应用信息论基础 (4).pdf

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1、Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryLecture 3.Channel CapacityFundamentals of Information Theory2017-fall TBSI1 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoi

2、nt TypicalityChannel CodingSummaryOutline1.Channel Capacity and its PropertiesDefinition of Channel CapacityDiscrete Memoryless ChannelChannel Capacity and Its Properties2.Discrete Memoryless Channel3.Continuous and Analog Channel4.Joint Typicality5.Channel Coding6.SummaryFundamentals of Information

3、 Theory2017-fall TBSI2 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryDefinition of Channel CapacityCommunications and ChannelsCommunication:Reliable transmission of messages from one peer toanother.Shannons channel m

4、odel in 1948Types of channels,according to the continuity of values in both time andamplitude,e.g.,discrete channel/digital channel,continuous channel andanalog channel.Fundamentals of Information Theory2017-fall TBSI3 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and An

5、alog ChannelJoint TypicalityChannel CodingSummaryDiscrete Memoryless ChannelDiscrete Memoryless Channel(DMC)Definition 3.1 A discrete memoryless channel is defined with the set ofinput alphabets X,the set of output alphabets Y and one-step transitionprobability matrix Q=q(yj|xi)i,j.Note that q(y|x)i

6、s the conditional probability of y given x,and thechannel matrix Q contains|X|rows and|Y|columns.Theorem 3.1 Let the input of channel to be X=(X1,X2,.,Xn)andthe output values Y=(Y1,Y2,.,Yn).The discrete memorylesschannel satisfiesI(X;Y)nXi=1I(Xi;Yj).(1)Fundamentals of Information Theory2017-fall TBS

7、I4 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryChannel Capacity and Its PropertiesChannel CapacityDefinition 3.2 The capacity of a channel is defined asC=maxp(x)I(X;Y).(2)The information-theoretical channel capacit

8、y is defined as the maxmutual information between the input and output of the channel,over allpossible input distribution p(x)given a specific communication channel.For discrete memoryless channels,the equivalent formulation isC=maxp(x)I(p,Q),(3)where the mutual information is rewritten as the funct

9、ion of inputdistribution p and transition matrix Q.Fundamentals of Information Theory2017-fall TBSI5 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryChannel Capacity and Its PropertiesProperties of Channel CapacityTheo

10、rem 3.2 The basic properties of C is listed as follows1.Non-negative:C 0.2.Bounded:C log|X|,and C log|Y|.More importantly,I(X;Y)is a continuously concave function over p(x),implying that the maximum value,i.e,C,can be obtained using convexoptimization.A classical example of channel models:noisy type

11、-writer.Definition 3.3 If the rows and columns of transition probability matrixare permutations of themselves,respectively,the channel is symmetric.Ifthe rows are permutations of each other and the sum of columns areequal,the channel is weakly symmetric.Fundamentals of Information Theory2017-fall TB

12、SI6 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryOutline1.Channel Capacity and its Properties2.Discrete Memoryless ChannelSimple Examples of DMCCompute the DMC CapacityThe pmf to achieve the channel capacityCascadin

13、g of ChannelsParallel Channels3.Continuous and Analog Channel4.Joint Typicality5.Channel Coding6.SummaryFundamentals of Information Theory2017-fall TBSI7 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummarySimple Examples

14、of DMCSimple examples of DMCTheorem 3.3 The capacity of Binary Symmetric Channel(BSC)isC=1 H(?),(4)where?is the error rate,i.e.,the flipping probability for each bittransmitted.Theorem 3.4 The capacity of Binary Erasure Channel(BEC)isC=1 ,(5)where is the erasure probability,i.e.,the bit-loss rate.Th

15、eorem 3.5 The capacity of weak symmetric channel Q equalsC=log|Y|H(the distribution w.r.t the row of Q),(6)achievable with equally distributed probabilities.Fundamentals of Information Theory2017-fall TBSI8 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog Channel

