2022年指数函数与对数函数专项练习 .pdf

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1、指数函数与对数函数专项练习1 设232555322555abc（）,（），（），则 a，b，c 的大小关系是 （A）ac b （B）abc （C）cab （D）b ca 2 函数 y=ax2+bx与 y=|logbax(ab 0，|a|b|)在同一直角坐标系中的图像可能是 3.设525bm，且112ab，则m （A）10（B）10 （C）20 （D）100 4.设 a=3log2,b=In2,c=125,则 A.abc B.bca C.cab D.cb0，y0，函数 f(x)满足 f（xy）f（x）f（y）”的是 （A）幂函数（B）对数函数（C）指数函数（D）余弦函数8.函数 y=log2x

2、的图象大致是 PS(A)(B)(C)(D)8.设554alog 4blogclog25，（3），则 (A)acb (B)bca (C)abc (D)bac 9.已知函数1()log(1),f xx若()1,f=(A)0(B)1(C)2(D)3 10.函数164xy的值域是 （A）0,）(B)0,4 (C)0,4)(D)(0,4)11.若372log log 6log 0.8abc，则（）AabcBbac CcabDbca12.下面不等式成立的是()A322log 2log 3log 5B3log5log2log223C 5log2log3log232 D2log5log3log32213.若0

3、1xy，则()A33yxBlog 3log3xyC44loglogxyD11()()44xy14.已知01a，log2log3aax，1log 52ay，log21log3aaz，则（）AxyzBzyxCyxzDzxy15.若13(1)ln2lnlnxeaxbxcx，则（）AabcBcabCbacDbc0 且 a 1).(1)求 f(x)的定义域；(2)讨论 f(x)的奇偶性；(3)讨论 f(x)的单调性.指数函数与对数函数专项练习参考答案1）A 文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX

4、1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E

5、10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档

6、编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2

7、Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F

8、2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE

9、2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L

10、6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6【解析】25yx在0 x时是增函数，所以ac，2()5xy在0 x时是减函数，所以cb。2.D【解析】对于 A、B两图，|ba|1 而 ax2+bx=0 的两根之和为-ba,由图知 0-ba1 得-1ba0,矛盾，对于C、D两图，0|ba|1,在 C图中两根之和-ba1 矛盾，选D。3.D 解析：选A.211log

11、2log5log102,10,mmmmab又0,10.mm4.C【解析】a=3log2=21log 3,b=In2=21log e,而22log 3log1e,所以 ab,c=125=15,而2252log 4log 3,所以 ca,综上 ca1log 61log 0.80abc，0，12 A【解析】由322log 21log 3log 5,故选 A.13C函数4()logf xx为增函数14.Clog6,axlog5,aylog7,az由01a知其为减函数,yxz15.【解析】由0ln111xxe，令xtln且取21t知ba1 时，ax+1 为增函数，且ax+10.12xa为减函数，从而 f

12、(x)1-12xa11xxaa为增函数.2当0a1 时，类似地可得f(x)11xxaa为减函数.文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6

13、文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:C

14、M2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V1

15、0F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6

16、HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P

17、5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6文档编码:CM2Z1V10F2B6 HE2K3P5L6O7 ZX1H7E7E10G6