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2022届新高考数学二轮复习数列专练(1).pdf

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1、（1）数列 1.下列各组数能组成数列的是()A.13，16，19 B.lg3，lg9，lg 27 C.6，8，10 D.3，3 3，9 2.莱茵德纸草书是世界上最古老的数学著作之一.书中有一道这样的题目：把 100 个面包分给 5 个人，使每人所得成等差数列，且使较大的三份之和的17是较小的两份之和，则最大的一份为()A.1153 B.1183 C.1213 D.1243 3.已知等差数列na的前 n 项和为nS，且210S，555S，则过点,nSP nn，*22,2nSQ nnnN的直线的斜率为()A.4 B.3 C.2 D.1 4.等差数列na的前 n 项和为nS，若20212020120

2、212020SS且13a，则()A.21nan B.1nan C.22nSnn D.24nSnn 5.已知递增等比数列na的前 n 项和为nS，10a，2464a a，1310aa，126nS，则n()A.4 B.5 C.6 D.7 6.（多选）已知正项数列na的前 n 项和为nS，若对于任意的 m，*nN，都有m nmnaaa，则下列结论正确的是()A.11285aaaa B.56110a aa a C.若该数列的前三项依次为 x，1x，3x，则10103a D.数列nSn 为递减的等差数列 7.（多选）在数列na中，11a，22a，33a，*31(1)1nnnaanN，数列na的前 n 项

3、和为nS，则下列结论正确的是()A.数列na为等差数列 B.1810a 文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10

4、HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 Z

5、X1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编

6、码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S1

7、0 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8

8、 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文

9、档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4文档编码:CI5F1K4C3S10 HW2Q8X9Q8C8 ZX1M8X8I2E4 C.173a D.31146S 8.设nS是各项均为正数的等比数列na的前 n 项和，13a，若4a，3a，5a成等差数列，则nS与na的关系式为_.9.已知等比数列na的公比0q，其前 n

10、项和为nS，且236,14SS，则数列2211loglognnaa的前 2021 项和为_.10.数列na是首项为 1，公差不为 0 的等差数列，且125,a aa成等比数列；数列nb的前 n 项和为nS，且1122,1()3nnbSSnN.（1）求,nna b；（2）若nnncab，且数列nc的前 n 项和为nT，证明：9nT.文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9

11、L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y

12、10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W

13、5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4

14、E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A

15、1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O

16、1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:C

17、Q4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2 答案以及解析 1.答案：D 解析：116123，129136，选项 A中的三个数不能组成等比数列.lg92lg32lg3lg3，lg 273lg33lg92lg32，选项B中的三个数不能组成等比数列.8463，10584，选项 C中的三个数不能组成等比数列.3 333，933 3，选项 D中的三个数能组成等比数列.故选 D.2.答案：A 解析：设最大的一份为 x，从大到小排列的等差数列的公差为 d.由题意得()(2)(3)(4)100 xxdxdxdxd，且1()(2)(3)(4)7xxdxdxdxd ，解得1153x.3

18、.答案：C 解析：因为数列na为等差数列，所以数列nSn 也是等差数列，则数列nSn 的图象是一条直线上的一些等间隔的点，因此经过 P，Q 两点的直线必经过点22,2S与55,5S，故直线 PQ 的斜率52115522523SSk，故选 C.4.答案：A 解析：设na的公差为 d，112nn nSnad，111222nSnddadnan ，即nSn 为等差数列，公差为2d，由20212020120212020SS知122dd，故23212122nnnnanSnn，.故选 A.5.答案：C 解析：设等比数列的公比为q，因为10a 且na递增，所以1q，因为2464a a，1310aa

19、，所以24121164+10a qaa q，所以122aq，所以 2 1212612nnS，所以2163n，所以6n，故选 C.文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 Z

20、R4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编

21、码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3

22、 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5

23、 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文

24、档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7

25、J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2 6.答案：AC 解析：令1m，则11nnaaa，因为10a，所以na为等差数列且公差0d，故 A 正确；2222561 1011119

26、209200a aa aaa ddaa dd，所以56110a aa a，故 B错误；根据等差数列性质得2(1)3xxx，所以13x，213x，故1011109333a ，故 C正确；11(1)222nn nnadSddnann，因为02d，所以nSn 是递增的等差数列，故 D错误.故选 AC.7.答案：BD 解析：依题意得，当 n 是奇数时，311nnaa，即数列na中的偶数项构成以22a 为首项、1 为公差的等差数列，所以182(91)110a .当 n 是偶数时，311nnaa，所以531nnaa，两式相减，得51nnaa，即数列na中的奇数项从3a开始，每间隔一项的两项相等，即数列na

27、的奇数项呈周期变化，所以174 3 55aaa.在311nnaa中，令2n，得531aa，因为33a，所以52a ，所以172a.对于数列na的前 31 项，奇数项满足351aa，791aa，27291aa，314 7 333aaa，偶数项构成以22a 为首项、1 为公差的等差数列，所以3115(151)1731521462S .故选 BD.8.答案：23nnSa 解析：设等比数列na的公比为 q，因为数列na的各项均为正数，所以0q.由4a，3a，5a成等差数列，得3542aaa，则220qq ，解得2q，所以 1111211nnnnaqaa qSaaqq，即23nnSa.9.答

28、案：20212022 解析：因为233212118,6aSSa qSaa q ，所以211143a qaa q，所以23440qq，文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5

29、 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文

30、档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7

31、J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2

32、M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G

33、2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6

34、G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2 得2q 或23（舍去），所以12a，故2nna.因为2211111loglog(1)1nnaan nnn，所以2021111111

35、2021112232021202220222022T .故答案为：20212022 10.答案：(1)21nan，22,112,233nnnbn (2)见解析解析：(1)设数列na的公差为(0)d d，由125,a aa成等比数列，得2(1)1(14)dd ，解得0d(舍去)或2d，所以21nan.已知1122,13nnbSS，当1n 时，121213bbb，解得213b；当2n 时，1213nnSS，则1123nnnnSSSS，即12(2)3nnbb n，又2123bb，所以22,112,233nnnbn .(2)证明：由(1)得22,1212,233nnncnn ，则2352722133

36、333nT 322322123333nnnn ，两边同乘23，得224252133333nT 321252232212333333nnnnnn ，两式相减，得214222333333nT 212212333nnn 文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5

37、 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文

38、档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7

39、J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2

40、M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G

41、2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6

42、G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2 221221335212233313nnn 12

43、52333nn ，所以129(25)3nnTn ，因为12(25)03nn ，所以129(25)93nnTn .文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7

44、G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L

45、6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y1

46、0V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5

47、X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E

48、9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2文档编码:CQ4E9L6G7J3 HY2A1Y10V2M5 ZR4O1W5X7G2

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2022届新高考数学二轮复习 数列专练(1).pdf

2022届新高考数学二轮复习数列专练(1).pdf