书签分享收藏举报版权申诉 / 9

立即下载

当前位置：首页 > 教育专区 > 高考资料 > 2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 .pdf

2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 .pdf

上传人：Q****o

文档编号：60239111

上传时间：2022-11-15

格式：PDF

页数：9

大小：171.26KB

( 4.5 )

《2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 .pdf》由会员分享，可在线阅读，更多相关《2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 .pdf（9页珍藏版）》请在淘文阁 - 分享文档赚钱的网站上搜索。

1、2009 中考数学专题讲座方程观点解几何计算题概述：含有未知数的等式便是方程，代数方面的应用题，?几何方面的计算题便是求某些未知数的值，都可用方程的观点去解决，一般一个未知数列一个方程，?两个未知数列两个方程典型例题精析例 1有一块直角三角形纸片，两直角边AC=6cm，BC=8cm，现将直角边AC?沿直线 AD折叠，使它落在斜边AB上，且与AE重合，求 CD长分析：RtABC，C=90，AC=6，BC=8 AB=10 由题意知ACD AEDDEB=90，DECD，AC=AE=6，设 CD=x，则 DE=x，而 EB=4，一个未知数，需要一个方程，从何而来，图中有直角，用勾股定理，有等式，有方程

2、在 Rt DEB中，（8-x）2=x2+42，64-16x+x2=x2+16，16x=48，x=3（cm）例 2已知 O中，两弦AB、CD相交于 E，若 E为 AB中点，且CE：ED=1：4，AB=4，求 CD长解：CE：ED=1：4，设 CE=x，则 ED=4x，由相交弦定理得 CEED=AE EB，即 x4x=2 2，4x2=4，x=1CD=x+4x=5x=5例 3如图，AB为 O的直径，P点在 AB延长线上，PM切 O于 M点，若 OA=a，PM=3a，求 PMB的周长分析：条件符合切割线定理，设BP=x，则由PM2=PB PA（方程出来了）得（3a）2=x（x+2a），x2+2ax-3

3、a2=0，OBCAED8-x6xBCAxED4aaMOBAP（x+3a）（x-a）=0，x1=a，x2=-3a（舍去）x=a，即 BP=a，连结 MO（常作辅助线）则 OMP=90，OB=BP=a，则 MB为 RtOMP 的斜边上的中线，MB=12OP=a MBP 的周长为2a+3a例 4如图，圆心在Rt ABC斜边 AB上的半圆切直角边AC、BC于 M、N，?其中 AC=?6，BC=8，求半圆的半径分析：设半径为R，（一个未知数建立一个方程即可），连 OM、ON、OC，则 OM=ON=R，用面积，SAOC+SBOC=SABC，得 6R+8R=6 8（一元一次方程）14R=48，R=247中考

4、样题训练:1如图，在 ABC中，C=90，BAC=30，BC=1，D为 BC边上的一点，tan ADC是方程 3（x2+21x）-5（x+1x）=2 的一个根，求CD的长2如图，已知直线BC切 O于 C，PD为 O的直径，BP的延长线与CD?的延长线交于点A，A=28,B=26，求 PDC的度数MOBCANBCADOBCADP文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10

5、Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D

6、8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1

7、P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M

8、10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H

9、6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4

10、E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S

11、1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P23已知，如图，C为半圆上一点，ACCE，过 C 作直径的垂线CP，P为垂足，弦AE分别交 PC，CB于点 D，F（1）求证：AD=CD；（2）若 DF=54，tan ECB=34，求 PB的长EOBCADPF 4已知关于x 的方程 x2-（k+1）x+14k2+1=0 的两根是一个矩形两邻边的长（1）k 取何值时，方程有两个实数根；（2）当矩形的对角线长为5时，求 k 的值文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1

12、P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M

13、10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H

14、6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4

15、E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S

16、1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L

17、5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6

18、B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2 5如图所示，AB是 O的直径，BC是 O的弦，O?的割线 PDE?垂直 AB于点 F，交 BC于点 G，连结 PC，BAC=BCP，求解下列问题：（1）求证：CP是 O的切线；（2）当 ABC=30，BG=23，CG=43时，求以 PD、PE的长为两根的一元二次方程（3）若（1）的条件不变，当点 C在劣弧 AD上运动时，应再具备什么条件可使结论BG2=BF DO成立？试写出你的猜想，并说明理由EOBCADPGF 6已知

19、：如图所示，BC为 O的直径，AD BC，垂足为 D，弦 BF和 AD交于 E，且 AE=BE（1）试猜想：AB与AF有何大小关系？并证明你的猜想；（2）若 BD、CD的长是关于x 的方程 x2-kx+16=0 的两个根，求BF的长；（3）在（2）的条件下，若k 为整数，且满足532(12),13713.22kkkk，求 sin2 A的值EOBCADF考前热身训练文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6

