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2022年奥数五年级带余数除法-奥数教研组 .pdf

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文档编号：60557857

上传时间：2022-11-16

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1、vip 会员免费奥数五年级带余数除法一、填空题1 小东在计算除法时，把除数 87 写成 78，结果得到的商是 54，余数是 8.正确的商是 _,余数是 _.2.a24=121b,要使余数最大，被除数应该等于_.3.一个三位数被 37 除余 17,被 36 除余 3,那么这个三位数是 _.4.393 除以一个两位数,余数为 8,这样的两位数有 _个,它们是 _.5.31453 68765 987657的积,除以 4 的余数是 _.6.5050888.8 666.6个个的积，除以 7 余数是 _.7.如果时针现在表示的时间是18 点整,那么分针旋转 1990 圈之后是 _点钟.8.甲、乙、丙、丁四

2、个小朋友玩报数游戏,从 1 起按下面顺序进行：甲报1、乙报 2、丙报 3、丁报 4、乙报 5、丁报 6、甲报 7、乙报 8、丙报 9，这样，报 1990这个小朋友是_.9.如果按红、橙、黄、绿、青、蓝、紫的顺序，将1991199219921992.1992个只彩灯依次反复排列，那么_颜色的彩灯必定要比其他颜色的彩灯少一只.10.从 7 开始,把 7 的倍数依次写下去,一直写到 994成为一个很大的数:71421 987994.这个数是 _位数.二、解答题11幼儿园某班学生做游戏，如果每个学生分得的弹子一样多，弹子就多12 颗，如果再增加 12颗弹子，那么每个学生正好分得12 颗，问这班有多少个

3、学生？原有多少颗弹子？vip 会员免费12已知：1991199119911991.1991a个,问：a 除以 13,余数是几？13100 个 7 组成的一百位数,被 13 除后,问：(1)余数是多少？(2)商数中各位数字之和是多少？14有一个数,甲将其除以 8,乙将其除以 9.甲所得的商数与乙所得的余数之和为13.试求甲所得的余数.文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5

4、R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G

5、5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4

6、A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7

7、O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F

8、6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8

9、Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:C

10、R7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3vip 会员免费五带余数除法(B)年级班姓名得分一、填空题1除 107后，余数为 2 的两位数有 _.2.27()=()3.上式()里填入适当的数,使等式成立,共有_种不同的填法.3.四位数 898 能同时被 17 和 19整除,那么这个四位数所有质因数的和是_.4.一串数 1、2、4、7、11、16、22、29这串数的组成规律，第2 个数比第 1 个数多1；第 3 个数比第 2 个数多 2；第 4 个数比第 3 个数多 3；依此类推；那么这串数左起第1992个数除以 5 的余数是 _.5.2000222.22个除以 13

11、所得的余数是 _.6.小明往一个大池里扔石子,第一次扔 1 个石子,第二次扔 2 个石子,第三次扔 3 个石子,第四次扔 4 个石子，他准备扔到大池的石子总数被106除，余数是 0 止，那么小明应扔 _次.7.七位数 372的末两位数字是 _时,不管十万位上和万位上的数字是0,1,2,3,4,5,6,7,8,9中哪一个,这个七位数都不是101的倍数.8.有一个自然数,用它分别去除 63,90,130都有余数,三个余数的和是25.这三个余数中最小的一个是 _.9.在 1,2,3,29，30这 30个自然数中，最多能取出 _个数,使取出的这些数中,任意两个不同的数的和都不是7 的倍数.10.用

12、1-9 九个数字组成三个三位数,使其中最大的三位数被3 除余 2,并且还尽可能地小；次大的三位数被 3 除余 1；最小的三位数能被3 整除.那么,最大的三位数是 _.文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9

13、O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I

14、4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A1

15、0F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5

16、R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G

17、5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4

18、A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3vip 会员免费二、解答题11桌面上原有硬纸片5 张。从中取出若干张来，并将每张都任意剪成7 张较

19、小的纸片，然后放回桌面，像这样，取出，剪小，放回；再取出，剪小，放回；是否可能在某次放回后，桌上的纸片数刚好是1991？12.一个自然数被 8 除余 1，所得的商被 8 除也余 1，再把第二次所得的商被8 除后余 7，最后得到一个商是a(见短除式)；又知这个自然数被17除余 4，所得的商被 17 除余 15，最后得到一个商是a 的 2 倍(见短除式).求这个自然数.8 所求自然数余 1 8 第一次商余 1 8 第二次商余 7 a短除式 17 所求自然数余 4 17 第一次商余 15 2 a短除式 13某班有 41 名同学，每人手中有10 元到 50 元钱各不相同.他们到书店买书,已知

20、简装书 3 元一本,精装书 4 元一本,要求每人都要把自己手中的钱全部用完,并且尽可能多买几本书,那么最后全班一共买了多少本精装书?14.某校开运动会,打算发给 1991 位学生每人一瓶汽水,由于商店规定每7 个空瓶可换一瓶汽水,所以不必买 1991 瓶汽水,但是最少要买多少瓶汽水?文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y