16、Joint TypicalityChannel CodingSummaryCompute the DMC CapacityA general solution for the capacity of DMCAs I(p,Q)is concave over p,the channel capacity can be formulated asthe maximization of the objective functionmaximizepI(p,Q),(7)subject toXxp(x)=1(8)p(x)0.(9)The methods of Lagrangian multiplier,g

17、radient-based search,iterativealgorithms and KKT conditions.Fundamentals of Information Theory2017-fall TBSI9 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryCompute the DMC CapacityConvex Programming using KKT conditi

18、onsTheorem 3.6 Karush-Kuhn-Tucker conditionsSuppose the objective function f(x)is defined over n-dimensional convexset S,where S=x=(x1,x2,.,xn)|xi 0,i=1,2,.,n,and it isdifferentiable and concave over the set.Let x=(x1,x2,.,xn)S bethe optimal solution.So the function f(x)can achieve its maximumvalue

19、over S at x=xif and only iff(x)xi|x=x=0,if xi 0,(10)f(x)xi|x=x 0,if xi=0.(11)Note that x=(x1,x2,.,xn)is the interior point of S when xi 0.If xn=0,xis on the boundary of S.Fundamentals of Information Theory2017-fall TBSI10 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and

20、 Analog ChannelJoint TypicalityChannel CodingSummaryCompute the DMC CapacityThe capacity of DMCTheorem 3.7 For the discrete memoryless channel with transitionprobability matrix Q,the mutual information I(p,Q)is maximized toachieve the capacity C with respect to pif and only ifI(X=xi;Y)=C,for xithat

21、p(xi)0(12)I(X=xi;Y)C,for xithat p(xi)=0,(13)where i 1,2,.,n andI(X=xi;Y)=JXj=1q(yj|xi)logq(yj|xi)p(yj)(14)indicates the average mutual information carried by xi.Fundamentals of Information Theory2017-fall TBSI11 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog Ch

22、annelJoint TypicalityChannel CodingSummaryThe pmf to achieve the channel capacityThe uniqueness of the distributionTheorem 3.8 The output distribution is unique when achieving thechannel capacity,and all possible input distributions are optimal thatmaximizes the mutual information.The optimal input

23、distribution pis not necessarily unique.Theorem 3.9 The non-zero components of the optimal input distributionwith the maximized number of zero components are uniquely determined,and the number of non-zeros components are no more than the numberof output symbols.Note that the optimal input distributi

24、on with the most zero terms are notunique,but the non-zero components are permutations of each other.Fundamentals of Information Theory2017-fall TBSI12 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryCascading of Chann

25、elsThe cascade of independent channelsAs a cascade of two independent channelsX Y Z,(15)the data processing theorem tells I(Y;Z)I(X;Z).The capacity goes to zero with the increased number of cascades.The transition probability matrix of n cascades of channels is calculatedasQ=nYi=1Qi,(16)the product

26、of all channel matrices.Data processing theorem tells us that the additional gain in channelcapacity can be lost rather than obtained from the increased cascades.Fundamentals of Information Theory2017-fall TBSI13 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog C

27、hannelJoint TypicalityChannel CodingSummaryParallel ChannelsParallel channelsTheorem 3.10 Parallel channels sharing the same input X with differentoutput values Y1,Y2,.,Yn.1.The capacity of parallel channels with the same input is greater than thatof any single channel and less than maxH(X).2.Divers

28、ity in wireless communications is the case.Theorem 3.11 The channels used in parallel with multiple input andmultiple output(MIMO).1.Sub-channels are independent on each other and X=X1,X2,.,Xnare transmitted through these sub-channels to get Y=Y1,Y2,.,Yn,simultaneously.The equivalent capacity is the

29、 sum of capacities of theparallel sub-channels.2.Multiplexing in communications is the case.Theorem 3.12 The probabilistic utilization of n channels leads to theequivalent capacity C=logPni=12Cnwith probability pi(C)=2(CiC).Opportunistic communication is the case.Fundamentals of Information Theory20

