为2,2,5,2,5,2,5,2,2,所以351.88P5.(江苏省南京市20XX届高三第一次模拟考试)在集合2,3A中随机取一个元素m，在集合1,2,3B中随机取一个元素n，得到点(,)P m n，则点 P在圆229xy内部的概率为.513【解析】由题意得到的,P m n有：2,1,2,2,2,3,3,1,3,2,3,3，共计 6 个，在圆229xy的内部的点有2,1,2,2，所以概率为21638(江苏省徐州市20XX 届高三

3、第一次调研考试)在区间 5,5内随机地取出一个数a，使得221|20 xxaxa的概率为 80.3【解析】由221|20 xxaxa，得220aa12a，所以所求概率为3108.(江苏省苏北四市20XX届高三第一次调研)一个质地均匀的正四面体（侧棱长与底面边长相等的正三棱锥）玩具的四个面上分别标有1，2，3，4 这四个数字.若连续两次抛掷这个玩具，则两次向下的面上的数字之积为偶数的概率是.8【解析】应用例举法共有16 种等可能情况，（1，1）（1，2），（1，3）（1，4），（2，1）（2，2），（2，3），（2，4），（3，1）（3，2），（3，3）（3，4

4、），（4，1），（4，2），（4，3），（4，4）。两次向下的面上的数字之积为偶数共有12 种情况，所以所求概率为346.(江苏省泰州市20XX届高三年级第一次模拟)设Rxxxxf322，则在区间,上随机取一个数x，使0 xf的概率为。6.2【解答】几何概型，242230,13,1,32xxxxP。3.(江苏省南京市20XX年 3 月高三第二次模拟考试)用两种不同的颜色给图中三个矩形随机涂色，每个矩形只涂一种颜色，则相邻两个矩形涂不同颜色的概率是。14（第 3 题）6(江苏省泰州中学20XX年 3 月高三调研）某学校有两个食堂，甲、乙、丙三名学生各自随机选择其中的一个食堂用餐，则他们在同一个食

5、堂用餐的概率为144(江苏省南京外国语学校20XX 年 3 月高三调研)如图所示，墙上挂有一边长为a的正方形木板，它的四个角的空白部分都是以正方形的顶点为圆心，半径为2a的圆弧，某人向此板投镖，假设每次都能击中木板，且击中木板上每个点的可能性都一样，则他击中阴影部分的概率是_ _419(江苏省南京外国语学校20XX年 3 月高三调研)将一枚骰子抛掷两次，若先后出现的点数分别为cb,，则方程02cbxx有实根的概率为19366(江苏省宿豫中学20XX年 3 月高考第二次模拟考试)将一枚骰子抛掷两次，若先后出现的点数分别为cb,，则方程02cbxx有实根的概率为36195(江苏省盐城市20XX 届

6、高三年级第一次调研)从长度分别为2,3,4,5的四条线段中任意取出三条,则以这三条线段为边可以构成三角形的概率是.5.34【解析】从长度分别为2,3,4,5 的四条线段中任意取出三条这一事件共有344C种，而不能构成三角形的情形为2,3,5.所以这三条线段为边可以构成三角形的概率是3.4P二、解答题：23(20XX 年3 月苏、锡、常、镇四市高三数学教学情况调查一)（10 分）当*kN时，求证：文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 H

7、S10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 Z

8、D7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编

9、码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8

10、 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2

11、 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文

12、档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4

13、J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1(13)(13)kk是正整数；试证明大于2(13)n的最小整数能被12n整除（*nN）.23（1）2424(13)(13)2 133kkkkCC3的偶数次幂均为正整数，(13)(13)kk是正整数.因为20131n由（1）知22(13)(13)nn为正整数，所以大于2(13)n最小整数为22(13)(13)nn，22(13)(13)22323nnnnn由二项式定理可知2323nn是一偶数，所以大于2(13)n的最小整数能被12n整除（*nN）.22.(江苏省

