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2022年中考数学卷精析版湖北天门卷 .pdf

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1、2012年中考数学卷精析版天门卷（本试卷满分120 分，考试时间120 分钟）一、选择题（共10 个小题，每小题3 分，满分 30 分）在下列各小题中，均给出四个答案，其中有且只有一个正确答案，请将正确答案的字母代号在答题卡上涂黑，涂错或不涂均为零分3（2012 湖北天门、仙桃、潜江、江汉油田3 分）吸烟有害健康据中央电视台2012 年 5 月 30 日报道，全世界每因吸烟引起的疾病致死的人数大约为600 万，数据600 万用科学记数法表示为【】A 0.6 107 B6 106 C60 105 D6 105【答案】B。【考点】科学记数法。【分析】根据科学记数法的定义，科学记数法的表示形式为a

2、10n，其中1|a|10，n 为整数，表示时关键要正确确定a 的值以及n 的值。在确定n 的值时，看该数是大于或等于1 还是小于1。当该数大于或等于 1 时，n 为它的整数位数减1；当该数小于1 时，n 为它第一个有效数字前0 的个数（含小数点前的1个 0）。600 万=6000000 一共 7 位，从而600 万=6000000=6 106。故选 B。4（2012 湖北天门、仙桃、潜江、江汉油田 3 分）不等式组x12x4。它与x 轴的两个交点分别为（1，0），（3，0），对称轴是x=1，文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1

3、P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5

4、A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1

5、P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5

6、A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1

7、P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5

8、A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1

9、P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3b=12a。b+2a=0。故命题错误。a0，b02a，b0。又 c0，abc 0。故命题正确。b+2a=0，a 2b+4c=a+2b 4b+4c=4b+4c。ab+c=0，4a4b+4c=0。4b+4c=4a。a0，a2b+4c=4b+4c=4a0。故命题正确。根据图示知，当x=4 时，y0，16a+4b+c0。由知，b=2a，8a+c0。故命题正确。正确的命题为：三个。故选A。二、填空题（本大题共5 个小题，每小题3 分，满分 15 分）11（2012 湖北

10、天门、仙桃、潜江、江汉油田3 分）分解因式：3a2b+6ab2=【答案】3ab（a+2b）。【考点】提公因式法因式分解。【分析】观察可得此题的公因式为：3ab，提取公因式即可求得答案：3a2b+6ab2=3ab（a+2b）。12（2012 湖北天门、仙桃、潜江、江汉油田3 分）Lost time is never found again（岁月既往，一去不回）在这句谚语的所有英文字母中，字母“i”出现的频率是【答案】0.12。【考点】频数、频率和总量的关系。【分析】找出字母“i”出现的次数，及总的字母数，根据频数、频率和总量的关系即可得出答案：由题意得，总共有25 个，字母“i”出现的次数为：3

11、次，故字母“i”出现的频率是3=0.1225。13（2012 湖北天门、仙桃、潜江、江汉油田3分）学校举行“大家唱大家跳”文艺汇演，设置了歌唱与舞蹈两类节目，全校师生一共表演了30 个节目，其中歌唱类节目比舞蹈类节目的3 倍少 2 个，则全校师生表演的歌唱类节目有个【答案】22【考点】一元一次方程的应用。【分析】设歌唱类节目有x 个，则舞蹈类节目有30 x 个。由等量关系：歌唱类节目比舞蹈类节目的3 倍少 2 个，可得x=2（30 x）2，解得：x=22，即歌唱类节目有22 个。14（2012 湖北天门、仙桃、潜江、江汉油田3分）如图，线段AC=n+1（其中 n 为正整数），点 B 在线段

12、 AC 上，在线段AC同侧作正方形 ABMN 及正方形BCEF，连接 AM、ME、EA 得到文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3

13、G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7

14、T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3

15、G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7

16、T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3

17、G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7

18、T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3AME当 AB=1 时，AME 的面积记为S1；当 AB=2 时，AME 的面积记为S2；当 AB=3 时，AME的面积记为S3；当 AB=n 时，AME 的面积记为Sn当 n2 时，SnSn1=【答案】2n12。【考点】正方形的性质，平行的判定和性质，同底等高的三角

19、形面积，整式的混合运算。【分析】连接 BE，在线段AC 同侧作正方形ABMN 及正方形BCEF，BEAM。AME 与 AMB 同底等高。AME 的面积=AMB 的面积。当 AB=n 时，AME 的面积为2n1Sn2，当 AB=n 1 时，AME 的面积为2n1Sn12。当 n2 时，22nn 11112n1SSnn1=n+n1nn+1=2222。15（2012 湖北天门、仙桃、潜江、江汉油田3分）平面直角坐标系中，M 的圆心坐标为（0，2），半径为 1，点 N 在 x 轴的正半轴上，如果以点N 为圆心，半径为4 的 N 与 M 相切，则圆心N 的坐标为【答案】（21，0）或（5，0）。【考点】

20、相切两圆的性质，坐标与图形性质，勾股定理。【分析】分别从 M 与 N 内切或外切去分析：M 与 N 外切，MN=4+1=5，2222ON=MNOM5221，圆心 N 的坐标为（21，0）。M 与 N 内切，MN=41=3，2222ON=MNOM325，圆心 N 的坐标为（5，0）。文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

