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2022年数电第五章习题答案 .pdf

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1、622196746.docx 第 1 页共 6 页5.1 基本触发器的逻辑符号与输入波形如图P5.1 所示。试作出Q、Q 的波形。图 P5.1 5.2 图 P5.2 电路，在开关S由 A 点拨到 B 点，再由B 点拨回 A 点过程中，A、B 两点电压波形如图中所示。试作出Q 和 Q 端的波形。图 P5.2 5.3 分析图 P5.3 的逻辑功能：列出真值表，导出特征方程并说明SD、RD的有效电平。解：(1)列真值表如下(2)求特征方程5.4 对于图 P5.4 电路，试导出其特征方程并说明对A、B 的取值有无约束条件。SDRDQQ345TitleNumSizeBDate:24-MaFile:E:

2、DesSRQQSRDD3456ABCD6543TitleNumberRevisionSizeBDate:24-Mar-2002Sheet of File:E:Design Explorer 99 SELibrary YangHengXinMyDesign.ddbDrawn By:SRRRS+5VBAQQUAtUBtQttQ?1 111 000 1Qn0 0Qn+1SDRD?00100?11100101011SDRDQnSDRD=0Qn+1=SD+RDQnSD、RD 高电平有效。QRD1G11G2QSD图 P5.3 622196746.docx 第 2 页共 6 页解：(1)列真值表如下(2)

3、求特征方程5.5 试写出图P5.5 触发器电路的特征方程。5.6 试写出图P5.6 各触发器电路的特征方程。图 P5.6 5.7 维阻 D 触发器的CP 和 D 信号如图P5.7 所示，设触发器 Q 端的初态为“0”，试作 Q 端波形。QA&G1 1G2QB图 P5.4 11 1Qn1 010 110 0Qn+1A B101100111011111001ABQnQn+1=A+B+Qn对 A、B 的取值无约束条件。Qn+1=S+RQnSR=0CP=1 时，图 P5.5 QR1 1QS&CPCP=0 时，Qn+1=Qn(a)321DCB1TC1TCPQQ1D1(b)321DCB1TC1TCPQQ1

4、D21DCB1TC1TCPQQ1D(c)123321DCBA1JC11K1CPQQ1JK(d)(e)4321JC11K1CPQQ1JK(f)43211JC11K1CPQQ1JK321DCBA1JC11K1CPQQ1JK(g)(h)321DCB1JC11K1CPQQ1JK(a)特征方程：Qn+1=1 CP(b)特征方程：Qn+1=Qn CP(c)特征方程：Qn+1=Qn CP(d)特征方程：Qn+1=JQn+KQn CP(e)特征方程：Qn+1=Qn CP(f)特征方程：Qn+1=Qn CP(g)特征方程：Qn+1=Qn CP=(h)特征方程：Qn+1 1 CP文档编码:CN10X4I1J1I8

5、 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2

6、G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W1

7、0 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N

8、4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z

9、5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:

10、CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4

11、I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5622196746.docx 第 3 页共 6 页图 P5.7 图 P5.8 5.8 维阻 D 触发器构成的电路如图P5.8 所示，试作Q 端波形。解：特征方程为：，Q 端波形如图P5.8 所示。5.

12、10 画出图 P5.10 中 Q 端的波形。设初态为“0”。解：特征方程为：，Q 端波形如图P5.10 所示。图 P5.10 5.11 画出图 P5.11电路 Q 端的波形。设初态为“0”。解：特征方程为：而且，Q 端波形如图P5.11所示。图 P5.11 P5.12 5.12 画出图 P5.12 电路中 Q1、Q2的波形。解：特征方程为：，Q 端波形如图P5.12所示。CPDQQn+1=D=QnCPRDQQn+1=D=QnACPQA2341DC1=1ACP=JQn CP Qn+1RD=CP QnCPQJRD=D CP1,Q1n+1Q2n+1=Q1n CP2CP1RDCP2DQ1Q20文档编码

