大一上期物理期末考试复习题.pdf

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1、优秀学习资料欢迎下载20XX 年上期物理期末考试复习题1-5质点沿x轴运动，其加速度和位置的关系为a 2+62x，a的单位为2sm，x的单位为 m.质点在x 0处，速度为 101sm,试求质点在任何坐标处的速度值解：xvvtxxvtvadddddddd分离变量：xxadxd)62(d2两边积分得cxxv322221由题知，0 x时，100v,50c13sm252xxv1-6已知一质点作直线运动，其加速度为a4+3t2sm，开始运动时，x5 mv=0，求该质点在t10s 时的速度和位置解：ttva34dd分离变量，得ttvd)34(d积分，得12234cttv由题知，0t,00v,01c故223

2、4ttv又因为2234ddtttxv分离变量，tttxd)234(d2积分得232212cttx由题知0t,50 x,52c故521232ttx所以s10t时-第 1 页，共 16 页精品p d f 资料 可编辑资料-优秀学习资料欢迎下载m70551021102sm190102310432101210 xv1-11飞轮半径为 0.4 m=0.2 rad2s，求t2s时边解：当s2t时，4.022.0t1srad则16.04.04.0Rv1sm064.0)4.0(4.022Ran2sm08.02.04.0Ra2sm22222sm102.0)08.0()064.0(aaan1-13 一船以速率1v

3、 30km h-1沿直线向东行驶，另一小艇在其前方以速率2v40km h-1沿直线向北行驶，问在船上看小艇的速度为何?在艇上看船的速度又为何?解：(1)大船看小艇，则有1221vvv，依题意作速度矢量图如题1-13 图(a)题 1-13 图由图可知1222121hkm50vvv方向北偏西87.3643arctanarctan21vv(2)小船看大船，则有2112vvv，依题意作出速度矢量图如题1-13 图(b)，同上法，得5012v1hkm方向南偏东o87.362-3质量为 16 kg 的质点在xOy平面内运动，受一恒力作用，力的分量为xf6 N，yf-7 N，当t0时，yx0，xv-2 m

4、s-1，yv 0求-第 2 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D

5、8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文

6、档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D

7、8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文

8、档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D

9、8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文

10、档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载当t2 s(1)位矢；(2)解：2sm83166mfaxx2sm167mfayy(1)20101200sm872167sm452832dtavvdtavvyyyxxx于是质点在s2时的速度1sm8745jiv(2)m874134)167(21)4832122(2

11、1)21(220jijijtaitatvryx2-9一质量为m的质点在xOyj tbi tarsincos求质点的动量及t0 到2t解:质点的动量为)cossin(j tbi tamvmp将0t和2t分别代入上式，得jbmp1,i amp2,则动量的增量亦即质点所受外力的冲量为)(12jbiampppI2-12设N67jiF合(1)当一质点从原点运动到m1643kjir时，求F所作的功(2)如果质点到r处时需 0.6s，试求平均功率(3)如果质点的质量为1kg，试求动能的变化-第 3 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 Z

12、T1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7

13、H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 Z

14、T1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7

15、H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 Z

16、T1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7

17、H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 Z

18、T1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载解:(1)由题知，合F为恒力，)1643()67(kjijirFA合J452421(2)w756.045tAP(3)由动能定理，J45AEk2-23物体质量为 3kg，t=0时位于m4ir,1sm6 jiv，如一恒力N5 jf作用在物体上,求 3秒后，(1)物体动量的变化；(2)相对z轴角动量的变化解:(1)301smkg15d5djtjtfp(2)解(一)73400tvxxxjattvyy5.2

19、5335213621220即ir41,jir5.257210 xxvv1133560atvvyy即jiv611,jiv112kjiivmrL72)6(34111kjijivmrL5.154)11(3)5.257(2221212smkg5.82kLLL解(二)dtdzMtttFrtML00d)(d301302smkg5.82d)4(5d5)35)216()4(2ktkttjjttit-第 4 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3

