2021年现代通信原理课后答案,沈宝锁第2版.pdf

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1、通信原理第一章绪论1-1 设英文字母C出现的概率为0.023，E出现的概率为0.105,试求 C与 E的信息量。解：1-2设某地方的天气预报晴占4/8，阴占 2/8，小雨占1/8，大雨占1/8，试求各每个消息的信息量。解：晴：阴：2bit 小雨：3bit 大雨：3bit。1-3设有四个信息A、B、C、D 分别以概率1/4，1/8，1/8和 1/2 传递，每一消息的出现的是相互独立的。试计算其平均信息量。解：1-4一个离散信号源每毫秒发出4 种符号中的一个，各相互独立符号出现的概率分别为0.4，0.3，0.2，0.1。求该信号源的平均信息量与信息传输速率。解：1-5设一信息源的输出由128 个不

2、同的符号组成，其中16 个出现的概率为1/32，其余112个出现概率为1/224，信息源每秒钟发1000 个符号，且每个符号彼此独立，试计算该信息源的平均信息速率。解:1-6设一数字传输系统传递二进制码元的速率为1200B，试求该系统的信息传输速率，若该系统改为8 进制码元传递，传码率仍为1200B，此时信息传输速率又为多少？解:Rb=RB=1200b/s 1-7已知二进制数字信号的传输速率为 2400b/s。试问变换成4 进制数字信号时，传输速率为多少波特？解:第二章信道2-1假定某恒参信道的传输特性具有幅频特性，但无相位失真，它的传递函数为dtjeTaKH0cos1)(sbNRRBb/36

3、00312008log1200log22bitXpIC44.5023.01log)(1log22bitIE25.3105.01log2bit148log2符号/75.1)21(1log21)81(1log81)81(1log81)41(1log41)(1log)()(1log)()(1log)()(1log)()(22222222bitDPDPCPCPBPBPAPAPXH符号/84.12.01log2.02.01log2.03.01log3.04.01log4.0)(2222bitXHsbitR/18401084.16符号/405.6)224/1(1log)224/1(112)32/1(1lo

4、g)32/1(16)(22bitXHBNRRbB120022400log2sbitRb/64051000405.6精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 1 页，共 12 页dtjdeTbKTbtjKH)sin1()sin(exp)(00)()()2/()()(00dddtTtStTtSkttKStS其中，K、a、T0和 td 均为常数，试求脉冲信号通过该信道后的输出波形 用 S(t)来表示 。解：根据时延定理：2-2假定某恒参信道的传输特性具有相频特性，但无幅度失真，它的传递函数可写成其 中，k、B、T0和 td均为常数。试求脉冲信号S(t)通过该信道后的输出波形。

5、注解：2-3假定某变参信道的两径时延为1 毫秒，试确定在哪些信号频率上将产生最大传输衰耗，选择哪些信号频率传输最有利。解：对 于 两 径 传 输 的 幅 频 性 依 赖 于（为两径时延），当=2n/（n 为整数）时，则出现传输极点；当=（2n+1）/（n 为整数）时，则出现传输零点。故：当=10-3时，则 f=（n+1/2）KHZ时传输衰耗最大；f=nKHZ时对传输最有利。2-4设某短波信道上的最大多径迟延为3 毫秒，试从减小选择性衰落的影响来考虑，估算在该信道上传输的数字信号的码元宽度。解：选择性衰落的示意图如下所示：因为多径传输时的相对时延差（简称多径时延），通常用最大多径时延来表征，并用

6、它来估计传输零极点在频率轴上的位置。设最大多径时延为m，则 定 义：为相邻零点的频率间隔。所以：2-5 设宽度为T，传号和空号相间的数字信号通过某衰落信道，已知多径迟延为=T/4，接收信号为两条路径信号之和。试画出接收到两信号后的波形，并讨论最大的时延max 为多少才能分辨出传号和空号来。（注：2-3、2-4 和 2-5 属于扩展内容，供教师参考，不作为学生作业）解：设两径的传输衰减相等（均为d0）则：接收到的信号为：s0(t)=d0s(t-t0)+dos(t-t0-)其接收到的两信号的合成波形为讨论：（1）合成波形比原波形的宽度展宽了，展宽部分将造成对邻近码元的串扰。mf10sinsin10

7、TbjeTjb)sin(exp)(0TbtjKHddtjeTaKH0cos1)()()2/()()2/()()(00dddtTtSatTtSattSktSf 0 1/2/3/5/f 秒33106103222mfT0 S(t)2T 3T T t t0+T+T/4 t0+T t0+T/4 t0S(t)t 2COS精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 2 页，共 12 页文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H

8、2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10

9、H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q1

10、0H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q

11、10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6

12、Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K

13、6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2

14、K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1文档编码:CZ3K2K6Q10H2 HF10M8R9H7P4 ZG3V10I2Z5P1)()(XtX)()(YtyjeXXtXtXFy)()()()()(jeXYH1)()()()()1(2)()1)(1()()()(2XXjjXYSCOSSeeSHS（2）若接收端在每码元中心判决，只要弥散不覆盖空码，仍有可能正确判，即要求两径时延不超过下一个码的中心位置，最

15、大时延maxT/2。2-6 在二进制数字信道中，若设发送“1”码与“0”码的概率P(1)与 P(0)相等，P(1/0)=10-4，P(0/1)=10-5，试求总的差错概率。解：P总=0.5P(1/O)+0.5P(0/1)=0.510-4+0.510-5=5.510-52-7 当平稳过程X(t)通过题 2-7 图所示线性系统时，试求输出功率谱。题 2-7 图解:由输入功率谱与输出功率谱之间的关系，则2-8 设随机过程：X(t)=Acos(0t+)式中 A、0是常数,是一随机变量,它在 0 范围内是均匀分布的。即 P()=1/,0(1)求 统计平均 EX(t);(2)确定该过程是否平稳过程。解：（