13、:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X

14、4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I

15、8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X

16、2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W

17、10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8

18、N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4

19、Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5622196746.docx 第 4 页共 6 页5.13 画出图 P5.13 电路中Q1和 Q2的波形。图 P5.13 解：特征方程为：，Q 端波形如图P5.13 所示。5

20、.14 试作出图P5.14 中 Q 端和 Z 端的波形。设Q 的初态为“0”。解：特征方程为：，而且 Z=A Qn，Q、Z 端波形如图P5.14 所示。图 P5.14 图 P5.15 5.15 画出图 P5.15 电路中 Q 端的波形。解：Q 端波形如图P5.15 所示。5.16 试作出图P5.16 电路中 QA、QB的波形。解：特征方程为：，Q 端波形如图P5.16所示。图 P5.16 图 P5.17 3456ABCT itleNu mberRevisio nSizeBDate:24-Mar-2002S h eet of File:E:Desig n Ex plorer 99 SELib r

21、aryYangHengXinMyDesign.ddbDrawn By:1DC1R1JC11KRCPCPRD1212QQQ1n+1=Q2n CP1Q2n+1=Q1n CP2Q1RDCP1CP2Q2Qn+1=QnA CPCPAQZSDCPQXQAn+1=QBn AQBn+1=QAn BARDBQAQBRDCPCPQ2Q1Q2文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1

22、J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 H

23、G9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2

24、V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10

25、ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G

26、5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文

27、档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN

28、10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5622196746.docx 第 5 页共 6 页5.17 试作出图P5.17 电路中 Q1、Q2的波形。解：特征方程为：，Q 端波形如图P5.17 所示。5.18 试作出图P5.18 电路中 Q1和 Q2的波形（设Q1和 Q2的初态均为“0”），并说明Q1和Q2对于 CP2各为多少分频。解：特征方程为：，Q 端波形如图P5.18 所示。Q1和 Q2对于 CP2都是 4分频，即图 P5.18 图 P5.19 5.19 已知电路如图P5.19

29、，试作出Q 端的波形。设Q 的初态为“0”。解：特征方程为：，Q 端波形如图P5.19 所示。5.20 已知输入uI、输出 uO波形分别如图P5.20 所示，试用两个D 触发器将该输入波形uI转换成输出波形uO。解：输出uO是对输入 uI的 4 分频，而采用1 个 DFF 可实现 2 分频，故实现电路如图P5.20所示。图 P5.20 5.21 试分别用公式法和列表图解法将主从SR 触发器转换成JK 触发器。解 1：Q1n+1=Q1n (CPQ2)Q2n+1=Q2n Q1?)?,(2221CPQCPQffffQ1n+1=Q1n CP1Q2n+1=Q2n CP2Q1nCP2CP1Q1Q241,4

30、12221CPQCPQffffQn+1=A CPCPAQ1DC1QQ1DC1QQuIuOQn+1=S+RQnSR=0Qn+1=JQn+KQn文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG

31、9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V

32、6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 Z

33、F8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5

34、A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档

35、编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN1

36、0X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5622196746.docx

37、第 6 页共 6 页令新老触发器的次态方程相等，则有S=JQn，R=K 但不满足约束条件SR=0。改为：解 2:(1)列综合表，如下所示：(2)作卡诺图，如下图所示（3）电路图如下：图 P5.21S=JQn，R=KQn=JQ（因为 Qn+1=JQn+KQnn+KQnQn）01 101 010 100 0Qn+1K QnS R 0 1?0?0 0 0 0 0 0 J 01 111 010 110 01 1?0 0 0 0 1 1 1 1 1 011JKQ10?110?00100100n?11JKQ0100110?0100100nS=JQnR=KQn1SC1QQJ1R&KCP文档编码:CN10

38、X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1

39、I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9

40、X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6

41、W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF

42、8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A

43、4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5文档编码:CN10X4I1J1I8 HG9X2G2V6W10 ZF8N4G5A4Z5

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