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2022年复数练习 .pdf

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1、复数基础练习题一、选择题1下列命题中：若 zabi，则仅当a0，b 0 时 z为纯虚数；若(z1z2)2(z2z3)20，则 z1z2z3；xyi22i?xy2；若实数a与 ai 对应，则实数集与纯虚数集可建立一一对应关系其中正确命题的个数是()A 0B1 C2 D 3 2在复平面内，复数zsin 2icos 2 对应的点位于()A第一象限B第二象限C第三象限D第四象限3a 为正实数，i 为虚数单位，z1ai，若|z|2，则 a()A 2 B.3 C.2 D 1 4(20XX 年高考湖南卷改编)若 a，bR，i 为虚数单位，且aii2b i，则()A a1，b1 Ba 1，b1 Ca 1，b

2、1 D a1，b 1 5复数 z3i2对应点在复平面()A第一象限内B实轴上C虚轴上D第四象限内6设 a，b为实数，若复数12i(a b)(ab)i，则()A a32，b12Ba3，b1 Ca12，b32Da1，b3 7复数 z1212i 在复平面上对应的点位于()A第一象限B第二象限C第三象限D第四象限8已知关于x 的方程 x2(m2i)x22i0(mR)有实根 n，且 zmni，则复数z 等于()A 3i B3 I C 3i D 3i 9设复数z满足关系式z|z|2i，那么 z 等于()A34i B.34 I C34i D.34i 10已知复数z 满足 zi33 i，则 z()A 0B2i

3、 C6 D6 2i 11计算(i3)(2 5i)的结果为()A 56i B3 5i C 56i D 35i 12向量 OZ1对应的复数是54i，向量 OZ2对应的复数是54i，则 OZ1OZ2对应的复数是()A 108i B108i C0 D108i 13设 z134i，z2 23i，则 z1z2在复平面内对应的点位于()A第一象限B第二象限C第三象限D第四象限14如果一个复数与它的模的和为53i，那么这个复数是()A.115B.3I C.1153i D.11523i 15设 f(z)z，z1 34i，z2 2i，则 f(z1z2)()A 13i B11i2 Ci2 D55i 16复数 z1

4、cos i，z2sin i，则|z1z2|的最大值为()A 5 B.5 C6 D.6 17设 zC，且|z1|zi|0，则|zi|的最小值为()A 0 B1 C.22D.1218若 zC，且|z2 2i|1，则|z 22i|的最小值为()A 2 B3 C4 D5 19(20XX 年高考福建卷)i 是虚数单位，若集合S 1,0,1，则()A iSBi2SC i3SD.2iS20(20XX 年高考浙江卷)把复数 z 的共轭复数记作z，i 为虚数单位若z1i，则(1 z)z()A 3i B3 I C13i D3 21化简24i1i2的结果是()A 2i B 2I C2i D 2i 22(20XX 年

5、高考重庆卷)复数i2i3i41i()A1212iB1212I C.1212i D.1212i 23(20XX 年高考课标全国卷)复数2i12i的共轭复数是()A35i B.35i C i Di 24i 是虚数单位，(1 i1 i)4等于()A i B I C1 D 1 25若复数z11i，z23 i，则 z1 z2()A 42i B2I C22i D3 i 26设 z 的共轭复数是z，若 z z 4，z z 8，则zz等于()A i B i C 1 D i 27(20XX 年高考浙江卷)对任意复数zxyi(x，yR)，i 为虚数单位，则下列结论正确的是()A|z z|2yBz2x2y2C|z

6、z|2xD|z|x|y|二、填空题28在复平面内表示复数z(m 3)2 mi 的点在直线yx 上，则实数m 的值为 _29复数 zx1(y 2)i(x，y R)，且|z|3，则点 Z(x，y)的轨迹是 _30复数z112i，z2 2i，z332i，z432i，z1，z2，z3，z4在复平面内的对应点分别是 A，B，C，D，则 ABC ADC _.31复数 43i 与 25i 分别表示向量 OA与OB，则向量 AB表示的复数是_32已知 f(zi)3z2i，则 f(i)_.33已知复数z1(a22)(a4)i，z2a(a22)i(aR)，且 z1z2为纯虚数，则a_.34(20XX 年高考上海卷

7、)若复数 z12i(i 为虚数单位)，则 z z z_.35(20XX 年高考江苏卷)设复数 z 满足 i(z1)32i(i 为虚数单位)，则 z的实部是 _36已知复数z 满足|z|5，且(34i)z 是纯虚数，则z _.文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y

8、3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9

9、H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10

10、K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q

11、6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7

12、S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS

13、10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2答案一、选择题1解析：选 A.在中没有注

14、意到zabi 中未对 a，b 的取值加以限制，故错误；在中将虚数的平方与实数的平方等同，如：若z11，z2i，则 z21z22110，从而由z21z220?/z1z20，故错误；在中若x，yR，可推出 xy2，而此题未限制x，yR，故不正确；中忽视0 i0，故也是错误的故选A.2 解析：选 D.220，cos20.故 zsin 2icos 2 对应的点在第四象限故选D.3解析：选 B.|z|1ai|a212，a 3.而 a 是正实数，a3.4解析：选 D.aii2 1aibi，故应有 a1，b 1.5 解析：选 B.z3i23 1R，z 对应的点在实轴上，故选B.6解析：选 A.由 1 2i(

