2022年完整word版,《自动控制原理》试卷及答案.docx
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1、精选学习资料 - - - - - - - - - AUTOMATIC CONTROL THEOREM 1 Derive the transfer function and the differential equation of the electric network shown in Fig.1. 12% R1 C1 V1S C2 R2 V2S Fig.1 Consider the system shown in Fig.2. Obtain the closed-loop transfer function C S , E S . (12%)R S R S G4 R E G1 G2 G3
2、C H2 H1 Fig.2 The characteristic equation is given 1GHSS35S26KS10K0. Discuss the distribution of the closed-loop poles. 16% There are 3 roots on the LHP There are 2 roots on the LHP There are 1 roots on the LHP There are no roots on the LHP . K=. Consider a unity-feedback control system whose open-l
3、oop transfer function is GS04.S01. Obtain the response to a unit-step input. What is the rise time for S S.6this system. What is the maximum overshoot. (10%)名师归纳总结 - - - - - - -第 1 页,共 29 页精选学习资料 - - - - - - - - - 5. Sketch the root-locus plot for the system GHSSK1 . The gain K is Sassumed to be pos
4、itive. Determine the breakaway point and K value. Determine the value of K at which root loci cross the imaginary axis. Discuss the stability. 12% r2t, n1 . Determine 6. The system block diagram is shown Fig.3. Suppose the value of K to ensure e SS1. 12% N R E SK2S43C SFig.3 7. Consider the system w
5、ith the following open-loop transfer function: GHSS T 1SKT2S1 . Draw Nyquist diagrams. Determine the 1 stability of the system for two cases, the gain K is small, K is large. 12% 8. Sketch the Bode diagram of the system shown in Fig.4. 14% RS S32SS2 10 CS S5 SFig.4 名师归纳总结 - - - - - - -第 2 页,共 29 页精选
6、学习资料 - - - - - - - - - V2S R 1R 2C 1C2SC 1C2V 1S R2C1C2SC 1CS 1G1 G2H1G 1G2G3G 1G42G3H2G4H2R S G 1 G2G3G 1G4G 0K6 K0 K6 no answer the breakaway point is 1 and 1/3; k=4/27 The imaginary axis S= j; K=2 名师归纳总结 .3 5KS 7 . 5S1 31 . 62 S 10 1.S S1 .3 481 34 . 811 S1第 3 页,共 29 页GH0 . 31682 . 54- - - - - -
7、-精选学习资料 - - - - - - - - - AUTOMATIC CONTROL THEOREM 2 Derive the transfer function and the differential equation of the electric network shown in Fig.1. 12% V1S R1 R1 C2 V2S Fig.1 C1 Consider the equation group shown in Equation.1. Draw block diagram and obtain the closed-loop transfer function CRS
8、. (16% )S SX1S G 1S R S G 1S G 7 S G 8S CEquation.1 X2S G 2S X1S G 6S X3S X3S X2S CS G 5S G 3S C S G 4S X3 S Use Rouths criterion to determine the number of roots in the right-half S plane for the equation 1GHS S53S428S3226S2600S4000. Analyze stability.(12% ) Determine the range of K value ,when r1t
9、2t, e SS0 .5. (12% )R E 3 S 24 SKC S 2 S2Fig.2 名师归纳总结 - - - - - - -第 4 页,共 29 页精选学习资料 - - - - - - - - - Fig.3 shows a unity-feedback control system. By sketching the Nyquist diagram of the system, determine the maximum value of K consistent with stability, and check the result using Rouths criterion
10、. Sketch the root-locus for the system(20%)R S S2K5 R C Fig.3 E 4 SSketch root-locus diagram.(18% )Im Re Im Re Im Re Im Im Im Re Re Re Determine the transfer function. Assume a minimum-phase transfer function.(10% )LdB 0 20 0 20 40 -60 40 30 20 名师归纳总结 5 0.1 1 2 3 4 第 5 页,共 29 页- - - - - - -精选学习资料 -
11、- - - - - - - - V2S R 1C1R 2C2S2R 11R 2C2R 1C2S1V 1S C 1CS 1G2G 3G6G3G 1G2G3G42G3G4G7G8R S G4G 5G1G There are 4 roots in the left-half S plane, 2 roots on the imaginary axes, 0 root in the RSP. The system is unstable. 8K20K=20 名师归纳总结 GHS S1 31 . 62 S 10 1.S S1 .3 481 34 . 811 S1第 6 页,共 29 页0 . 31682
12、 . 54- - - - - - -精选学习资料 - - - - - - - - - AUTOMATIC CONTROL THEOREM 3 List the major advantages and disadvantages of open-loop control systems. 12% Derive the transfer function and the differential equation of the electric network shown in Fig.1.(16% )C1 U1 R1 R2 U2 Fig.1 C2 Consider the system sho
13、wn in Fig.2. Obtain the closed-loop transfer functionCS, ES , CS . (12%)G5 C R SRS P SR E G1 P G4 G2 G3 H2 H1 Fig.2 H3 The characteristic equation is given 1GHS S33S22 S200. Discuss the distribution of the closed-loop poles. 16% 5. Sketch the root-locus plot for the system GHSS K1 . The gain K is Sa
14、ssumed to be positive. Determine the breakaway point and K value. Determine the value of K at which root loci cross the imaginary axis. 名师归纳总结 Discuss the stability. 14% 第 7 页,共 29 页- - - - - - -精选学习资料 - - - - - - - - - 6. The system block diagram is shown Fig.3. G1SK2, G2S43 . Suppose Sr2t, n1. Det
15、ermine the value of K to ensure e SS1. 15% R E N C G1 G2 Fig.3 7. Consider the system with the following open-loop transfer function: GHSS T 1SKT2S1 . Draw Nyquist diagrams. Determine the 1 stability of the system for two cases, the gain K is small, K is large. 15% 名师归纳总结 - - - - - - -第 8 页,共 29 页精选
16、学习资料 - - - - - - - - - Solution: The advantages of open-loop control systems are as follows: Simple construction and ease of maintenance Less expensive than a corresponding closed-loop system There is no stability problem Convenient when output is hard to measure or economically not feasible. For ex
17、ample, it would be quite expensive to provide a device to measure the quality of the output of a toaster. The disadvantages of open-loop control systems are as follows: Disturbances and changes in calibration cause errors, and the output may be different from what is desired. To maintain the require
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