2022年2020届中考化学必备知识点归纳复习资料19 .pdf

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1、一、复习内容和要求1化学计算的常用方法（1）守恒法：包括原子个数守恒、得失电子守恒、电荷守恒法、质量守恒法等。（2）极值法：从问题的极端去思考、去推理、判断，使问题得到解决。（3）讨论法：当题中含有不确定的因素时，对每一种可能情况进行的讨论。（4）十字交叉法：已知混合中某一量的平均值，求混合物中两物质的质量比。（5）差量法：运用前后量的差，根据方程式中的计量数的关系直接求解。2化学计算的常用技巧（1）定量问题定性化；（2）近似估算；（3）运用整体思维，化繁为简；（4）利用图象解题等等。二、解题方法和技巧：1守恒法：例 1、由 Mg(OH)2和 MgO 组成的混合物，测得其中含镁元素的质量分数为

2、 48。取该混合物10g，将其投入 110g的稀硫酸中恰好完全反应，所得溶液中溶质的质量分数为()A 12B24C20D30解析：根据在化学反应中Mg 元素的质量守恒，建立Mg 元素和MgSO4的质量关系可求得反应后所得溶液中的溶质MgSO4的质量，即可求得所得溶液中溶质的质量分数。Mg MgSO424 120 10g48%=4.8g x 2平均值法例 1锌、铁、镁三种金属中的两种混合物13 g，与足量的盐酸反应产生的氢气在标准状况下为1g，则混合物中一定含有的金属是。(A)锌(B)铁 (C)镁(D)无法推断解析：根据锌、铁、镁三种金属与足量的盐酸反应，均生成二价金属阳离子得：(R 为金属，设

3、平均式量M）R+2HCl=RCl2+H2M 2g 13 1g M:13=2:1 M=26 则必须有相对原子质量大于26 和小于 26 的金属存在，又因为锌、铁的相对原子质量均大于26，只有镁的相对原子质量小于26，故答案为 C。2十字交叉法例 2.用向下排气法在容积为V mL 的集气瓶中收集氨气，由于空气尚未排净，最后瓶内气体的平均式量为19，将此盛满气体的集气瓶倒置于水中，瓶内水马上升到一定高度后，即停止上升，则在同温同压下，瓶内剩余气体的体积 为（）A.V/4 mL B.V/5 mL C.V/6 mL.D.无法判断解析：用十字交叉法计算氨气与空气的体积比：所以氨气占 5/6，空气占 1/6

4、；由于氨气易溶于水，故剩余气体为空气。3极值法例 4.取 5.4 g由某碱金属 R 及其氧化物 R2O 组成的混合物。该混合物与足量的水反应。反应完毕，蒸发反应后得到的溶液，得到8 g无水晶体。试通过计算，判断该金属是哪一种碱金属？解析：(i)设 5.4 克混合物都是碱金属R，则由(ii)设 5.4 g 混合物都是碱金属 R 的氧化物 R2O，则由综(i)和(ii)所述，碱金属R 的式量 k 的范围为(10.7,35.3)。在碱金属中，只有金属Na 的式量 23 在(10.7,35.3)中，所以该碱金属是金属钠。4、差量法例 3.把 22.4g 铁片投入到 500gCuSO4溶液中，充分反应后

5、取出铁片，洗涤、干燥后称其质量为22.8g，计算(1)析出多少克铜？(2)反应后溶液的质量分数多大？解析：“充分反应”是指 CuSO4中 Cu2+完全反应，反应后的溶液为FeSO4溶液。分析下面的化学方程式可知：每溶解56gFe，就析出 64g 铜，使铁片质量增加 8g(64-56=8)，反过来看：若铁片质量增加8g，就意味文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6

6、N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV

7、6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:C

8、V6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:

9、CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码

10、:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编

11、码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档

12、编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9着溶解 56gFe、生成 64gCu，即“差量”8 与方程式中各物质的质量(也可是物质的量)成正比。所以就可以根据题中所给的已知“差量”22.8-22.4=0.4g 求出其他有关物质的量。5、讨论法：例 4、将 5g 某物质完全溶解在95g 水中，所得溶液中溶质的质量分数为（）A、等于 5%B、小于 5%C、大于 5%D、无法确定解析：对于 5

13、g 某物质要进行讨论：这5 g 某物质若是 CaO、Na2O或 SO2等物质，则溶于水后其溶质质量分数会大于5%；这 5g 某物质若是 CuSO45H2O 等物质溶于水后其溶质质量分数则会小于5%；若是 NaCl 等物质，则其溶质质量分数等于5%。三、习题精练：1某硫酸钠溶液中，Na+与 H2O 分子个数比为 1:50 时，此溶液中硫酸钠质量分数为（）A、32.4%B、1.96%C、7.3%D、88.75%2用 60%酒精溶液甲与 25%酒精溶液乙混合，配制成45%酒精，所3用甲、乙溶液的质量比为（）A、12 B、23 C、43 D、31 3要使 50g 某物质溶液含水量由98%增加到 99%

