工程力学习题答案第2章 力系的简化与平衡.docx
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1、第2章力系的简化与平衡2-4 Fr = -1.5i 一 2.0 J (kN) , x = 290mm 2-5 Fa = 54.64kN, Fc = 74.64kN26 Q=173kN, 7 = 952-7 P2 = 333.3kN, x = 6.75m2-8 Fa =231N2-9 P = 81kg/2Z?Y32-10 a = arccos I,J2-11 k = 5.61 N/m,、L F 5 . M 厂 F 1 7 M2-12(a) Fa =1qb, FR =qb-a 24 2b R 2 4 2b 3313(b) Fa =-F + -qb, Fb =-F + -qbFAx = l(MkN,
2、 FAv = 60kN, MA =220kN.m Fc =120kN(c) FAx = 0, FAv = -2.5kN; Fb = 15kN, FD = 2.5kNFAx = 0, FAy = 2.5kN, MA =10kN.m, Fc =1.5kN(f),, = 0, FAy = -51.25kN, Fb = 105 kN, FD = 62.5kN2-13(a) FAx = FAv = 0; FBx = -50kN,心v= 100kN *FAx = 20kN, FAy = 70kN; F以=20kN, FBy = 50kN2-14 M = 70.36N m“ Pr A2-15 M =Lr22
3、-16 6底=112.5kN, FAy =112.5kN; FBx = -37.5kN, FBy =-112.5kN;FCx =75 kN, FCy=02-17= 一4.4kN, FAy = 4.0kN;方以=9.34 kN, FBy = 2.67kN;Fc=Fe= 14.9kN, Fd = 4.4kN2.18 FAx = 1.2kN, F/b) =0.15kN; FB =1.05kN, FBC =-1.5kN2-19 F = 1467N2-20 Fac = Fcc = Fgk = Fbd = Fdh = Fhk = -lOkN,其余为零杆。2-21 K = 5.333F (压),& = 2F
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