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2022年2019届高考数学考前归纳总结复习题19 .pdf

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1、导数中的求参数取值范围问题一、常见基本题型：（1）已知函数单调性，求参数的取值范围，如已知函数()f x增区间，则在此区间上导函数()0fx，如已知函数()f x减区间，则在此区间上导函数()0fx。（2）已知不等式恒成立，求参数的取值范围问题，可转化为求函数的最值问题。例 1.已知aR，函数2()()exf xxax.（xR，e 为自然对数的底数）（1）若函数()(1,1)f x 在内单调递减，求a 的取值范围；（2）函数()f x是否为 R上的单调函数，若是，求出 a 的取值范围；若不是，请说明理由.解：（1）2-()()exf xxax-2-()(2)e()(e)xxfxxaxax=2-

2、(2)exxaxa.()f x要使在-1,1上单调递减，则()0fx对(1,1)x都成立，2(2)0 xaxa对(1,1)x都成立.令2()(2)g xxaxa，则(1)0,(1)0.gg1(2)01(2)0aaaa,32a.（2）若函数()f x在 R上单调递减，则()0fx对xR 都成立即2-(2)e0 xxaxa对xR都成立.2e0,(2)0 xxaxa对xR都成立令2()(2)g xxaxa，图象开口向上不可能对xR都成立若函数()f x在 R上单调递减，则()0fx对xR 都成立，即2-(2)e0 xxaxa对xR都成立，e0,x2(2)0 xaxa对xR都成立.22(2)4

3、40aaa故函数()f x不可能在 R上单调递增.综上可知，函数()f x不可能是 R上的单调函数例 2：已知函数ln3fxaxaxaR,若函数()yf x的图像在点(2,(2)f处的切线的倾斜角为45，对于任意 1,2t，函数32/()2mgxxxfx在区间(,3)t上总不是单调函数，求m的取值范围；解：/(2)1,22afa由32/2()2ln23()(2)2,()3(4)22fxxxmg xxxxgxxmx令/()0gx得，2(4)240m故/()0gx两个根一正一负，即有且只有一个正根函数32/()2mg xxxfx在区间(,3)t上总不是单调函数/()0gx在

4、(,3)t上有且只有实数根/(0)20,()0,(3)0gg tg237,(4)233mmtt故243mtt，而23ytt在t1,2单调减，9m，综合得3793m例 3.已知函数14341ln)(xxxxf（）求函数)(xf的单调区间；（）设42)(2bxxxg，若对任意)2,0(1x，2,12x，不等式)()(21xgxf恒成立，求实数b的取值范围文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I

5、7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5

6、C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6

7、C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I

8、6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4

9、O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10

10、G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A

11、7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1解：（I）14341ln)(xxxxf的定义域是(0,)22243443411)(xxxxxxf由0 x及0)(xf得31x；由0 x及0)(xf得310 xx或，故函数)(xf的单调递增区间是)3,1(；单调递减区间是),3(,)1,0(（II）若对任意)2,0(1x，2,12x，不等式)()(21xgxf恒成立，问题等价于maxmin)()(xgxf，由（I）可知，在(0,2)上，1x是函数极小值点，这个极小值是唯一的极值点，故也是最小值点，所以min1()(1)2f xf；2()24,1,2g

12、 xxbxx当1b时，max()(1)25g xgb；当12b时，2max()()4g xg bb；当2b时，max()(2)48g xgb；问题等价于11252bb或212142bb或21482bb解得1b或1412b或b即142b，所以实数b的取值范围是14,2。例 4设函数22()ln,()f xxmx h xxxa,(1)当a0 时，f(x)h(x)在(1，)上恒成立，求实数m的取值范围；文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 H

13、L10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 Z

14、X8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编

15、码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5

16、 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2

17、 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文

18、档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6

19、J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1(2)当m2 时，若函数k(x)f(x)h(x)在1,3 上恰有两个不同零点，求实数a的取值范围解：(1)由a0，f(x)h(x)，可得mlnxx，x(1，)，即mxlnx.记(x)xlnx，则f(x)h(x)在(1，)上恒成立等价于m(x)min.求得(x)lnx1ln2x当x(1，e)，(x)0；当x(e，)时，(x)0.故(x)在xe 处取得极小值，也是最小值，即(x)min(e)e，故me.(2)函数k(x)f(x)h(x)在1,3 上恰有两个不同的零

20、点等价于方程x2lnxa，在1,3 上恰有两个相异实根令g(x)x2ln，则g(x)12x.当x1,2)时，g(x)0；当x(2,3 时，g(x)0.g(x)在(1,2)上是单调递减函数，在(2,3 上是单调递增函数故g(x)ming(2)22ln2.又g(1)1，g(3)32ln3，g(1)g(3)，只需g(2)ag(3)故a的取值范围是(2ln2,3 2ln3.文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A

21、7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:C

22、V4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL

23、10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX

24、8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码

25、:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5

26、HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2

27、ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1二、针对性练习1.已知函数2()ln.f xxax若函数()()2g xf xx在1，4上是减函数，求实数 a的取值范围。解：由xxaxxg2ln)(2，得222)(xxaxxg又函数xxaxxg2ln)(2为1，4上的单调减函数。则0)(xg在1，4上恒成立，所以不等式0222xxax在1，4上恒成立即222xxa在1，4上恒成立。设222)(xxx，显然)(x在1，4上为减函数，所以)(x的最小值为.263)4(a的取值范围是.263a2.已知函数()1xf xex（1）若存在4 1,l

28、n3x，使10 xaex成立，求a的取值范围；（2）当0 x时，2()f xtx恒成立，求t的取值范围.解:（1）1,xaex即().af x令()10,0.xfxex0 x时，()0,0fxx时，()0.fx()f x在(,0)上减，在(0,)上增.又041,ln3x时，()f x的最大值在区间端点处取到.11444(1)1 1,ln,1ln333fefe，文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6

29、I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O

30、5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G

31、6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7

32、I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV

33、4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL1

34、0G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8

35、A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J14144114(1)ln1 lnln0,33333ffee4(1)ln,()3fff x在41,ln3上最大值为1,e故a的取值范围是1ae，（3）由已知得0 x时，210 xextx恒成立，设2()1.xg xextx()12.xgxetx由（2）知1,xex当且仅当0 x时等号成立，故()2(12)gxxtxt x，从而当120,t即12t时，()0(0),()gxxg x为增函数，又(0)0,g于是当0 x时，()0,g x即2()f xtx，12t时符合题意.由1(0)xex x可得1(0

36、),xex x从而当12t时，()12(1)(1)(2),xxxxxgxet eeeet故当(0,ln 2)xt时，()0,()gxg x为减函数，又(0)0,g于是当(0,ln 2)xt时，()0,g x即2(),f xtx故1,2t不符合题意.综上可得t的取值范围为1,23.已知函数ln(1xf(x)x），设3h(x)xf(x)xax在（0，2）上有极值，求 a的取值范围.解：由3h(x)x f(x)xax可得，文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4

37、O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10

38、G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A

39、7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:C

40、V4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL

41、10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX

42、8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码

43、:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5

44、HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2

45、ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档

46、编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J

47、5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L

48、2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1文档编码:CV4O5C7F6J5 HL10G6C8R6L2 ZX8A7I6I7J1

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