2022年1998考研数二真题及解析 .pdf
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1、1998 年全国硕士研究生入学统一考试数学二试题一、填空题(本题共 5 小题,每小题 3 分,满分 15 分,把答案填在题中横线上.)(1)20112limxxxx .(2)曲线322yxxx与x轴所围成的图形的面积A .(3)2ln sinsinxdxx .(4)设()f x连续,则220()xdtf xtdtdx .(5)曲线1ln()(0)yxexx的渐近线方程为 .二、选择题(本题共 5小题,每小题 3分,共15分.在每小题给出的四个选项中,只有一项符合题目要求,把所选项前的字母填在题后的括号内.)(1)设数列nx与ny满足lim0nnnx y,则下列断言正确的是 ()(A)若nx发散
2、,则ny发散 (B)若nx无界,则ny必有界(C)若nx有界,则ny必为无穷小 (D)若1nx为无穷小,则ny必为无穷小(2)函数23()(2)f xxxxx的不可导点的个数是 ()(A)0 (B)1 (C)2 (D)3(3)已知函数()yy x在任意点x处的增量2,1y xyx其中是比(0)xx高阶的无穷小,且(0),y,则(1)y ()(A)4e (B)2 (C)(D)4e(4)设函数()f x在xa的某个邻域内连续,且()f a为其极大值,则存在0,当(,)xaa时,必有 ()(A)()()()0 xaf xf a (B)()()()0 xaf xf a(C)2()()lim0()()t
3、af tf xxatx (D)2()()lim0()()taf tfxxatx(5)设A是任一(3)n n阶方阵,A是其伴随矩阵,又k为常数,且0,1k,则必有()kA ()(A)kA (B)1nkA (C)nk A (D)1kA三、(本题满分 5分)求函数tan()4()(1)xxf xx在区间(0,2)内的间断点,并判断其类型.四、(本题满分 5分)确定常数,a b c的值,使30sinlim(0).ln(1)xxbaxxc ctdtt五、(本题满分 5分)利用代换cosuyx将方程cos2sin3 cosxyxyxyxe化简,并求出原方程的通解.六、(本题满分 6分)计算积分32122d
4、xxx.七、(本题满分 6分)从船上向海中沉放某种探测仪器,按探测要求,需确定仪器的下沉深度y(从海平面算起)与下沉速度v之间的函数关系.设仪器在重力作用下,从海平面由静止开始铅直下沉,在下沉过程中还受到阻力和浮力的作用.设仪器的质量为m,体积为B,海水比重为,仪器所受的阻力与下沉速度成正比,比例系数为(0)k k.试建立y与v所满足的微分方程,并求出函数关系式y=fv.八、(本题满分 8分)设()yfx是区间0,1上的任一非负连续函数.(1)试证存在0(0,1)x,使得在区间00,x上以0()f x为高的矩形面积,等于在0,1x上以()yf x为曲边的梯形面积.(2)又设()f x在区间(0
5、,1)内可导,且2()()fxfxx,证明(1)中的0 x是唯一的.文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3
6、H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:C
7、L5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3
8、H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:C
9、L5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3
10、H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:C
11、L5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6九、(本题满分 8分)设有曲线1yx,过原点作其切线,求由此曲线、切线及x轴围成的平面图形绕x轴旋转一周所得到的旋转体的表面积.十、(本题满分 8分)设()yy x是一向上凸的连续曲线,其上任意一点(,)x y处的曲率为211y,且此曲线上点(0,1)处的切线方程为1yx,求该曲线的方程,并
12、求函数()yy x的极值.十一、(本题满分 8分)设(0,1)x,证明:(1)22(1)ln(1);xxx(2)11111.ln 2ln(1)2xx十二、(本题满分 5分)设11(2)TEC B AC,其中E是4阶单位矩阵,TA是4阶矩阵A的转置矩阵,1232120101230120,0012001200010001BC求A.十三、(本题满分 8分)已知123(1,4,0,2),(2,7,1,3),(0,1,1,),(3,10,4)TTTTab,问:(1),a b取何值时,不能由123,线性表示?(2),a b取何值时,可由123,线性表示?并写出此表达式.1998年全国硕士研究生入学统一考试
13、数学二试题解析文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J
14、7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A
15、2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J
16、7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A
17、2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J
18、7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A
19、2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6一、填空题(本题共 5 小题,每小题 3 分,满分 15 分,把答案填在题中横线上.)(1)【答案】14【解析】方法 1:用四则运算将分子化简,再用等价无穷小替换,原式20112112lim112xxxxxxxx220114lim112xxxxxx220211lim4xxx222201112112lim24xxxxx.方法 2:采用洛必达法则.
20、原式02112limxxxx洛0112 12 1lim2xxxx2011lim41xxxxx011lim4xxxx0112 12 1lim4xxx洛011lim12 12 144xxx.方法 3:将分子按佩亚诺余项泰勒公式展开至2x项,1x22111128xxox,1x22211128xxox,从而原式2222122011111122828limxxxoxxxoxx222122014limxxoxoxx14.(2)【答案】3712【分析】求曲线与x轴围成的图形的面积,应分清楚位于x轴上方还是下方,为此,要先求此曲线与x轴交点.【解析】322yxxx与x轴的交点,即322(2)(1)0 xxxx
21、 xx的根文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S
22、6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U
23、5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S
24、6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U
25、5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S6 HH3I1Q3K3H3 ZF5A2U5Q8R6文档编码:CL5R6J9J7S
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