16、1）（2）因为与 t 有关，所以X（t）不是平稳过程。2-9 已知平稳过程的相关函数为(1)0)1()(aaeRa，(2)cos)(aeR a0 求相应的功率谱。解：（1）（2）2-10 已知平稳过程的功率谱为(1)0)(aSbb(2)0)(2CS其他002 (00)求其相关函数。X(t)Y(t)=X(t)+X(t-)tatadtadxPtXE00000sin2)sin(1)cos()()()(TXE22)()()1(2)()(ajadeadedeRSjajajX2222222222200)()()(2)()()(1)(1)(1)(121)(21)(21cos)()(aaaaaaaajajaj

17、ajadeeeedeeeedeedeRSjjjajjjajajX精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 3 页，共 12 页文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F

18、6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10

19、H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3

20、J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU

21、9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R

22、3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编

23、码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8解：（1）（2）2

24、-11功率谱为n0/2 的白噪声，通过RC 低通滤波器。试求输出噪声的功率谱和自相关函数，并作图与输入噪声作比较。题 2-11 图解：RC 低通滤波器的传输函数为输出功率为：而：自相关函数为：2-12设某一噪声过程N(t)具有题 2-12 图所示的功率谱密SN()(EN(t)=0)。(1)求自相关函数；(2)求此过程的均方值(功率)；(3)把 N(t)写成窄带形式N(t)=NC(t)cos0t-NS(t)sin0t，画出功率谱SNC()和 SNS()，计算)t(NE2C和)t(NE2C。题 2-12 图解：(1)(2)(3)wntNsEtNcE2022)()(2-13 已知某标准音频线路带宽为

25、3.4KHZ。(1)设要求信道的S/N=30dB，试求这时的信道容量是多少?SN()n0/2 W 0-0W R C badaedeSRbjjsin21)(21)()sin2(sin21)(21)(0022200cdecdeSRjj11)(CRJH)1(2112)(2)(22202020CRnCRjnHnSRCjjeRCndeCRndeSR4)1(2)()(02220-W/2 W/2 002/2/02/2/0cos)2(2221221)(21)(000000WSaWndendendesRwwtjwwtjwwtjn2)0(0WnRPSnc()=Snc()no精品w o r d 学习资料 可编辑资料

26、-精心整理-欢迎下载-第 4 页，共 12 页文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3

27、P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10

28、ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I

29、1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文

30、档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP

31、9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K

32、3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8(2)设线路上的最大信息传输速率为4800b/s，试求所需最小信噪比为多少?解：（1）已 知：S/N=30dB S/N=1

33、000（倍）（2）已知：C=Rmax=4800b/s则：2-14 有一信息量为1Mbit的消息,需在某信道传输，设信道带宽为4KHz，接收端要求信噪比为30dB，问传送这一消息需用多少时间?解：秒第三章模拟调制系统3-1 已知调制信号f(t)=Amsin mt，载波 C(t)=A0cos0t (1)试写出标准调幅波AM的表达式。(2)画出时域波形(设=0.5)及频谱图。解：(1)(2)3-2 设一调幅信号由载波电压100cos(2 106t)加上电压50cos12.56t cos(2 106t)组 成。(1)画出已调波的时域波形(2)试求并画出已调信号的频谱(3)求已调信号的总功率和边带功率解

34、：(1)（2）（3）载波功率边带功率)56.12102()56.12102(25)56.12102()102(25)102()102(100)(666666S)/(1089.33)10001(log104.3)1(log3232sbitNSBCdBNSBC2.2)(66.1121233104.3108.4倍)/1(2NSLog100030/dbNSttAAtSmmAm00cossin)()102cos(56.12cos50100)(6tttSAmwApc322010521002wApms625450422SAM(t)t 00 0S()t SAM(t)00 0S()25log32.310410)

35、11000(log100010362BI精品w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 5 页，共 12 页文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3

36、J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU

37、9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R

38、3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编

39、码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H

40、6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F

41、6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8t-00F()已调波功率3-3设调制信号f

42、(t)为)2000cos()(tAtfm,载波频率为10KHZ。试画出相应的DSB和 SSB 信号波形图及AM=0.75 时的 AM的波形图。解：（1）DSB的波形(2)(3)3-4试画出双音调制时双边带(DSB)信号的波形和频谱。其中调制信号为f1(t)=Acos mt，f2(t)=Acos2 mt 且0m。解：图为调制信号3-5已知调幅波的表达式为S(t)=0.125cos(2104t)+4cos(21.1104t)+0.125cos(21.2104t)试求其中(1)载频是什么？(2)调幅指数为多少？(3)调制频率是多少？解：（1）载频为 1.1 104Hz （2）调制指数（3）调制频率为

43、 103HZ0625.0161ttAtftftfmm2coscos)()()(21wpppsc5625ttAttftSmDSB44102cos)2000cos(102cos)()(tAttttAtSmmSSB2000102cos)102sin()2000sin()102cos()2000cos()(444ttAtSAm40102cos)2000cos(75.01)()101.12cos()102cos(16114)102.12cos(125.0)101.12cos(4)102cos(125.0)(43444ttttttSSSSB(t)t 0 SDSB(t)t0 SAM(t)t 0 f(t)精品

44、w o r d 学习资料 可编辑资料-精心整理-欢迎下载-第 6 页，共 12 页文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP

45、9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K

46、3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM

47、10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3

48、P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10

49、ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I

50、1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8文档编码:CP9H6G5K3F6 HM10H1C3P3J10 ZU9F8I1R3V8F()Wm-Wm 0 3-6 已知调制信号频谱如题3-6 图所示，采用相移法产生SSB