15、ab)(ab)i 得ab 1ab 2，解得 a32，b12.7 解析：选 A.复数 z在复平面上对应的点为12，12，该点位于第一象限，复数z 在复平面上对应的点位于第一象限8解析：选 B.由题意知n2(m 2i)n 22i0，即 n2mn2(2n2)i 0.n2mn202n 20，解得m3n 1，z3i.9解析：选 D.设 zxyi(x、y R)，则 xyix2y22i，xx2y22，y1.解得x34，y1.z34i.10解析：选 D.由 zi33i，知 z(3i)(3i)62i.11解析：选 A.(i3)(25i)(32)(51)i56i.12解析：选 C.OZ1OZ2对应的复数是5 4i

16、(54i)(55)(44)i0.13 解析：选 D.z1 z2(34i)(23i)(32)(43)i1i，z1z2对应的点为(1，1)，在第四象限14解析：选 C.设这个复数为z abi(a，bR)，则 z|z|53i，即 aa2b2 bi 53i，b3aa2b25，解得b3a115.z1153i.15解析：选 D.先找出 z1z2，再根据求函数值的方法求解z134i，z2 2i，z1z2(32)(41)i55i.f(z)z，f(z1z2)z1z255i.故选 D.16解析：选 D.|z1z2|(cos sin)2i|cos sin24 文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P

17、5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2

18、文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6

19、M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D

20、3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2

21、L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6

22、M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y

23、3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L252sin cos5sin2 6.17解析：选 C.|z1|zi|表示以(1,0)、(0,1)为端点的线段的垂直平分线，而|zi|z(i)|表示直线上的点到(0，1)的距离，数形结合知其最小值为22.18 解析：选 B.法一：设 zxyi(x，yR)，则有|xyi2 2i|1，即|(x2)(y2)i|1，所以根据复数模

24、的计算公式，得(x 2)2(y 2)2 1，又|z 2 2i|(x 2)(y 2)i|x22 y 22x 221 x2218x.而|x2|1，即 3x1，当 x 1 时，|z22i|min3.法二：利用数形结合法|z 22i|1 表示圆心为(2,2)，半径为 1 的圆，而|z22i|z(22i)|表示圆上的点与点(2,2)的距离，由数形结合知，其最小值为3，故选 B.19解析：选 B.因为 i2 1S，i3 i/S，2i 2i/S，故选 B.20解析：选 A.(1z)z(2i)(1i)3i.21解析：选 C.24i1i224i2i12ii2i.故选 C.22解析：选 C.i2i3 i

25、41i 1i11 ii1ii1i1i1 i1i21212i.23解析：选 C.法一：2i12i()2i()12i()12i()12i2i4i25 i，2i12i的共轭复数为i.法二：2i12i2i2 i12ii()1 2i12ii，2i1 2i的共轭复数为i.24解析：选 C.(1i1i)4(1i1i)22(2i2i)21.故选 C.25解析：选 A.z11i，z23i，z1 z2(1i)(3 i)3 3iii23 2i 142i.故选 A.26解析：选 D.法一：设 zxyi(x，y R)，则 z xyi，由 z z 4，zz 8 得，xyixyi4，xyixyi 8.?x2x2y28?x2

26、y 2.zzxyixyix2y22xyix2y2 i.法二：z z 4，设 z2bi(bR)，又 z z|z|28，4b2 8，b24，b 2，z2 2i，z 2?2i，zz i.27解析：选 D.z xyi(x，yR)，|z z|xyi xyi|2yi|2y|，A 不正确；对于B，z2x2y22xyi，故不正确；|z z|2y|2x 不一定成立，C 不正确；对于D，|z|x2y2|x|y|，故D 正确二、填空题28解析：复数 z 在复平面上对应的点为(m 3,2m)，m32m，即 m2m30.解得 m9.答案：9 29解析：|z|3，x12 y223，即(x1)2(y2)232.故点 Z(x

27、，y)的轨迹是以O(1,2)文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L

28、2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M

29、6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3

30、D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H

31、2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K

32、6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6

33、Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2为圆心，以3 为半径的圆答案：以(1,2)为圆心，3 为半径的圆30解析：|z1|z2|z3|z4|5，所以点 A，B，C，D 应在以原点为圆心，5为半径的圆上，由于圆内接四边形 ABCD 对角互补，所以ABC ADC180.31解析：

34、AB表示 OBOA对应的复数，由25i(43i)6 8i，知 AB对应的复数是68i.答案：68i 32解析：设 zabi(a，bR)，则fa(b1)i 3(a bi)2i3a(3b2)i，令 a 0，b0，则 f(i)2i.答案：2i 33 解析：z1 z2(a2 a 2)(a 4 a2 2)i (a2 a 2)(a2 a 6)i(a R)为纯虚数，a2a20，a2a60，解得 a 1.34解析：z12i，zz|z|25.z z z62i.答案：62i 35解析：设 zabi(a、bR)，由 i(z1)32i，得 b(a1)i 32i，a12，a 1.答案：1 36解析：(34i)z

35、是纯虚数，可设(34i)zti(tR 且 t0)，zti34i，|z|t|55，|t|25，t 25，z 25i34i i(34i)(43i)，z (43i)(43i)答案：(43i)文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档

36、编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5

37、Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P

38、5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2

39、文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6

40、M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2文档编码:CS10K6M6M5Q8 HV3Q6Y3D3P5 ZE2W7S9H2L2

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