2022年上海市中考数学试题及解析 .pdf

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1、2018 年上海市初中毕业统一学业考试数学试卷（满分 150 分，考试时间 100 分钟）一、选择题（本大题共6 题，每题 4 分，满分 24 分。下列各题的四个选项中，有且只有一个选项是正确的）1（4 分）下列计算的结果是（）A4 B3 C 2 D 2（4 分）下列对一元二次方程x2+x3=0 根的情况的判断，正确的是（）A有两个不相等实数根B有两个相等实数根C有且只有一个实数根D没有实数根3（4 分）下列对二次函数y=x2x 的图象的描述，正确的是（）A开口向下B对称轴是 y 轴C经过原点D 在对称轴右侧部分是下降的4（4 分）据统计，某住宅楼30 户居民五月份最后一周每天实行垃圾分类的户

2、数依次是：27，30，29，25，26，28，29，那么这组数据的中位数和众数分别是（）A25 和 30 B25 和 29 C28 和 30 D28 和 295（4 分）已知平行四边形ABCD，下列条件中，不能判定这个平行四边形为矩形的是（）AA=B BA=C CAC=BD DAB BC6（4 分）如图，已知 POQ=30，点 A、B在射线 OQ 上（点 A在点 O、B之间），半径长为 2 的A与直线 OP相切，半径长为 3 的B与A相交，那么 OB的取值范围是（）A5OB 9 B4OB 9 C 3OB 7 D2OB 7二、填空题（本大题共12 题，每题 4 分，满分 48分）7（4 分）8

3、的立方根是8（4 分）计算：（a+1）2a2=9（4 分）方程组的解是10（4 分）某商品原价为 a 元，如果按原价的八折销售，那么售价是元（用含字母 a 的代数式表示）11（4 分）已知反比例函数 y=（k 是常数，k1）的图象有一支在第二象限，那么 k 的取值范围是12（4 分）某校学生自主建立了一个学习用品义卖平台，已知九年级200 名学生义卖所得金额的频数分布直方图如图所示，那么2030 元这个小组的组频率是13（4 分）从，这三个数中选一个数，选出的这个数是无理数的概率为14（4 分）如果一次函数 y=kx+3（k 是常数，k0）的图象经过点（1，0），那么 y 的值随 x 的增大而

4、（填“增大”或“减小”）15（4 分）如图，已知平行四边形ABCD，E 是边 BC的中点，联结 DE并延长，与 AB的延长线交于点 F设=，=那么向量用向量、表示为文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5

5、A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6

6、E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6

7、K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4

8、L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ

9、2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O

10、10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O316

11、（4 分）通过画出多边形的对角线，可以把多边形内角和问题转化为三角形内角和问题 如果从某个多边形的一个顶点出发的对角线共有2 条，那么该多边形的内角和是度17（4 分）如图，已知正方形DEFG 的顶点 D、E在ABC的边 BC上，顶点 G、F分别在边AB、AC 上如果BC=4，ABC的面积是6，那么这个正方形的边长是18（4 分）对于一个位置确定的图形，如果它的所有点都在一个水平放置的矩形内部或边上，且该图形与矩形的每条边都至少有一个公共点（如图1），那么这个矩形水平方向的边长称为该图形的宽，铅锤方向的边长称为该矩形的高如图 2，菱形 ABCD 的边长为 1，边 AB水平放置如果该菱形的高是宽

12、的，那么它的宽的值是三、解答题（本大题共7 题，满分 78 分）19（10分）解不等式组：，并把解集在数轴上表示出来20（10分）先化简，再求值：（），其中 a=21（10分）如图，已知 ABC中，AB=BC=5，tan ABC=（1）求边 AC的长；（2）设边 BC的垂直平分线与边AB的交点为 D，求的值文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6

13、K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4

14、L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ

15、2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O

16、10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档

17、编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5

18、A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6

19、E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O322（10 分）一辆汽车在某次行驶过程中，油箱中的剩余油量y（升）与行驶路程 x（千米）之间是一次函数关系，其部分图象如图所示（1）求 y 关于 x 的函数关系式；（不需要写定义域）（2）已知当油箱中的剩余油量为8 升时，该汽车会开始提示加油，在此次行驶过程中，行驶了500 千米时，司机发现离前方最近的加油站有30 千米的路程，在开往该加油站的途中，汽车开始提示加油，这时离加油站的路程是多少千米？23（12 分）已知：如图，正方形ABCD 中，P是边 BC

