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2022年2017年高考真题--立体几何部分 .pdf

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上传时间：2022-11-02

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1、试卷第 1 页，总 3 页20XX年高考真题-立体几何部分学校:_姓名：_班级：_考号：_ 一、解答题1（12 分）如图，四棱锥P-ABCD 中，侧面PAD 为等比三角形且垂直于底面ABCD，o1,90,2ABBCADBADABCE是 PD 的中点.（1）证明：直线/CE平面 PAB（2）点 M 在棱 PC 上，且直线BM 与底面 ABCD所成锐角为o45，求二面角M-AB-D的余弦值2（12 分）如图，在四棱锥P-ABCD中，AB/CD，且90BAPCDP(1)证明：平面PAB 平面 PAD；(2)若 PA=PD=AB=DC,90APD,求二面角A-PB-C的余

2、弦值.3（12 分）如图，四面体ABCD中，ABC是正三角形，ACD是直角三角形，ABD=CBD，AB=BD 试卷第 2 页，总 3 页（1）证明：平面ACD 平面 ABC；（2）过 AC的平面交BD于点 E，若平面 AEC把四面体ABCD 分成体积相等的两部分，求二面角 DAE C的余弦值4如图，在四棱锥P-ABCD中，底面ABCD为正方形，平面PAD平面 ABCD，点 M 在线段 PB上，PD/平面 MAC，PA=PD=6，AB=4（I）求证：M 为 PB的中点；（II）求二面角B-PD-A 的大小；（III）求直线MC 与平面 BDP所成角的正弦值5如图，在三棱锥P-ABC中，PA 底面

3、 ABC，90BAC.点 D，E，N 分别为棱PA，PC，BC的中点，M 是线段 AD 的中点，PA=AC=4，AB=2.（）求证：MN平面 BDE；（）求二面角C-EM-N 的正弦值；（）已知点H 在棱 PA上，且直线NH 与直线 BE所成角的余弦值为721，求线段AH的长.617.如图，几何体是圆柱的一部分，它是由矩形（及其内部）以边所在直线为旋转轴旋转得到的，是的中点.（）设是上的一点，且，求的大小；（）当，求二面角的大小.文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文

4、档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9

5、X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1

6、H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z

7、7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6

8、O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5

9、P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B

10、6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7试卷第 3 页，总 3 页7（本题满分15 分）如图，已知四棱锥P ABCD，PAD 是以 AD 为斜边的等腰直角三角形，BC AD，CDAD，PC=AD=2DC=2CB，E 为 PD 的中点.（）证明：CE平面 PAB；（）求直线CE 与平面 PBC 所成角的正弦值.文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6

11、Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G

12、6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J

13、5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6

14、B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N

15、1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P1

16、0J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5

17、W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE

18、8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9

19、P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2

20、B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:

21、CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 H

22、C9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 Z

23、T2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7本卷由系统自动生成，请仔细校对后使用，答案仅供参考。答案第 1 页，总 10 页参考答案

24、1（1）详见解析（2）110cos|cos,|56114n k【解析】z yxMMOFPABCDE（1）取PA中点F，连接EF、BF、ECE、F分别为PD、PA中点12EFAD，又12BCADEFBC，四边形BCEF为平行四边形CE平面PAD（2）取AD中点O，连PO，由于PAD为正三角形POAD又平面PAD平面ABCD，平面PAD平面ABCDADPO平面ABCD，连OC，四边形ABCD为正方形。PO平面POC，平面POC平面ABCD而平面POC平面ABCDOC过M作MHOG，垂足为H，MH平面ABCDMBH为MB与平面ABCD所成角，45MBHMHBH在PCO中，MHPO，MHCHPOCO，

25、设ABBCa，2ADa，3POa，COa3MHCHaa，3MHCH在RtBCH中，222BHBCCH，2223CHaCH文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5

26、W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE

27、8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9

28、P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2

29、B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:

30、CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 H

31、C9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7本卷由系统自动生成，请仔细校对后使用，答案仅供参考。答案第 2 页，总 10 页22CHa，62MHa，22OHaa以O为坐标原点，OC

32、、OD、OP分别为x、y、z轴建立空间直角坐标系，26(,0,)22M aaa，(0,0)Aa，(,0)B aa，26(,)22MAaaaa，(,0,0)ABa设平面MAB的法向量为(0,1)yn，602MAayan，62y6(0,1)2n，而平面ABCD的法向量为(0,0,1)k设二面角MABD的大角为（为锐角）110cos|cos,|56114n k。2（1）详见解析；（2）33【解析】（1）由已知90BAPCDP，得 AB AP，CD PD.由于 AB CD，故 AB PD，从而AB 平面 PAD.又 AB 平面 PAB，所以平面PAB 平面 PAD.（2）在平面P

33、AD内做PFAD，垂足为F，由（1）可知，AB平面PAD，故ABPF，可得PF平面ABCD.以F为坐标原点，FA的方向为x轴正方向，|AB为单位长，建立如图所示的空间直角坐标系Fxyz.文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档

34、编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X

35、3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H

36、6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7

37、文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O

38、9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P

39、1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7本卷由系统自动生成，请仔细校对后使用，答案仅供参考。答案第 3 页，总 10

40、页由（1）及已知可得2(,0,0)2A，2(0,0,)2P，2(,1,0)2B，2(,1,0)2C.所以22(,1,)22PC，(2,0,0)CB，22(,0,)22PA，(0,1,0)AB.设(,)x y zn是平面PCB的法向量，则00PCCBnn，即2202220 xyzx，可取(0,1,2)n.设(,)x y zm是平面PAB的法向量，则00PAABmm，即220220 xzy，可取(1,0,1)n.则3cos,|3n mn mn m，所以二面角APBC的余弦值为33.3（1）见解析（2）二面角CAED的余弦值为42.【解析】（1）由题设可得，,ABDCBDADDC从而又ACD是直角三

41、角形，所以0=90ACD取 AC的中点 O，连接 DO,BO,则 DO AC,DO=AO又由于ABCBOAC是正三角形，故所以DOBDACB为二面角的平面角文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3

42、HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6

43、ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档

44、编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X

45、3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H

46、6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7

47、文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7本卷由系统自动生成，请仔细校对后使用，答案仅供参考。答案第 4 页，总 10 页2222222220,Rt

48、AOBBOAOABABBDBODOBOAOABBDACDABC在中，又所以，故DOB=90所以平面平面（2）由题设及（1）知，OA,OB,OD两两垂直，以 O 为坐标原点，OA的方向为x轴正方向，OA为单位长，建立如图所示的空间直角坐标系O xyz-，则(1，0，0),(0，3，0),(1，0，0),(0，0，1)ABCD由题设知，四面体ABCE的体积为四面体ABCD的体积的12，从而E 到平面ABC的距离为D到平面 ABC的距离的12，即 E为 DB的中点，得E3 10，22.故3 11，0，1，2，0，0，1，22ADACAE设=x,y,zn是平面 DAE的法向量，则00，即3100，22

49、xzADxyzAEnn可取3113=,n设m是平面 AEC的法向量，则0，0，ACAEmm同理可得013,m则77cos,n mn mn m文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5

50、P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B6Z7文档编码:CE8N1G6O9X3 HC9P10J5P1H6 ZT2B5W6B

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