14、苏州市20XX年 1 月高三调研)（本小题满分10 分）一个口袋装有5 个红球，3 个白球，这些球除颜色外完全相同，某人一次从中摸出3 个球，其中白球的个数为X.求摸出的三个球中既有红球又有白球的概率；求X的分布列及X的数学期望.22.【解析】（1）记“摸出的三球中既有红球又有白球”为事件A，依题意知122153533845.56C CC CP AC所以摸出的三个球中既有红球又有白球的概率为45.56（2）0312535333881150,1,5656C CC CP XP XCC21305353338830102,3,5656C CC CP XP XCC所以X的分布列为X0123P156155

15、630561056文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码

16、:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8

17、HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2

18、ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档

19、编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J

20、8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E

21、2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1所以X的数学期望1153010150123.565656568EX23.(江苏省苏北四市20XX届高三第一次调研)（本小题满分10 分）设二项展开式21*(31)()nnCnN的整数部分为nA，小数部分为nB.（1）计算2211,BCBC的值；（

22、2）求nnBC.23.(江苏省徐州市20XX 届高三第一次调研考试)（本小题满分10 分）甲、乙、丙三名射击运动员射中目标的概率分别为1,2a a(01)a，三人各射击一次，击中目标的次数记为.（1）求的分布列及数学期望；（2）在概率()Pi(i=0，1，2，3)中,若(1)P的值最大,求实数a的取值范围.23.【解析】本题主要考查数学知识的实际背景，重点考查相互独立事件的概率乘法公式计算事件的概率、文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8

23、 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2

24、 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文

25、档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4

26、J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3

27、E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A

28、1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3

29、J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1随机事件的数学特征，考查思维能力、运算能力、实践能力.（1）()P是“个人命中,3个人未命中”的概率.其中的可能取值为0，1，2，3.0022121122(0)C1C(1)(1)Paa,1020121212111222(1)CC(1)C1C(1)(1)Paaaa,1102221212111222(2)CC(1)C1C(2)Paaaaa,21221212(3)CC2aPa.所以的分布列为0123P212(1)a212(1)a212(2)aa22a的数学期望为

30、22221112222410(1)1(1)2(2)32aaEaaaa.5分（2）221(1)(0)1(1)(1)2PPaaaa,22112(1)(2)(1)(2)22aPPaaa,222112(1)(3)(1)22aPPaa.由2(1)0,120,21202aaaa和01a，得102a,即a的取值范围是10,2.10 分22(江苏省盐城市20XX 届高三年级第一次调研)（本小题满分10 分）设,m nN,()(12)(1)mnfxxx.（）当mn=2011 时,记220110122011()f xaa xa xax，求0122011aaaa；文档编码:CV3Y9D3J4J8 HS10F4W4F

31、3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7

32、A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D

33、3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W

34、4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9

35、T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y

36、9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F

37、4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1（）若()f x展开式中x的系数是20，则当m、n变化时，试求2x系数的最小值22.解：（）令1x，得0122011aaaa=20112011(12)(1 1)14 分（）因为112220mnCCmn，所以202nm,则2x的系数为2222mnCC2(1)(1)1422(202)(192)222m mn nmmmm

38、=2441190mm,所以当5,10mn时，()f x展开式中2x的系数最小，最小值为85 10 分23(江苏省盐城市20XX 届高三年级第一次调研)（本小题满分10 分）有一种闯三关游戏规则规定如下：用抛掷正四面体型骰子（各面上分别有1，2，3，4 点数的质地均匀的正四面体）决定是否过关，在闯第(1,2,3)n n关时，需要抛掷n次骰子，当n次骰子面朝下的点数之和大于2n时,则算闯此关成功,并且继续闯关，否则停止闯关.每次抛掷骰子相互独立.（）求仅闯过第一关的概率；（）记成功闯过的关数为，求的分布列和期望23.解：（）记“仅闯过第一关的概率”这一事件为A,则339()4 1664P A4分

39、（）由题意得,的取值有0,1,2,3,且1(0)4p,9(1)64p,(2)p3 13 564 16 64273512,(3)p3 1 384 1 66 439512,即随机变量的概率分布列为:0 1 2 3 p1496427351239512来8 分所以,19273397350123464512512512E10分文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 H

40、S10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 Z

41、D7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编

42、码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8

43、 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2

44、 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文

45、档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1文档编码:CV3Y9D3J4J8 HS10F4W4F3E2 ZD7A2W9T7A1

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