书签分享收藏举报版权申诉 / 15

立即下载

当前位置：首页 > 教育专区 > 高考资料 > 2022年全国高考文科数学试题及答案安徽卷 .pdf

2022年全国高考文科数学试题及答案安徽卷 .pdf

上传人：H****o

文档编号：57877550

上传时间：2022-11-06

格式：PDF

页数：15

大小：398.25KB

( 4.5 )

《2022年全国高考文科数学试题及答案安徽卷 .pdf》由会员分享，可在线阅读，更多相关《2022年全国高考文科数学试题及答案安徽卷 .pdf（15页珍藏版）》请在淘文阁 - 分享文档赚钱的网站上搜索。

1、20XX年普通高等学校招生全国统一考试（安徽卷文科）（1）设i是虚数单位，若复数10()3aaRi是纯虚数，则a的值为（）（A）-3（B）-1（C）1（D）3【答案】D【解析】iaiaiaiiaiiiaia)3()3(10)3(109)3(10)3)(3()3(103102，所以 a=3，故选择 D【考点定位】考查纯虚数的概念，及复数的运算，属于简单题.（2）已知|10,2,1,0,1Ax xB，则()RC AB（）（A）2,1（B）2（C）1,0,1（D）0,1【答案】A【解析】A：1x，1|xxACR，2,1)(BACR，所以答案选A【考点定位】考查集合的交集和补集，属于简单题.（3）如图

2、所示，程序据图（算法流程图）的输出结果为（A）34（B）16（C）1112（D）2524【答案】C【解析】21210,0,2ssn；434121,21,4ssn；12116143,43,6ssn1211,8 sn，输出所以答案选择C【考点定位】本题考查算法框图的识别，逻辑思维，属于中等难题.（4）“(21)0 xx”是“0 x”的（A）充分不必要条件（B）必要不充分条件（C）充分必要条件（D）既不充分也不必要条件【答案】B【解析】210,0)12(或xxx，所以答案选择B【考点定位】考查充分条件和必要条件，属于简单题.（5）若某公司从五位大学毕业生甲、乙、丙、丁、戌中录用三人，这五人被录用的机

3、会均等，则甲或乙被录用的概率为文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:

4、CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D

5、6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:

6、CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D

7、6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:

8、CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D

9、6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3（A）23(B)25(C)35（D）910【答案】D【解析】总的可能性有10 种，甲被录用乙没被录用的可能性3 种，乙被录用甲没被录用的可能性3 种，甲乙都被录用的可能性3 种，所以最后的概率333110p【考点定位】考查古典概型的概念，以及对一些常见问题的分析，简单题.（6）直线2550 xy被圆22240 xyxy截得的弦长

10、为（A）1（B）2（C）4（D）4 6【答案】C【解析】圆心(1,2)，圆心到直线的距离1+4-5+5=15d，半径5r，所以最后弦长为222(5)14.【考点定位】考查解析几何初步知识，直线与圆的位置关系，点到直线的距离，简单题.（7）设nS为等差数列na的前n项和，8374,2Sa a，则9a=（A）6（B）4（C）2（D）2【答案】A【解析】188333636978()4420226aaSaaaaaadaad【考点定位】考查等差数列通项公式和前n 项公式的应用，以及数列基本量的求解.(8)函数()yf x的图像如图所示，在区间,a b上可找到(2)n n个不同的数12,nx xx，使文档

11、编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7

12、N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档

13、编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7

14、N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档

15、编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7

16、N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档

17、编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3得1212()()()nnf xf xf xxxx，则n的取值范围为(A)2,3(B)2,3,4(C)3,4(D)3,4,5【答案】B【解析】1111()()00f xf xxx表示11(,()xf x到原点的斜率；1212()()()nnf xf xf xxxx表示1122(,()(,()(,()nnxf xxf xxf x，与原点连线的斜率，而1122(,(

18、)(,()(,()nnxf xxf xxf x，在曲线图像上，故只需考虑经过原点的直线与曲线的交点有几个，很明显有3 个，故选B.【考点定位】考查数学中的转化思想，对函数的图像认识.(9)设ABC的内角,A B C所对边的长分别为,a b c，若2,3sin5sinbcaAB,则角C=(A)3 (B)23(C)34 (D)56【答案】B【解析】BAsin5sin3由正弦定理，所以baba35,53即；因为acb2，所以ac37，文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码