14、，应加水（）A、1g B、5g C、50g D、100g 4海水中 Na+的质量分数为 1.42%，如全部以 NaCl 计算，则海水中NaCl 的质量分数为（）A、3.61%B、39.3%C、14.2%D、55.81%6.现有铁，锌，镁，铝四种金属分别与足量稀硫酸反应，生成氢气质量相等时，消耗金属质量最小的是：（）A铁B.锌C.镁D.铝7.质量相同的一氧化碳，甲烷和酒精分别燃烧，消耗氧气最多的是：（）A.一氧化碳B.甲烷C.酒精D.无法判断8.一定质量的 Fe2O3分别被 CO、C 和 H2三种还原剂完全还原成铁，所生成的纯铁的质文档编码:CV6N4M10S5M10 HX10I1H3C5K4

15、ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4

16、 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K

17、4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5

18、K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C

19、5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3

20、C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H

21、3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9量是：（）A.一样多B.CO 多C.C 多D.H2多9.两份质量相同的碳分别生成二氧化碳和一氧化碳，消耗氧气的质量比是：（）A.1:1

22、B.1:2 C.2:1 D.3:2 10.质量相同，质量分数也相同的硫酸溶液，分别与足量的下列物质完全反应，所得MgSO4质量分数最大的是：（）A.MgCO3B.MgO C.Mg D.Mg(OH)211.Cu 和 Fe的混合粉末若干克，与足量盐酸反应后，过滤。将滤渣在空气中充分加热，加热后的质量恰好等于原混合物的质量，则原混合物中铁的质量分数：（）A.20B.40C.50.4D.8012.在托盘天平的两盘上分别放一个盛有100毫升质量分数为 20的稀硫酸的等质量的烧杯，调节天平至平衡，然后分别加入等质量铁片（左盘）和锌片（右盘），反应完全后，天平可能出现的情况是：（）1.仍保持平衡2.右盘下沉

23、3.左盘下沉4.无法判断A.B.C.D.14.把 A、B 两块等重的铁片，分别浸入稀硫酸和硫酸铜溶液中，过一段时间后取出烘干，冷却。如果把它们分别放入已经平衡的天平两个托盘下，可以推测：（）A.放 A 铁片的托盘上升B.放 B 铁片的托盘上升C.天平仍保持平衡D.哪一边托盘上升不一定，这需根据原铁片消耗的程度而定15.在天平两端各放一个盛有等质量等质量分数的稀硫酸的烧杯，调天平至平衡，若分别投入镁粉和铁粉，且全部溶解，天平仍保持平衡，则投入镁粉和铁粉的质量比为：（）A.37 B.73 C.7781 D.8177 16.在托盘天平两端各放一只烧杯，调节到至平衡，向烧杯中分别注入等质量，等质量分数

24、的稀硫酸，然后向一只烧杯里加入一定质量的镁，向另一只烧杯里加入等质量的铜铝合金，两烧杯中的反文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9

25、L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I

26、9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7

27、I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G

28、7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8

29、G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX

30、8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 Z

31、X8G7I9L1I9应恰好完全且天平保持平衡，铜铝合金中铜与铝的质量比为：（）A.13 B.12 C.34 D.23 17.在托盘天平两边各放一只烧杯，调节至平衡，在烧杯里分别注入质量相等，质量分数相同的稀硫酸，若在右盘投入一定量的铁，恰好完全反应，为使天平保持平衡，应向左盘投入与铁质量相同的纯净金属是：（）A.Mg B.Al C.Zn D.Ag 18等物质的量的 NaHCO3和 KHCO3的混合物 9.20g与 100mL 盐酸反应。（1）试分析，欲求标准状况下生成的CO2的体积时，还需什么数据（用 a、b 等表示，要注明单位）。（2）利用所确定的数据，求标准状况下生成的CO2的体积：所 需

32、 数 据的 取值范围生成 CO2的体积（标准状况）盐酸不足时盐酸过量时(3)若 NaHCO3和 KHCO3不是等物质的量混合，则9.2g 固体与盐酸完 全反 应时，在 标准状 况下 生成CO2气体 的 体积 大 于L，小于L。文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5

33、M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S

34、5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10

35、S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M1

36、0S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M

37、10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4

38、M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9文档编码:CV6N4M10S5M10 HX10I1H3C5K4 ZX8G7I9L1I9