2022年中考数学试卷-锐角三角函数与特殊角 .pdf

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1、锐角三角函数与特殊角一、选择题1,（2015?淄博第 7 题,4 分）若锐角满足 cos 且 tan ，则 的范围是（）A 30 45 B 45 60 C 60 90 D 30 60考点：锐角三角函数的增减性.专题：应用题分析：先由特殊角的三角函数值及余弦函数随锐角的增大而减小，得出45 90；再由特殊角的三角函数值及正切函数随锐角的增大而增大，得出 0 60；从而得出45 60 解答：解：是锐角，cos 0，cos，0cos，又cos90=0，cos45=，4590；是锐角，tan 0，tan ，0tan ，又 tan0=0，tan60=，0 60；故 45 60 故选 B点评：本题主要考查

2、了余弦函数、正切函数的增减性与特殊角的余弦函数、正切函数值，熟记特殊角的三角函数值和了解锐角三角函数的增减性是解题的关键2.（2015?四川南充,第 5 题 3 分）如图，一艘海轮位于灯塔P 的北偏东方向55，距离灯塔为 2 海里的点A 处如果海轮沿正南方向航行到灯塔的正东位置，海轮航行的距离AB 长是（）（A）2 海里（B）海里（C）海里（D）海里【答案】C【解析】试题分析：根据题意可得P AB=55，则 cosPAB=，即 cos55=，则 AB=2 cos55.考点：三角函数的应用.3.（2015?浙江湖州，第8 题 3 分）如图，以点O 为圆心的两个圆中，大圆的弦AB 切小圆于点 C，

3、OA 交小圆于点D，若 OD=2，tanOAB=，则 AB 的长是()A.4B.2C.8 D.4【答案】C.文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5

4、文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U

5、1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B1

6、0C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9

7、F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P

8、7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1

9、B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5考点：切线的性质定理；锐角三角函数；垂径定理.5.（2015?四川乐山,第 7 题 3 分）如图，已知ABC 的三个顶点均在格点上，则cosA的值为（）AB

10、CD【答案】D考点：1锐角三角函数的定义；2勾股定理；3勾股定理的逆定理；4格型文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1

11、T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10

12、C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F

13、5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7

14、U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B

15、10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D

16、9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F56.（2015?山东聊城,第 15 题 3 分）如图，在 ABC 中，C=90，A=30，BD 是ABC 的平分线若AB=6，则点 D 到 AB 的距离是考点：角平分线的性质.分析：求

17、出 ABC，求出 DBC，根据含30 度角的直角三角形性质求出BC，CD，问题即可求出解答：解：C=90，A=30，ABC=180 30 90=60，BD 是 ABC 的平分线，DBC=ABC=30，BC=AB=3，CD=BC?tan30=3=，BD 是 ABC 的平分线，又 角平线上点到角两边距离相等，点 D 到 AB 的距离=CD=，故答案为：点评：本题考查了角平分线上的点到角的两边的距离相等的性质，熟记性质是解题的关键7,（3 分）（2015 山东威海，第2 题 3 分）如图，在ABC 中，ACB=90，ABC=26，BC=5若用科学计算器求边AC 的长，则下列按键顺序正确的是（）AB

18、CD文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P

19、7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1

20、B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6

21、D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P

22、4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7

23、V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8

24、X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5考点：计算器 三角函数.分析：根据正切函数的定义，可得tan B=，根据计算器的应用，可得答案解答：接：由 tanB=，得AC=BC?tanB=5 tan26故选：D点评：本题考查了计算器，利用了锐角三角函数，计算器的应用，熟练应用计算器是解题关键8（4 分）

25、（2015?山东日照，第 10 题 4 分）如图，在直角BAD 中，延长斜边BD 到点C，使 DC=BD，连接 AC，若 tanB=，则 tanCAD 的值（）ABCD考点：解直角三角形.分析：延长 AD，过点 C 作 CEAD，垂足为 E，由 tanB=，即=，设 AD=5x，则 AB=3x，然后可证明 CDE BDA，然后相似三角形的对应边成比例可得：，进而可得 CE=x，DE=，从而可求tanCAD=解答：解：如图，延长AD，过点 C 作 CE AD，垂足为E，tanB=，即=，设 AD=5x，则 AB=3x，CDE=BDA，CED=BAD，CDE BDA，文档编码:CD5P4P7U1T

