大学物理第二版习题答案罗益民北邮出版社第七章答案.pdf
《大学物理第二版习题答案罗益民北邮出版社第七章答案.pdf》由会员分享,可在线阅读,更多相关《大学物理第二版习题答案罗益民北邮出版社第七章答案.pdf(15页珍藏版)》请在淘文阁 - 分享文档赚钱的网站上搜索。
1、优秀学习资料欢迎下载第 7 章电磁感应电磁场7-1 ac 间电势差等于其电动势lBvd)(端电势高cVbcBbcbcabacV1088.1215.11.0105.260cos327-2 解:lBvd)(先求0b,在 ob 上任取rr d,d上的)(Bv方向如图则lbBlrrBrvB3202092d0cosd90sin同理18d23100BlrrBla端电势高bBlBlBlabba222006118927-3 如右图所示,设B 的方向垂直小面积a2向下。当圆盘逆时针转动时,磁场区产生感应电动势BarBai因此,在此小区域形成沿径向流向盘心的感应电流RBarRIiiR 为小面积a2的电阻,由图示可
2、知tBarItataRi11此电流 Ii在磁场中受到磁力为traBBaIfi22显然力 f 与转速反向,为一磁阻力,故磁阻力矩为traBrfM222习题 7-1 图习题 7-2 图习题 7-3 图-第 1 页,共 15 页精品p d f 资料 可编辑资料-优秀学习资料欢迎下载7-4 见图示,在圆弧ab上取一线元dl,由于切割磁力线产生动生电动势lVBlBVddcosd)(为BV与ld之间的夹角,由图示几何关系可知:sin,dd,2RrRldsindsindsind22BRBRrVBR则ab上的动生电动势为24/024/02282d22cos1dsindBRBRBR的方向为ba7-5 设 t 时
3、刻半圆形导线的法线与B 构成角,因匀角速旋转,故ftt2,此时,通过半圆形部分的磁通量为ftrBtBS2cos2cos2该电路中产生的感应电动势为ftfrBt2sindd22感应电流为ftRfrBRI2sin22其最大值为电流幅值RfrBIm227-6 设 t 时刻圆形导线的法线与B 构成角。tNBStNtBsftsinddcos602习题 7-4 图-第 2 页,共 15 页精品p d f 资料 可编辑资料-文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A
4、7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S
5、9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R
6、10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2
7、H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX
8、5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G
9、3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编
10、码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7优秀学习资料欢迎下载V7.16012.0105.01042442maxrNBNBS7-7 解法(一)设 t时刻时,AD 边离电流 I 的距离为 y,y 是时间的函数。在矩形线圈内取面元xlSdd1,电流 I 产生的磁场穿过dS的磁通量xlxISdBdd210则yylIlxxIllyy21010ln2d2d2)dd()(2dd)11(2dd2210210
11、vtyvylylIltyylyIlt当m10.0ay时V106.105.009.004.003.006.05102)(2872210alavlIl其绕行方向为顺时针方向。解法(二),线圈 4 个边中仅有平行电流I 的两个边切割磁力线而产生电动势,在t 时刻近电流I 的一边产生电动势aIllB2101111的方向向上。同理,t 时刻远电流边产生的电动势为)(2210122alIllB2方向向上。故线圈中的电动势为alaIl21021112习题 7-7 图-第 3 页,共 15 页精品p d f 资料 可编辑资料-文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7
12、文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:C
13、Y7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2
14、L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 H
15、P4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J
16、4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10
17、 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6
18、I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7优秀学习资料欢迎下载alalIl)(2221021结论同解法(一)。7-8 取如图示之坐标轴ox,在金属杆上取线元dx,两个长直等值反向电流在dx 处产生的磁感强度xaxIB21120则 dx 上产生的动生电动势为xxaxIxBd2112dd0故金属杆
19、上的动生电动势为babaIxxaxIbabalnd2112d00金属杆在左端电势高。7-9(1)在矩形线圈内取一面元dS=ldx,此面元处的磁感强度据题设可得xdbxIB1120B 的方向垂直纸面向里。故穿过线圈内的磁通量bbaddaIldabbdaIlbabddaIlxxdbxIlSBabb)()(ln2)()(ln2lnln2d112d0000线圈中的感生电动势为tIdbabadltdd)()(ln2dd07-10 设 t 时刻杆 CD 位于 Y 处,这时CD 杆与抛物线相交的两端长为kyx22,此时杆向上运动的速度据题设应为ay2,故此时回路中的电动势即为杆长2x 内切割磁力线所产生的感
20、应电动势,即习题 7-8 图习题 7-9 图-第 4 页,共 15 页精品p d f 资料 可编辑资料-文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6
21、G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档
22、编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7
23、A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9
24、S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4
25、R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J2H10 ZX5K6I6G3B7文档编码:CY7A7Z2L9S9 HP4R10J4J
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 大学物理 第二 习题 答案 罗益民北邮 出版社 第七
限制150内