2022年-普通高等学校招生全国统一考试理科数学试题及答案 .pdf

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1、20XX 年普通高等学校招生全国统一考试(全国大纲卷)_ 理科数学试题及答案20XX年高考题全国卷II 数学试题理科全解全析莘县实验高中赵常举邮编：252400 科目：数学 试卷名称 20XX 年普通高等学校招生全国统一考试全国卷 II(理科)知识点检索号新课标题目及解析（1）复数，z 为 z 的共轭复数，则（A）（B）（C）i 54【思路点拨】先求出的z 共轭复数,然后利用复数的运算法则计算即可。【精讲精析】选（2）函数的反函数为（D）2i x2（A）（C）4 x2(x 0)（B）（D）【思路点拨】先反解用y 表示 x,注意要求出y 的取值范围，它是反函数的定义域。y2【精讲精析】选B.在函

2、数中，且反解 x 得，所以 4 x2 的反函数为（3）下面四个条件中，使ab 成立的充分而不必要的条件是2233（A）a（B）a（C）ab（D）ab 24【思路点拨】本题要把充要条件的概念搞清，注意寻找的是通过选项能推出 ab，而由 ab推不出选项的选项.【精讲精析】选A.即寻找命题 P使推不出 P，逐项验证可选 A。（4）设 Sn为等差数列的前 n 项和，若，公差，则（A）8（B）7（C）6（D）5【思路点拨】思路一：直接利用前n 项和公式建立关于k 的方程解之即可。思路二：利用直接利用通项公式即可求解，运算稍简。【精讲精析】选D.5.（5）设函数0)，将的图像向右平移文档编码:CR3I10

3、L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2

4、 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8

5、I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B1

6、0 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S

7、8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A

8、9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:

9、CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9文档编码:CR3I10L1N3S2 HK2U8I5F3B10 ZX9S8C3J5A9所得的图像与原图像重合，则的最小值等于（A）个单位长度后，31（B）3（C）6（D）9 3【思路点拨】此题理解好三角函数周期的概念至关重要，将的图像向右平个单位长度后，所得的图像与原图像重合

10、，说明了是此函数周期的整数倍。33 解得，令，即得【精讲精析】选 C.由题移(6)已知直二面角，点为垂足，为垂足若 AB=2，AC=BD=1，则 D到平面 ABC的距离等于(A)(B)(C)3 3 3【思路点拨】本题关键是找出或做出点D到平面 ABC的距离 DE，根据面面垂直的性质不难证明平面，进而平面平面 ABC,所以过 D作于 E，则 DE就是要求的距离。40【精讲精析】选C.如图，作于 E，由为直二面角，得平面，进而，又，于是平面 ABC，文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6

11、W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L1

12、0G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编

13、码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10

14、J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6

15、A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6

16、P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9

17、U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2故 DE为 D到平面 ABC的距离。在BCD中，利用等面积法得(7)某同学有同样的画册2 本，同样的集邮册3 本，从中取出4 本赠送给 4 位朋友每位朋友1 本，则不同的赠送方法共有(A)4 种(B)10种(C)18 种(D)20 种45【思路点拨】本题要注意画册相同，集邮册相同，这是重复元素，不能简单按照排列知识来

18、铸。所以要分类进行求解。1【精讲精析】选B.分两类：取出的1 本画册，3 本集邮册，此时赠送方法有种；2 取出的 2 本画册，2 本集邮册，此时赠送方法有种。总的赠送方法有10 种。(8)曲线 y=e(A)文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5

19、 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4

20、H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G

21、2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:

22、CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5

23、N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6

24、 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6

25、Z7T9U5 ZI6W4H5L10G2+1 在点(0，2)处的切线与直线y=0 和 y=x 围成的三角形的面积为112(B)(C)(D)1 323【思路点拨】利用导数求出点（0，2）切线方程然后分别求出与直线y=0 与 y=x 的交53 点问题即可解决。【精讲精析】选切线方程是：在直角坐标系中作出示意图，即得(9)设 f(x)是周期为 2 的奇函数，当0 x1 时，则-121。233 5 2 1111 4242 6【思路点拨】解本题的关键是把通过周期性和奇偶性把自变量上进行求值。【精讲精析】选A.5 文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:

26、CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5

27、N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6

28、 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6

29、Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5

30、 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4

31、H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G

32、2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2转化到区间 0,12 先利用周期性，再利用奇偶性得2 5212121.2(10)已知抛物线 C：的焦点为 F，直线与 C交于 A，B两点则34(A)3443 5555【思路点拨】方程联立求出A、B两点后转化为解三角形问题。【精讲精析】选 D.联立，消 y 得，解

33、得4.不妨设 A在 x 轴上方，于是A，B的坐标分别为(4,4),(1,-2),可求，利用余弦定理文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G

34、2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:

35、CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5

36、N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6

37、 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6

38、Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5

39、 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2(11)已知平面 截一球面得圆M，过圆心 M且与 成 60 二面角的平

40、面 截该球面得圆N.若该球面的半径为4，圆 M的面积为，则圆 N的面积为【思路点拨】做出如图所示的图示，问题即可解决。【精讲精析】选B.42 作示意图如，由圆M的面积为，易得 0 中，。故设向量 a,b,c满足，则|c|的最大值 2 等于【思路点拨】本题按照题目要求构造出如右图所示的几何图形，然后分析观察不难得到当线段AC为直径时，|c|最大.【精讲精析】选A.如图，构造文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5

41、 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4

42、H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G

43、2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:

44、CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5

45、N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6

46、 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6

47、Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2，所以 A、B、C、D四点共圆，分析可知当线段AC为直径时，|c|最大，最大值为2.45 的二项展开式中，x 的系数与 x 的系数之差为:.209【思路点拨】解本题一个掌握展开式的通项公式，另一个要注意r218【精讲精析】0.由的系数为 C20,而(20 得 x 的系数为 C209(14)已知 a(，sin tan2=2【思路点拨】本题涉及到同角三角函数关系式,先由正弦值求出余弦值一定要注意

48、角的范围，再求出正切值，最后利用正切函数的倍角公式即可求解。文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6

49、HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z

50、7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5 ZI6W4H5L10G2文档编码:CL10J5N6Y6A6 HV6P6Z7T9U5