复旦大学电磁学期末考试试题解答.pdf
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1、复旦大学大学物理 A 电磁学2014.7.4 一、选择题。1.设源电荷与试探电荷分别为Q、q,则定义式qFE对Q、q的要求为:C ()二者必须是点电荷。()Q为任意电荷,q必须为正电荷。()Q为任意电荷,q是点电荷,且可正可负。()Q为任意电荷,q必须是单位正点电荷。2.一均匀带电球面,电荷面密度为,球面内电场强度处处为零,球面上面元dS的一个带电量为dS的电荷元,在球面内各点产生的电场强度:C ()处处为零。()不一定都为零。()处处不为零。()无法判定3.当一个带电体达到静电平衡时:D ()表面上电荷密度较大处电势较高。()表面曲率较大处电势较高。()导体内部的电势比导体表面的电势高。()
2、导体内任一点与其表面上任一点的电势差等于零。4.在相距为2R 的点电荷+q 与-q 的电场中,把点电荷+Q 从 O 点沿 OCD 移到 D 点(如图),则电场力所做的功和+Q 电位能的增量分别为:A ()RqQ06,RqQ06。()RqQ04,RqQ04。()RqQ04,RqQ04。()RqQ06,RqQ06。5.相距为1r的两个电子,在重力可忽略的情况下由静止开始运动到相距为2r,从相距1r到相距2r期间,两电子系统的下列哪一个量是不变的:C ()动能总和;()电势能总和;()动量总和;()电相互作用力6.均匀磁场的磁感应强度B垂直于半径为r的圆面。今以该圆周为边线,作一半球面s,则通过s面
3、的磁通量的大小为:B ()Br22。()Br2。()0。()无法确定的量。7.对位移电流,有下述四种说法,请指出哪一种说法正确:A ()位移电流是由变化电场产生的。()位移电流是由线性变化磁场产生的。()位移电流的热效应服从焦耳楞次定律。()位移电流的磁效应不服从安培环路定理。8在一个平面内,有两条垂直交叉但相互绝缘的导线,流过每条导线的电流相等,方向如图所示。问那个区域中有些点的磁感应强度可能为零:D A仅在象限1 B仅在象限2 C仅在象限1、3 D仅在象限2、4 9通有电流J 的无限长直导线弯成如图所示的3 种形状,则P、Q、O 各点磁感应强度的大小关系为:D APBQBOBBQBPBOB
4、CQBOBPBDOBQBPB文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S
5、10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9
6、S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J
7、9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2
8、J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D
9、2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2
10、D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M1010若空间存在两根无限长直载流导线,空间的磁
11、场分布就不具有简单的对称性,则该磁场分布:D A不能用安培环路定理来计算B可以直接用安培环路定理求出C只能用毕奥-萨伐尔定律求出D可以用安培环路定理和磁感应强度的叠加原理求出二、填空题1一磁场的磁感应强度为kcj bi aB,则通过一半径为R,开口向 Z 方向的半球壳,表面的磁通量大小为2R cWb 2.一电量为C9105的试验电荷放在电场中某点时,受到N91020向下的力,则该点的电场强度大小为4/NC,方向向上。3无限长直导线在P处弯成半径为R的圆,当通以电流I 时,则在圆心O点的磁感应强度大小等于0112IR。4.AC 为一根长为l 2的带电细棒,左半部均匀带有负电,右半部均匀带有正电荷
12、,电荷线密度分别为和,如图所示。O 点在棒的延长线上,距A 端的距离为l,P 点在棒的垂直平分线上,到棒的垂直距离为l。以棒的中点B 为电势的零点,则O 点的电势OU=文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文
13、档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10
14、文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M1
15、0文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M
16、10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6
17、M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F
18、6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4
19、F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M1003ln44,P 点的电势PU=0。5如图所示,有两根载有相同电流的无限长直导线,分别通过X1=1,X2=3 的点,且平行于Y轴,则磁感应强度B等于零的地方是在 X=2的直线上。6.在安培环路定理iLIldB0中,iI是指环路所包围的所有稳恒电流的代数和;B是指环路上的磁感应强度,它是由环路内外全部电流所产生的磁场叠加。决定的。7若通过S 面上某面元Sd的元磁通为d,而线圈中的电流增加为I2时通过同一面元的元磁通为d,则dd:1:2 。8半径为R 的闭合球面包围一个条形磁铁的一端,此条形磁铁端部的磁
20、感应强度B,则通过此球面的磁通量0。三、计算题。1.一锥顶角为的圆台,上下底面半径分别为1R和2R,在它的侧面上均匀带电,电荷面密度为,求顶点O的电势。(以无穷远处为电势零点)解:以顶点 O为坐标原点,圆锥轴线为x轴,向下为正,在任意位置x处取高度dx的小园环,其面积:222coscos22tgdxdSrxdx其电量:22cos2tgdqdSxdx(它在 O点产生的电势:1 22200224tgdqdUdxrx文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ
21、10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:C
22、J10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:
23、CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码
24、:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编
25、码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档编码:CJ10G2H7B2M1 HK3E2D2J9S10 ZA1Q4Q4F6M10文档
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