26、3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C

27、3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5

28、文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U

29、1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B1

30、0C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9

31、F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P

32、7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5CE=x，DE=，AE=，tanCAD=故选 D点评：本题考查了锐角三角函数的定义，相似三角形的判定和性质以及直角三角形的性质，是基础知识要熟练掌握，解题的关键是：正确添加辅助线，将CAD 放在直角三角形中9（2015?甘肃兰州,第 4 题，4 分）如图，ABC 中，B=90，BC=2AB，则

33、 cosA=A.25B.21C.552D.55【答案】D【考点解剖】本题考查了直角三角形中角的三角函数值的定义【思路点拔】直角三角形中，某锐角的余弦值等于夹这个角的那条直角边与斜边之比【解答过程】RtABC 中，AC2=AB2+BC2=AB2+(2AB)2=5 AB2，AC=5AB，则 cosA=555ABABACAB，选 D【解题策略】一般地说，在涉及到某个锐角的三角函数值时，只要将之放到直角三角形中去，那么问题往往不难解决。在直角三角形中，我们将夹角的那条直角边称为邻边，角 所对的那条边称为对边，那么文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码

34、:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3

35、HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3

36、ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档

37、编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T

38、3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C

39、3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5

40、文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5角阿尔法的各三角函数值分别为斜边对边sin，斜边邻边cos，邻边对边tan。如果原题没有图，那么可以自己在草稿纸上画一个示意图；如果是在斜三角形中，那么可以根据实际情况构造一个直角三角形出来，将问题转化到直角三角形中去解决。【题目星级】10(2015?江苏无锡,第 7 题 2 分)tan45 的值为（）AB1 CD考点：特殊角的三角函数值分析：根据 4

41、5 角这个特殊角的三角函数值，可得tan45=1，据此解答即可解答：解：tan45=1，即 tan45 的值为 1故选：B点评：此题主要考查了特殊角的三角函数值，要熟练掌握，解答此类问题的关键是牢记30、45、60 角的各种三角函数值二.填空题1（2015?甘肃武威,第 15 题 3 分）已知 、均为锐角，且满足|sin|+=0，则 +=75 考点：特殊角的三角函数值；非负数的性质：绝对值；非负数的性质：算术平方根分析：根据非负数的性质求出sin 、tan 的值，然后根据特殊角的三角函数值求出两个角的度数解答：解：|sin|+=0，文档编码:CD5P4P7U1T3 HO8H7V1B10C3 Z

42、L4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编

43、码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3

44、 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3

45、 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文

46、档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1

47、T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10

48、C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5sin =，tan =1，=30，=45，则 +=30+45=75 故答案为：75 点评：本题考查了特殊角的三角函数值，解答本题的关键是掌握几个特殊角的三角函数值2.（2015?山东临沂,第 17 题 3 分）如图，在ABCD 中，连接BD，,，则ABCD 的面积是 _.【答案】考点：勾股定理，平行四边形的面积3.（2015

49、?四川省内江市，第23 题，6 分）在平面直角坐标系xOy 中，过点P（0，2）作直线 l：y=x+b（b 为常数且b 2）的垂线，垂足为点Q，则 tanOPQ=考点：一次函数图象上点的坐标特征；解直角三角形.分析：设直线 l 与坐标轴的交点分别为A、B，根据三角形内角和定理求得 OAB=OPQ，根据一次函数图象上点的坐标特征求得tanOAB=，进而就可求得解答：解：如图，设直线l 与坐标轴的交点分别为A、B，AOB=PQB=90，ABO=PBQ，文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4

50、M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码:CD5P4P7U1T3 HO8H7V1B10C3 ZL4M8X6D9F5文档编码: