2022年人教A版数学必修一2.1.2《指数函数及其性质》强化作业 .pdf
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1、名师精编优秀教案河北省衡水中学高一数学必修一强化作业:2.1.2 指数函数及其性质(第二课时)一、选择题1.函数121xy的定义域为()AR B,C 0,D 0|xRxx且2.函数2)21(xy的定义域为()A.1,B.)1,(C.),1(D.,13当时,函数xay)1(的值总大于,则的取值范围是()A、01a B、1aC、20aD、2a4.函数 y=121x的值域是()A、(-1,)B、(-,0)(0,+)C、(-1,+)D、(-,-1)(0,+)5.若指数函数xay在 1,1 上的最大值与最小值的差是1,则底数a等于()A251B251C251D2156.下列各不等式中正确的是()A、(1
2、2)23(12)13B、233222C、(12)32223D、(12)322237.若指数函数xay在 0,1上的最大值与最小值的和是3,则底数a等于()A251B12C 2 D215二填空 题8.对于正数满足a0.1a0.2,则的取值范围是。9.对于,1)1()(xaxf恒成立,则的取值范围是。10.比较大小:1.50.90.4812314,8,2yyy。名师精编优秀教案11.函数11011xy的定义域为。三解答题12.求下列函数的定义域:126)2(;10)1(211xxxxyy13.求下列函数的值域:10264)2(;1212)1(xxxxyy14.设20 x,求函数524121xxy的
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7、码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7
8、 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5
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10、文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V2B7 HH10N9V2Y8R5 ZK8X2W9Y8N7文档编码:CS4M6A1V
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