19、:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7

20、D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码

21、:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7

22、D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码

23、:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7

24、D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码

25、:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3212cos222abcbaC，所以32C，答案选择B【考点定位】考查正弦定理和余弦定理，属于中等难度.（1）已知函数32()f xxaxbxc有两个极值点12,x x，若112()f xxx，则关于x的方程23()2()0fxa fxb的不同实根个数为（A）3(B)4(C)5(D)6【答案】A【解析】2()32fxxaxb，12,x x是方程2320 xaxb的两根，由23()2()0f xaf xb，则又两个()f x使得等式成立，11()xf x，211()xxf x，其函数图象如下：如图则有3 个交点，故选A.【考

26、点定位】考查函数零点的概念，以及对嵌套型函数的理解.2.填空题（11）函数21ln(1)1yxx的定义域为 _.【答案】0,1文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V

27、5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5

28、HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V

29、5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5

30、HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V

31、5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5

32、HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3【解析】2110011011xxxxx或，求交集之后得x的取值范围0,1【考点定位】考查函数定义域的求解，对数真数位置大于0，分母不为 0，偶次根式底下大于等于0.（12）若非负数变量,x y满足约束条件124xyxy，则xy的最大值

33、为 _.【答案】4【解析】由题意约束条件的图像如下：当直线经过(4,0)时，404zxy，取得最大值.【考点定位】考查线性规划求最值的问题，要熟练掌握约束条件的图像画法，以及判断何时z取最大.（13）若非零向量,a b满足32abab，则,a b夹角的余弦值为_.【答案】13【解析】等式平方得：2222944ababa b则22244|cosaaba b，即22044 3|cosbb得1cos3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U

34、7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文

35、档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U

36、7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文

37、档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U

38、7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文

39、档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U

40、7N7D6E2 ZE8O2B3V5X3【考点定位】考查向量模长，向量数量积的运算，向量最基本的化简.（14）定义在R上的函数()f x满足(1)2()f xf x.若当01x时。()(1)f xxx，则当10 x时，()f x=_.【答案】(1)()2x xf x【解析】当10 x，则011x，故(1)(1)(11)(1)f xxxx x又(1)2()f xf x，所以(1)()2x xf x【考点定位】考查抽象函数解析式的求解.（15）如图，正方体1111ABCDABC D的棱长为1，P为BC的中点，Q为线段1CC上的动点，过点,A P Q的平面截该正方体所得的截面记为S，则下列命题正确的是

41、（写出所有正确命题的编号）。当102CQ时，S为四边形当12CQ时，S为等腰梯形当34CQ时，S与11C D的交点R满足113C R当314CQ时，S为六边形当1CQ时，S的面积为62文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2

42、Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2

43、 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2

44、Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2

45、 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2

46、Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2

47、 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3【答案】【解析】（1）12CQ，S等腰梯形，正确，图如下：（2）1CQ，S是菱形，面积为36222，正确，图如下：（3）34CQ，画图如下：113C R，正确（4）314CQ，

48、如图是五边形，不正确；文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z

49、9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2

50、ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z9I3A1H5 HB2U7N7D6E2 ZE8O2B3V5X3文档编码:CJ2Z

文档加载中……请稍候！
如果长时间未打开，您也可以点击刷新试试。

下载文档到电脑，查找使用更方便

4.3 金币

版权申诉 word格式文档无特别注明外均可编辑修改；预览文档经过压缩，下载后原文更清晰！ 立即下载

配套讲稿：: 如PPT文件的首页显示word图标，表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
特殊限制：: 部分文档作品中含有的国旗、国徽等图片，仅作为作品整体效果示例展示，禁止商用。设计者仅对作品中独创性部分享有著作权。
关键词：: 2022年全国高考文科数学试题及答案安徽卷 2022 全国高考文科数学试题答案安徽

淘文阁 - 分享文档赚钱的网站所有资源均是用户自行上传分享，仅供网友学习交流，未经上传用户书面授权，请勿作他用。

限制150内

关于本文

本文标题：2022年全国高考文科数学试题及答案安徽卷 .pdf
链接地址：https://www.taowenge.com/p-57877550.html