20、上一点，BE AP，DF AP，垂足分别是点 E、F（1）求证：EF=AE BE；（2）联结 BF，如课=求证：EF=EP 24（12分）在平面直角坐标系xOy中（如图）已知抛物线 y=x2+bx+c 经过点 A（1，0）和点 B（0，），顶点为 C，点 D在其对称轴上且位于点C下方，将线段 DC绕点 D按顺时针方向旋转90，点 C落在抛物线上的点P处（1）求这条抛物线的表达式；（2）求线段 CD的长；文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q

21、6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX

22、6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K

23、4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 Z

24、J2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7

25、O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文

26、档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD

27、5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3（3）将抛物线平移，使其顶点 C移到原点 O的位置，这时点 P落在点 E的位置，如果点 M在 y 轴上，且以 O、D、E、M为顶点的四边形面积为8，求点 M的坐标25（14分）已知 O的直径 AB=2，弦 AC与弦 BD交于点 E且 OD AC，垂足为点 F（1）如图 1，如果 AC=BD，求弦 AC的长；（2）如图 2，如果 E为弦 BD的中点，求 ABD的

28、余切值；（3）联结 BC、CD、DA，如果 BC是O的内接正 n 边形的一边，CD是O的内接正（n+4）边形的一边，求 ACD 的面积文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D

29、9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10

30、 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4

31、T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O

32、3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:

33、CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q

34、5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O32018年上海市中考数学试卷参考答

35、案与试题解析一、选择题（本大题共6 题，每题 4 分，满分 24 分。下列各题的四个选项中，有且只有一个选项是正确的）1（4 分）下列计算的结果是（）A4 B3 C 2 D【分析】先化简，再合并同类项即可求解【解答】解：=3=2故选：C2（4 分）下列对一元二次方程x2+x3=0 根的情况的判断，正确的是（）A有两个不相等实数根B有两个相等实数根C有且只有一个实数根D没有实数根【分析】根据方程的系数结合根的判别式，即可得出=130，进而即可得出方程 x2+x3=0有两个不相等的实数根【解答】解：a=1，b=1，c=3，=b24ac=124（1）（3）=130，方程 x2+x3=0有两个不相等的

36、实数根故选：A3（4 分）下列对二次函数y=x2x 的图象的描述，正确的是（）A开口向下B对称轴是 y 轴C经过原点D 在对称轴右侧部分是下降的【分析】A、由 a=10，可得出抛物线开口向上，选项A不正确；B、根据二次函数的性质可得出抛物线的对称轴为直线x=，选项 B不正确；C、代入 x=0 求出 y 值，由此可得出抛物线经过原点，选项C正确；文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文

37、档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD

38、5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q

39、6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX

40、6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K

41、4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 Z

42、J2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7

43、O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3D、由 a=10 及抛物线对称轴为直线x=，利用二次函数的性质，可得出当x时，y 随 x 值的增大而增大，选项D不正确综上即可得出结论【解答】解：A、a=10，抛物线开口向上，选项A不正确；B、=，抛物线的对称轴为直线x=，选项 B不正确；C、当 x=0 时，y=x2x=0，抛物线经过原点，选项C正确；D、a0，抛物线的对称轴为直线x=，当 x时，y 随 x 值的增大而增大，选项D不正确故选：C4（4 分）据统计，某住

44、宅楼30 户居民五月份最后一周每天实行垃圾分类的户数依次是：27，30，29，25，26，28，29，那么这组数据的中位数和众数分别是（）A25 和 30 B25 和 29 C28 和 30 D28 和 29【分析】根据中位数和众数的概念解答【解答】解：对这组数据重新排列顺序得，25，26，27，28，29，29，30，处于最中间是数是28，这组数据的中位数是28，在这组数据中，29出现的次数最多，这组数据的众数是29，故选：D5（4 分）已知平行四边形ABCD，下列条件中，不能判定这个平行四边形为矩形的是（）文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3

45、文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:C

46、D5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5

47、Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 H

48、X6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9

49、K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10

50、ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T7O10O3文档编码:CD5A6Q5Q6E2 HX6K3D9K4L10 ZJ2J4T