21、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

22、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

23、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

24、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

25、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

26、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3综上所述，圆心N 的坐标为（21，0）或（5，0）。三、解答题（本大题共9 个

27、小题，满分74 分）16（2012 湖北天门、仙桃、潜江、江汉油田5分）计算：252000+4【答案】解：原式=10+2000+2=2012.【考点】实数的运算。【分析】先进行乘法运算和开方运算，然后进行实数的加法运算即可。17（2012 湖北天门、仙桃、潜江、江汉油田7分）某市青少年宫准备在七月一日组织市区部分学校的中小学生到本市A，B，C，D，E 五个红色旅游景区“一日游”，每名学生只能在五个景区中任选一个为估算到各景区旅游的人数，青少年宫随机抽取这些学校的部分学生，进行了“五个红色景区，你最想去哪里”的问卷调查，在统计了所有的调查问卷后将结果绘制成如图所示的统计图（1）求参加问卷调查的学

28、生数，并将条形统计图补充完整；（2）若参加“一日游”的学生为1000 人，请估计到C 景区旅游的人数【答案】解：（1）参加问卷调查的学生数为：50 25%=200（人）。到 B 景区旅游的人数是：2002070 1050=50（人），据此补充条形统计图如图：（2）70 200=35%，1000 35%=350（人）。答：估计到C 景区旅游的有350 人。【考点】扇形统计图，条形统计图，频数、频率和总量的关系，用样本估计总体。文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:C

29、L3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1

30、N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:C

31、L3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1

32、N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:C

33、L3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1

34、N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:C

35、L3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3【分析】（1）用到 E 景区旅游的人数除以其所占的百分比即可求出参加问卷调查的学生数，用参加问卷调查的学生数减去到A、C、D、E 景区旅游的人数，求出到 B 景区旅游的人数，即可将条形统计图补充完整。（2）先求出到C 景区旅游的人数的百分比，再乘以1000，即可求出答案。18（2012 湖北天门、仙桃、潜江、江汉油田7 分）如图，海中有一小岛B，它的周围15 海里内有暗礁有一货轮以30 海里/时的速度向正北航行半小时后到达C 处，发现 B 岛在它的东北方向问货轮继续向北航行有无触礁的危险？（参考数据：31.721.4，）【答

36、案】解：作 BDAC 于点 D设 BD=x 海里，则在 RtABD 中，xtan30AD，AD=3x。在 RtCBD 中，xtan45CD，CD=x。AC=AD CD=3xx。AC=3012=15，3xx=15，解得 x 21.4。21.4 海里 15 海里。货轮继续向北航行没有触礁的危险。【考点】解直角三角形的应用（方向角问题）。【分析】作 BDAC 于点 D，在 RtABD 和 RtCBD 中求得点 B 到 AC 的距离，从而能判断出有无危险。19（2012 湖北天门、仙桃、潜江、江汉油田8分）小明和小刚玩“石头、剪刀、布”的游戏，每一局游戏双方各自随机做出“石头”、“剪刀”、“布”三种手

37、势的一种，规定“石头”胜“剪刀”，“剪刀”胜“布”，“布”胜“石头”，相同的手势是和局（1）用树形图或列表法计算在一局游戏中两人获胜的概率各是多少？（2）如果两人约定：只要谁率先胜两局，就成了游戏的赢家用树形图或列表法求只进行两局游戏便能确定赢家的概率【答案】解：（1）画树状图得：文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

38、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

39、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

40、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

41、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W

42、3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE

43、9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3总共有9 种等可能情况，每人获胜的情形都是3种，两人获胜的概率都是13。（2）

44、由（1）可知，一局游戏每人胜、负、和的机会均等，都为13任选其中一人的情形可画树状图得：总共有9 种等可能情况，当出现（胜，胜）或（负，负）这两种情形时，赢家产生，两局游戏能确定赢家的概率为：29。【考点】列表法或树状图法，概率，游戏规则的制定。【分析】（1）根据题意画出树状图或列表，由图表求得所有等可能的结果与在一局游戏中两人获胜的情况，利用概率公式即可求得答案。（2）因为由（1）可知，一局游戏每人胜、负、和的机会均等，都为13可画树状图，由树状图求得所有等可能的结果与进行两局游戏便能确定赢家的情况，然后利用概率公式求解即可求得答案。20（2012 湖北天门、仙桃、潜江、江汉油田8分）如图，

45、AB 是 O 的直径，AC 和 BD 是它的两条切线，CO 平分 ACD（1）求证：CD 是 O 的切线；（2）若 AC=2，BC=3，求 AB 的长【答案】（1）证明：过O 点作 OECD，垂足为E，AC 是切线，OAAC。CO 平分 ACD，OECD，ACO=ECO，CAO=CEO，又 OC=OC，ACO ECO（AAS）。OA=OE。CD 是 O 的切线。文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6

46、W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 H

47、E9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6

48、W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 H

49、E9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6

50、W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 HE9X1C2M1N5 ZO5A7T3P6W3文档编码:CL3E4G1P3G2 H

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关键词：: 2022年中考数学卷精析版湖北天门卷 2022 年中数学卷精析版湖北天门

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