20、B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV

21、9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD

22、8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5

23、S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:

24、CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4

25、HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 Z

26、Y5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P21要用圆形铁片截出边长为4cm的正方形铁片，求选用的圆形铁片的直径的最小值2圆内两条弦AB和 CD相交于 P点，AB长为 7，AB把 CD分成两部分的线段长为2 和 6，?求 AP的长3如图，PA切 O于点 A，PBC交 O于 B、C，若 PB、PC的长是关于x 的方程 x2-（m-?2）x+（m+2）=0的两个根，且BC=4，求 m的值及 PA的长OBCAP4如图，D是 ABC的边 AC上一点，CD=2AD，AE BC，交 BC于点 E，若 BD=8，sin CBD=34，求 AE的长文档编

27、码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T

28、4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8

29、 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文

30、档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z

31、4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8

32、R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P

33、2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P25如图，在ABC中，CAD=B，若 AD=7，AB=8，AC=6，求 DC的长6已知，如图，以ABC的边 BC为直径的半圆交AB于 D，交 AC于 E，过 E点作 EFBC，?垂足为 F，且 BF：FC=5：1，AB=8，AE=2，求 EC的长EOBCADF答案:中考样

34、题看台1解：3（x+1x）2-5（x+1x）-8=0，x+1x=83或 x+1x=-1，BCAD2xEBCAxDF文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E

35、1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1

36、M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5

37、H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B

38、4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9

39、S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8

40、L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2由 x+1x=83得 x=473 x+1x=-1 得 x2+x+1=0 无解tan ADC=473，在 RtABC中，AC=tan30BC=3在 Rt

41、ADC中，CD=tanACADC=4 3213CD1，CD=4 32132 PDC=36 3（1）证明：连结AC，ACCE，CEA=CAE CEA=CBA，CBA=CAE，?AB是直径，ACB=90，CP AB，CBA=ACP，CAE=ACP，AD=CD（2）解：ACB=90，CAE=ACP，DCF=CFD，AD=CD=DF=54，ECB=?DAP，tan ECB=34，tan DAP=DPPA=34，PD2+PA2=DA2，DP=34，PA=1，CP=2，ACB=90，CP AB，APC CPB，APPCPCPB，PB=4 4（1）要使方程有两个实数根，必须0，即-（k+1）2-4（14k2

42、+1）0，文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9

43、S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8

44、L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S

45、6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:C

46、V9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 H

47、D8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY

48、5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2化简得：2k-3 0，解之得：k32（2）2222(5)1114ababkabk解之得：k1=2，k2=-6 由（1）可知，k=-6 时，方程无实数根，所以，只能取k=25（1）连结 OC，证 OCP=90 即可（2）B=30，A=BCP=60，BCP=

49、CGP=60，CPG 是正三角形PG=CP=43，PC切 O于 CPC2=PD PE=（43）2=48，又 BC=63，AB=6，FD=33，EG=3，PD=23，PD+PE=23+83=103以 PD、PE为两根的一元二次方程为x2-48x+103=0（3）当 G为 BC中点，OG BC，OG AC或 BOG=BAC 时，结论BG2=BFBO成立?要让此结论成立，只证明BFG BGO 即可，凡是能使BFG BGO 的条件都可以6可以猜想到ABAF证明：延工AD交 O于点 GBC是 O的直径，AD BC，ABBG AE=BE，ABE=BAE，AFBG，ABAF（2）ABBGAF，BFAG，BF

50、=AG AD BC，BC是 O直径，AG=2AD，BF=2AD，文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L5H6D8R8 ZY5S6B4E1P2文档编码:CV9S1M10Z4T4 HD8L

文档加载中……请稍候！
如果长时间未打开，您也可以点击刷新试试。

下载文档到电脑，查找使用更方便

4.3 金币

版权申诉 word格式文档无特别注明外均可编辑修改；预览文档经过压缩，下载后原文更清晰！ 立即下载

配套讲稿：: 如PPT文件的首页显示word图标，表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
特殊限制：: 部分文档作品中含有的国旗、国徽等图片，仅作为作品整体效果示例展示，禁止商用。设计者仅对作品中独创性部分享有著作权。
关键词：: 2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 2022 数学同步练习题考试题试卷教案中考专题讲座方程观点几何算题

淘文阁 - 分享文档赚钱的网站所有资源均是用户自行上传分享，仅供网友学习交流，未经上传用户书面授权，请勿作他用。

限制150内

关于本文

本文标题：2022年数学同步练习题考试题试卷教案中考数学专题讲座方程观点解几何计算题 .pdf
链接地址：https://www.taowenge.com/p-60239111.html