2022年提公因式法练习题 .pdf
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1、提公因式法(一)课堂练习一、填空题 1.把一个多项式_,这样的式子变形,叫做把这个多项式因式分解,也叫做把这个多项式 _。2.把下列各多项式的公因式填写在横线上。(1)x2-5xy _ (2)-3m2+12mn _ (3)12b3-8b2+4b _ (4)-4a3b2-12ab3 _(5)-x3y3+x2y2+2xy _ 3.在括号内填入适当的多项式,使等式成立。(1)-4ab-4b=-4b()(2)8x2y-12xy3=4xy()(3)9m3+27m2=()(m+3)(4)-15p4-25p3q=()(3p+5q)(5)2a3b-4a2b2+2ab3=2ab()(6)-x2+xy-xz=-x
2、()(7)21a2-a=21a()二、选择题1.下列各式从左到右的变形是因式分解的是()(A)m(a+b)=ma+mb (B)x2+3x-4=x(x+3)-4 (C)x2-25=(x+5)(x-5)(D)(x+1)(x+2)=x2+3x+2 2.下列各等式从左到右的变形是因式分解的是()(A)8a2b3c=2a22b32c (B)x2y+xy2+xy=xy(x+y)(C)(x-y)2=x2-2xy+y2 (D)3x3+27x=3x(x2+9)3.下列各式因式分解错误的是()(A)8xyz-6x2y2=2xy(4z-3xy)(B)3x2-6xy+x=3x(x-2y)(C)a2b2-41ab3=4
3、1ab2(4a-b)(D)-a2+ab-ac=-a(a-b+c)4.多项式-6a3b2-3a2b2+12a2b3因式分解时,应提取的公因式是()(A)3ab (B)3a2b2 (C)-3a2b (D)-3a2b25.把下列各多项式分解因式时,应提取公因式2x2y2的是()(A)2x2y2-4x3y (B)4x2y2-6x3y3+3x4y4(C)6x3y2+4x2y3-2x3y3 (D)x2y4-x4y2+x3y36.把多项式-axy-ax2y2+2axz 提公因式后,另一个因式是()(A)y+xy2-2z (B)y-xy2+2z (C)xy+x2y2-2xz (D)-y+xy2-2z 7.如果
4、一个多项式4x3y-M 可以分解因式得4xy(x2-y2+xy),那么 M等于()(A)4xy3+4x2y2 (B)4xy3-4x2y2 (C)-4xy3+4x2y2 (D)-4xy3-4x2y28.下列各式从左到右的变形:(a+b)(a-b)=a2-b2 x2+2x-3=x(x+2)-3 x+2=x1(x2+2x)a2-2ab+b2=(a-b)2是因式分解的有()(A)1 个 (B)2个 (C)3个 (D)4个(二)课后作业1.把下列各式分解因式 (1)9m2n-3m2n2 (2)4x2-4xy+8xz (3)-7ab-14abx+56aby (4)6x4-4x3+2x2 (5)6m2n-1
5、5mn2+30m2n2 (6)-4m4n+16m3n-28m2n(7)xn+1-2xn-1 (8)-2x2n+6xn2.用简便方法计算:(1)9 10100-10101 (2)4.3199.7+7.5 199.7-1.8 199.7 3.已知 a+b=2,ab=-3 求代数式2a3b+2ab3的值。文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 Z
6、R3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5
7、D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 Z
8、R3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5
9、D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 Z
10、R3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5
11、D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B34.如果哥哥和弟弟的年龄分别为x 岁、y 岁,且 x2+xy
12、=99,求出哥哥、弟弟的年龄。一、填空题1.在横线上填入“+”或“-”号,使等式成立。(1)a-b=_(b-a)(2)a+b=_(b+a)(3)(a-b)2=_(b-a)2 (4)(a+b)2=_(b+a)2(5)(a-b)3=_(b-a)3 (6)(-a-b)3=_(a+b)32.多项式 6(x-2)2+3x(2-x)的公因式是 _ 3.5(x-y)-x(y-x)=(x+y)_ 4.a(b-c)+c-b=(b-c)_ 5.p(a-b)+q(b-a)=(p-q)_ 6.分解因式a(a-1)-a+1=_ 7.x(y-1)-(_)=(y-1)(x+1)8.分解因式:(a-b)2(a+b)+(a-b
13、)(a+b)2=(_)(a-b)(a+b)二、选择题 1.下列各组的两个多项式,没有公因式的一组是()(A)ax-bx与 by-ay (B)6xy+8x2y 与-4x-3 (C)ab-ac与 ab-bc (D)(a-b)3x 与(b-a)2y 2.将 3a(x-y)-9b(y-x)分解因式,应提取的公因式是()(A)3a-9b (B)x-y (C)y-x (D)3(x-y)3.下列由左到右的变形是因式分解的是()文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8
14、R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3
15、O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8
16、R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3
17、O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8R2F7 HN1W2P1S6C9 ZR3O4B9B7B3文档编码:CD8W5D8
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