20、I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 H

21、H7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3

22、I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 H

23、H7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3

24、I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 H

25、H7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3

26、I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载题 2-24 图2-24 平板中央开一小孔，质量为m的小球用细线系住，细线穿过小孔后挂一质量为1M的重物小球作匀速圆周运动，当半径为0r时重物达到平衡 今在1M的下方再挂一质量为2M的物体，如题 2-24 图试问这时小球作匀速圆周运动的角速度和半径r为多少?解:在只挂重物时1M，小球作圆周运动的向心力为gM1，即2001mrgM挂上2M后，则有221)(rmgMM重力对圆心的力矩为零，故小球对圆心的角动量守恒即vmrmvr002020rr联立、得0211213212101010)(rMMMg

27、mMMrMMMmrgMmrgM2-27计算题 2-27 图所示系统中物体的加速度设滑轮为质量均匀分布的圆柱体，其质量为M，半径为r，在绳与轮缘的摩擦力作用下旋转，忽略桌面与物体间的摩擦，设1m50kg，2m 200 kg,M 15 kg,r 0.1 m 解:分别以1m,2m滑轮为研究对象，受力图如图(b)所示对1m,2m运用牛顿定律，有amTgm222-第 5 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M

28、1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F

29、4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M

30、1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F

31、4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M

32、1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F

33、4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M

34、1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载amT11对滑轮运用转动定律，有)21(212MrrTrT又，ra联立以上4 个方程，得2212sm6.721520058.92002Mmmgma题 2-27(a)图题 2-27(b)图题 2-28 图2-28如题 2-28 图所示，一匀质细杆质量为m，长为l，可绕过一端O的水平轴自由转动，杆于水平位置由静止开始摆下求：(1)初始时刻的角加速度；(2)杆转过角时的角速度.解:(1)由转动定律，有)31(212mlmglg23(2)由机械能守恒定律，有22)31(21sin2mllmglg sin3-第 6 页，共 16

35、页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档

36、编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8

37、Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档

38、编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8

39、Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档

40、编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8

41、Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载4-4 质量为kg10103的小球与轻弹簧组成的系统，按)SI()328cos(1.0 x的规律作谐振动，求：(1)振动的周期、振幅和初位相及速度与加速度的最大值；(2)最大的回复力、振动能量、平均动能和平均势能，在哪些位置上动能与势能相等?(3)s52t与s11t两个时刻的位相差；解：(1)设谐振动的

42、标准方程为)cos(0tAx，则知：3/2,s412,8,m1.00TA又8.0Avm1sm51.21sm2.632Aam2sm(2)N63.0mmaFJ1016.32122mmvEJ1058.1212EEEkp当pkEE时，有pEE2，即)21(212122kAkxm20222Ax(3)32)15(8)(12tt4-6一质量为kg10103的物体作谐振动，振幅为cm24，周期为s0.4，当0t时位移为cm24求：(1)s5.0t时，物体所在的位置及此时所受力的大小和方向；(2)由起始位置运动到cm12x处所需的最短时间；(3)在cm12x处物体的总能量解：由题已知s0.4,m10242TA1

43、srad5.02T又，0t时，0,00Ax故振动方程为m)5.0cos(10242tx-第 7 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N

44、2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX

45、4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N

46、2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX

47、4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N

48、2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX

49、4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z3I5优秀学习资料欢迎下载(1)将s5.0t代入得0.17mm)5.0cos(102425.0txN102.417.0)2(10103232xmmaF方向指向坐标原点，即沿x轴负向(2)由题知，0t时，00，tt时3,0

50、,20tvAx故且s322/3t(3)由于谐振动中能量守恒，故在任一位置处或任一时刻的系统的总能量均为J101.7)24.0()2(10102121214223222AmkAE4-8图为两个谐振动的tx曲线，试分别写出其谐振动方程题4-8图解：由题 4-8 图(a)，0t时，s2,cm10,23,0,0000TAvx又即1srad2T故m)23cos(1.0txa由题 4-8 图(b)0t时，35,0,2000vAx01t时，22,0,0111vx又253511-第 8 页，共 16 页精品p d f 资料 可编辑资料-文档编码:CX4C7H5M1U6 HH7D8Z6D1N2 ZT1F4T4Z