2022年人教A版高中数学必修三1.2.3《循环语句》教案2 .pdf

《2022年人教A版高中数学必修三1.2.3《循环语句》教案2 .pdf》由会员分享，可在线阅读，更多相关《2022年人教A版高中数学必修三1.2.3《循环语句》教案2 .pdf（5页珍藏版）》请在淘文阁 - 分享文档赚钱的网站上搜索。

1、名师精编优秀教案湖南省蓝山二中高一数学1.2.3 循环语句教案新人教 A版必修3 一 教材分析1 教材背景算法是新课标教材新增加的内容，从古至今算法思想都能在解决问题中得到体现，他不仅是数学及应用的重要组成部分，也是信息技术的重要基础。随着信息技术的发展，算法思想已成为数学素养的一部分,所以学习算法是非常必要的。2 本节课的地位及作用这部分的学习与前面的循环结构有密切的关系,也为后面学习算法案例打下良好的基础.二 重点难点重点:正确理解循环语句的作用难点:准确写出循环语句的两种形式三 目标分析1 知识目标教学目标（1）正确理解循环语句的结构；（2）让学生充分地感知、体验应用计算机解决数学问题的

2、方法；（3）通过实例，使学生理解循环语句的表示方法、结构和用法，进一步体会算法的基本思想2 能力目标发展学生有条理的思考与表达能力，培养学生的逻辑思维能力.3 情感目标通过体验算法表述的过程，培养学生的创新意识，认识到计算机是人类征服自然的一各有力工具，进一步提高探索、认识世界的能力.四 学情分析算法这部分的使用性很强，与日常生活联系紧密，虽然是新引入的章节，但很容易激发学生的学习兴趣。在教师的引导下，通过多媒体辅助教学，学生比较容易掌握本节课的内容。五 教法分析采用“问题探究式”教学法，以多媒体为辅助手段，让学生主动发现问题、分析问题、解决问题，培养学生的探究论证、逻辑思维能力。六 教学设计

3、1 新课引入顺序结构的框图可以用输入语句,输出语句,赋值语句来表示,条件结构用条件语句表示,循环结构我们必须用循环语句表示.2 新课教学问题 1:直到型循环结构的程序框图是什么？结论:该循环结构对应的循环语句的一般格式设定为：名师精编优秀教案问题 2:你能说明计算机在执行上述语句时是怎样工作的吗？先执行一次DO和 UNTIL 之间的循环体，再对UNTIL 后的条件进行判断.如果条件不符合，则继续执行循环体；然后再检查上述条件，如果条件仍不符合，则再次执行循环体，直到条件符合为止.这时，计算机将不执行循环体，而执行UNTIL 语句之后的语句.问题 3:计算 1+2+3+100 的值有如下算法:第

4、一步，令i=1，S=0.第二步，计算S+i，仍用 S表示.第三步，计算 i+1，仍用 i 表示.第四步，判断i100 是否成立.若是，则输出S，结束算法；否则，返回第二步.你能利 用 UNTIL语句写出这个算法对应的程序吗？解答:问题 4:在下面的程序运行中，计算机输出的结果是多少？问题 5:当型循环结构的程序框图是什么？结论:该循环结构对应的循环语句的一般格式设定为：WHILE条件循环体WEND文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N

5、5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G

6、8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q

7、3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W

8、5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T

9、10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码

10、:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P

11、5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10文档编码:CE10P5H8U8N5 HH8G8A4U6Q3 ZF8W5E2C1T10名师精编优秀教案问题 6:你能说明计算机在执行上述语句时是怎样工作的吗？先对条件进行判断，如果条件符合，则执行WHILE和 WEND 之间的循环体；然后再检查上述条件，如果条件仍符合，则再次执行循环体，直到某一次条件不符合为止.这时，计算机将不执行循环体，而执行WEND 语句之后的语句.问题 7:计算 1+2+3+100 的值又有如下算法:第一步，令i=1，S=0.

12、第二步，若i 100 成立，则执行第三步；否则，输出S，结束算法.第三步，S=S+i.第四步，i=i+1，返回第二步.你能利用WHILE语句写出这个算法对应的程序吗？解答:问题 8:阅读下面的程序，你能说明它是一个什么问题的算法吗？结论:求满足 x21000 的所有正整数x 的值.3.例题讲解例 1 已知函数y=x3+3x2-24x+30，写出连续输入自变量的11 个取值，分别输出相应的函数值的程序.算法分析:第一步，输入自变量x 的值.第二步，计算y=x3+3x2-24x+30.第三步，输出y.第四步，记录输入次数.第五步，判断输入的次数是否大于11.若是，则结束算法；否则，返回第一步.i=

13、1S=0WHILE i=100S=S+ii=i+1WENDPRINT SEND x=1WHILE x211？结束是否n=1DOINPUT xy=x3+3*x2-24*x+30PRINT yn=n+1LOOP UNTILn11END文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L1

14、0 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V

15、4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N

16、8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A

17、7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S

18、3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:

19、CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T

20、4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3名师精编优秀教案例 2 将用“二分法”求方程的近似解的程序框图转化为相应的程序.4.课堂练习：1.教材 P32面 1、2 题2.下边程序运行后输出的结果为（D）A.50 B.25 C.5 D.0 3.下边程序执行后输出的结果为（D）A.-1 B.0 C.1 D.2 4.山东执行右边的程序框图，若p=0.8,则输出的n=_4_ .220(0)xx开始结束f(a)f(m)0?a=mb=m是否|a-b|d 或 f(m)=0?输出 m是否f(x)=x2-2输入精确度d和初始值 a，b2abmENDINPUT“a，b，d=”；a，b，dDOm

21、=(a+b)/2g=a2-2f=m2-2IFg*f 0 THENb=mELSEa=mEND IFLOOP UNTILABS(a-b)d OR f=0PRINT m输入 pn=1,S=0Sp?nSS21开始输出 n否是a=0 j=1WHILE j=5a=(a+j)MOD 5j=j+1WENDPRINT aENDn=5s=0WHILE s15S=s+nn=n1WENDPRINT nEND文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V

22、4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N

23、8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A

24、7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S

25、3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:

26、CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T

27、4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L1

28、0 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3名师精编优秀教案5.阅读图 4 的程序框图，若输入4,3,mn则输出a 1 2 ，i 3 。（注：框图中的赋值符号“”也可以写成“”或“:”）5.课堂小结：1.两种循环语句源于两种循环结构，直到型循环语句先执行循环体，再判断条件；当型循环语句先判断条件，再执行循环体.2.直到型循环语句在条件不符合时再执行循环体，当型循环语句在条件符合时再执行循环体.6.课后作业习案与学案开始输入

29、 m，ni=1a=m in整除 a?是输出 a，i结束i=i+1否文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10

30、L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ

31、1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J

32、4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB

33、6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A

34、1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3文档编码:CP8I6T4Y10L10 HJ1V4R3J4N8 ZB6A7P1A1S3