21、4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR

22、7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7

23、F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R

24、8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:

25、CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 H

26、Z7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC

27、2R8Y4A10F3vip 会员免费答案1.48,44.依题意得被除数=7854+8=4220 而 4220=87 48+44,所以正确的商是 48,余数是 44.2.2927 因为余数一定要比除数小,所以余数最大为23,故有被除数=24121+23=2927 3.831 这个三位数可以写成37商+17=36 商+(商+17).根据“被 36 除余 3”.(商+17)被 36 除要余 3.商只能是 22(如果商更大的话,与题目条件“三位数”不符合).因此,这个三位数是 3722+17=831.4.4;11,35,55,77 393 减 8,那么差一定能被两位数整除.393-8=385 385

28、=57 11=(5 7)11=(5 11)7=(711)5 385 能被两位数 11，35，55，77整除.本题的答案是 4 个:11,35,55,77.5.1 31453 4=7863168765 4=171911987657 4=24691411 1 1=1 31453 68765 987657的积除以 4 余数是 1.6.5 文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5

29、R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G

30、5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4

31、A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7

32、O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F

33、6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8

34、Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:C

35、R7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3vip 会员免费因为 111111能被 7 整除,所以 888888和 666666均能被 7 整除.而 50=6 8+2,故得被乘数与 88 被 7 除的余数相同,乘数与 66 被 7 除的余数相同,进而得:被乘数被 7 除余 4,乘数被 7 除余 3.所以乘积与(43=)12 被 7 整除的余数相同.因此得乘积被 7 除的余数是 5.7.16 因为分针旋转一圈为一个钟头,所以分针旋转 24圈,时针旋转 2 圈.若以现时 18点整为起点与终点,这样时针又回到18点整的位置上.由 199024=82余 22，可知那时时钟表示

36、的时间应是16 点整.8.丁根据小朋友报数顺序列表如下:甲乙丙丁1 2 3 4 5 6 7 8 9 10 11 12 由上表可知每 6 个数号为一组的报数的规律.由 1990 6=3314，根据余数是 4 可知报1990 的小朋友是丁.9.紫考虑通过试除发现规律后求彩灯总数被7 除的余数即可.经试除得:199219921992能被 7整除,而 1991 被 3 除余 2,所以彩灯总数与 19921992被 7 除的余数相同,均为 6.所以,紫色的彩灯要比其它颜色的彩灯少一只.10.411 97=12一位数中能被7 整除的数有 1 个；997=141两位数中能被7 整除的数有（14-1=）13

37、个；9997=1425三位数中能被7 整除的数有142-13-1=128（个）文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D

38、1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7

39、 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3

40、文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O

41、7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4

42、B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10

43、F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3vip 会员免费所以，这个数的位数为1+132+1283=411 11 依题意知，原来每个学生分相等的若干颗，余12 颗，则学生人数大于12.同时由增加 12 颗后每个学生正好分得12

44、颗,即 12+12=24(颗),24 能被班级人数整除,又 24 能分解为24=124=2 12=3 8=46 由班级人数大于12,可知符合题意的是24 人.所以,共有弹子数 1224-12=276(颗).12.用试除的方法可知:199119911991可以被 13 除尽.原数 a 有 1991 个 1991.因为 1991除以 3 余 2,所以 a 与 19911991除以 13 所得余数相同.又 19911991除以 13 余 8,所以 a 除以 13的余数也是 8.13.因为 777777 13=59829,即 777777 能被 13 整除,把这 100个 7,从第一个起,每 6 个分

45、成一组,1006=164，共 16 组还多 4 个.每一组除以 13 的商都是 59829,7777除以 13的商是 598,余数是 3.所以,100个 7 组成一百位数除以13 后,余数是 3,商数中各位数字之和是(5+9+8+2+9)16+(5+9+8)=550 14.设甲所得的商和余数分别为a 和 b,乙所得的商和余数分别为c 和 d,于是由题意知8a+b=9c+d,a+d=13.将 d=13-a 代入前一式并整理后即得9(a-c)=13-b上式左端是 9 的倍数,因此 13-b 也是 9 的倍数.由于 b 是被 8 除的余数,所以 b 介于 0 与 7之间.故 b=4.答案答案:1.

46、15,21,35 从 107里减去余数 2,得 107-2=105,所以 105 是除数与商数相乘之积,将 105分解质因数得105=3 57,可知这样的两位数有15,21,35.2.5 根据带余数除法中各部分之间的关系可知，商除数=27-3=24.这样可通过分解质因数解答.文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10

47、F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R

48、9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5

49、I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A

50、10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O5R9O7D1 HZ7F6G5I4B7 ZC2R8Y4A10F3文档编码:CR7O

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