大学物理电磁场练习题含答案教程文件.pdf
《大学物理电磁场练习题含答案教程文件.pdf》由会员分享,可在线阅读,更多相关《大学物理电磁场练习题含答案教程文件.pdf(12页珍藏版)》请在淘文阁 - 分享文档赚钱的网站上搜索。
1、资料收集于网络,如有侵权请联系网站删除word 可编辑前面是答案和后面是题目,大家认真对对.三、稳恒磁场答案1-5 CADBC 6-8 CBC三、稳恒磁场习题1.有一个圆形回路 1及一个正方形回路 2,圆直径和正方形的边长相等,二者中通有大小相等的电流,它们在各自中心产生的磁感强度的大小之比B1/B2为(A)0.90(B)1.00(C)1.11(D)1.222.A I I 边长为 l的正方形线圈中通有电流I,此线圈在 A点(见图)产生的磁感强度 B为(A)lI420(B)lI220(C)lI02(D)以上均不对3.a I I I a a a a 2a I P Q O I a 通有电流 I的无限
2、长直导线有如图三种形状,则P,Q,O各点磁感强度的大小 BP,BQ,BO间的关系为:(A)BP BQ BO.(B)BQ BP BO(C)BQ BO BP(D)BO BQ BP资料收集于网络,如有侵权请联系网站删除word 可编辑4.a O B b r(A)O B b r(C)a O B b r(B)a O B b r(D)a 无限长载流空心圆柱导体的内外半径分别为a、b,电流在导体截面上均匀分布,则空间各处的B的大小与场点到圆柱中心轴线的距离r的关系定性地如图所示 正确的图是5.abcIO12电流I由长直导线 1沿平行 bc边方向经 a点流入由电阻均匀的导线构成的正三角形线框,再由 b点沿垂直
3、 ac边方向流出,经长直导线2返回电源(如图)若载流直导线1、2和三角形框中的电流在框中心O点产生的磁感强度分别用1B、2B和3B表示,则O点的磁感强度大小(A)B=0,因为 B1=B2=B3=0(B)B=0,因为虽然 B1 0、B2 0,但021BB,B3=0(C)B 0,因为虽然 B2=0、B3=0,但B1 0(D)B 0,因为虽然021BB,但B3 06.ab2I1O电流由长直导线 1沿半径方向经 a点流入一电阻均匀的圆环,再由b点沿切向从圆文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10
4、I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:
5、CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 H
6、R5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF
7、10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编
8、码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9
9、 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7
10、ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5资料收集于网络,如有侵权请联系网站删除word 可编辑环流出,经长导线 2返回电源(如图)已知直导线上电流强度为I,圆环的半径为 R,且a、b与圆心 O三点在同一直线上 设直电流 1、2及圆环电流分别在 O点产生的磁感强度为1B、2B及3B,则O点的磁感强度的大小(A)B=0,因为 B1=B2=B3=0(B)B=0,因为021BB,B3=0(C)B 0,因为虽然 B1=B3=0,但B2 0(D)B 0,因为虽
11、然 B1=B2=0,但B3 0(E)B 0,因为虽然 B2=B3=0,但B1 0v7.abdI1OI2c电流由长直导线 1沿切向经 a点流入一个电阻均匀的圆环,再由b点沿切向从圆环流出,经长直导线 2返回电源(如图)已知直导线上电流强度为I,圆环的半径为 R,且a、b和圆心 O在同一直线上 设长直载流导线 1、2和圆环中的电流分别在O点产生的磁感强度为1B、2B、3B,则圆心处磁感强度的大小(A)B=0,因为 B1=B2=B3=0(B)B=0,因为虽然 B1 0、B2 0,但021BB,B3=0(C)B 0,因为 B1 0、B2 0,B3 0(D)B 0,因为虽然 B3=0,但021BB8.a
12、RrOOI在半径为 R的长直金属圆柱体内部挖去一个半径为r的长直圆柱体,两柱体轴线平行,其间距为 a,如图今在此导体上通以电流I,电流在截面上均匀分布,则空心部分轴线上 O点的磁感强度的大小为(A)2202RaaI(B)22202RraaI文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9
13、 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7
14、ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文
15、档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5
16、Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X
17、7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q
18、5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5资料收集于网络,如有侵权
19、请联系网站删除word 可编辑(C)22202rRaaI(D)(222220arRaaI参考解:导体中电流密度)(/22rRIJ设想在导体的挖空部分同时有电流密度为J和J的流向相反的电流这样,空心部分轴线上的磁感强度可以看成是电流密度为J的实心圆柱体在挖空部分轴线上的磁感强度1B和占据挖空部分的电流密度J的实心圆柱在轴线上的磁感强度2B的矢量和由安培环路定理可以求得02B,)(222201rRaIaB所以挖空部分轴线上一点的磁感强度的大小就等于)(22201rRIaB9.R2c3分10.221RB3分11.6.6710-7 T 3分7.2010-7 Am22分12.减小2分在2/Rx区域减小;
20、在2/Rx区域增大(x为离圆心的距离)3分13.0 1分I02分14.410-6 T 2分5 A 2分15.I01分0 2分2I02分16.解:电子绕原子核运动的向心力是库仑力提供的即02202041amaev,由此得002amev2分电子单位时间绕原子核的周数即频率0000142amaeav2分由于电子的运动所形成的圆电流文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5
21、Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X
22、7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q
23、5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9
24、B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L
25、9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O2Q5文档编码:CQ7A1B9B5Z9 HR5C1G9L9X7 ZF10I1L8O
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 大学物理 电磁场 练习题 答案 教程 文件
限制150内