30、17-fall TBSI14 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryOutline1.Channel Capacity and its Properties2.Discrete Memoryless Channel3.Continuous and Analog ChannelCapacity-cost FunctionAdditive Noise Continuous Cha

31、nnelWater FillingThe notion of analog channel capacityShannon FormulaInsights of Shannon Formula4.Joint Typicality5.Channel Coding6.SummaryFundamentals of Information Theory2017-fall TBSI15 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityC

32、hannel CodingSummaryCapacity-cost FunctionThe Capacity of Continuous ChannelContinuous channel that is discrete in time and continuous in values withpower constraint.Definition 3.4 Define the function b()0 as the cost for a sequencex=(x1,x2,.,xn)for continuous memoryless channel X,q(y|x),Y.Let the j

33、oint probability distribution of random vectorX=X1,X2,.,Xn be p(x).Then,the average cost isE(b(X)=Xxp(x)b(x).(17)Definition 3.5 Let X and Y be the n-dimensional vectors as the inputand output of a continuous channel.The capacity-cost function isdefined asC()=limn1nmaxp(x):E(b(X)nI(X;Y).(18)Fundament

34、als of Information Theory2017-fall TBSI16 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryAdditive Noise Continuous ChannelContinuous memoryless channel with Additive NoiseThe mutual information is simplified to nI(X,Y

35、)with stationarymemoryless input,and the capacity-utility function becomesC()=maxp(x):E(b(X)I(X;Y).(19)The channel output equals Y=X+Z,where Z is memorylessstationary noise added on the input X.Theorem 3.13 The capacity-cost function of continuous memorylessadditive noisy channel isC(PS)=maxp(x):E(X

36、2)PSh(Y)h(Z).(20)Fundamentals of Information Theory2017-fall TBSI17 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryAdditive Noise Continuous ChannelAdditive White Gaussian Noise channel(AWGN)Theorem 3.14 The capacity-

37、cost function for memoryless additivegaussian noise channel isC(PS)=12log(1+PSPN),(21)wherePSPNis the signal-to-noise ratio.AWGN channel can always be fully exploited using gaussian input at thecosts of equal transmission power.Theorem 3.15 If the input signal X is gaussian,the mutual informationis

38、minimized with gaussian noise under power constraint PN.It indicates that gaussian noise is the worst when the input is given asgaussian distribution.Fundamentals of Information Theory2017-fall TBSI18 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint

39、TypicalityChannel CodingSummaryWater FillingContinuous parallel channels and water-fillingInput vector X=(X1,X2,.,Xn)and allocated power PSiof the i-thelement;channel noise vector Z=(Z1,Z2,.,Zn)and noise powerPNi,i=1,2,.,n.The capacity of the parallel channels isC(PS)=maxp(X):Pi=1PSiP0I(X;Y),(22)whe

40、re P0is the budget for the total transmitting power.The capacity is achievable by allocating power as water-filling viaLagrange multiplier.Fundamentals of Information Theory2017-fall TBSI19 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityC

41、hannel CodingSummaryThe notion of analog channel capacityThe capacity of analog channelAnalog channel is continuous in both time and values,e.g.,fiber,wire,electromagnetic wave.A special case:Additive white gaussian noise(AWGN)channel.1.limited bandwidth:W2.additive noise:y(t)=x(t)+z(t)3.white noise

42、:stationary ergodic stochastic process and a uniformdistribution in spectral density.4.Gaussian noise:The noise is gaussian at any time.Problem formulation1.Input signal x(t)with limited bandwidth W,W,duration T and powerconstrain P.2.Output signal y(t)=x(t)+z(t)3.Noise z(t)is additive white gaussia

43、n with zero-mean,and its double-sidespectral density isN(f)=N02,if|f|W(23)and zero otherwise.Fundamentals of Information Theory2017-fall TBSI20 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryThe notion of analog chann

44、el capacityThe capacity of analog channelSampling the analog signal in time is equivalent to the parallelcombination of addictive gaussian channels.So the total capacity iswritten asCT(PS)=122WTXi=1log(1+PSiPNi)(24)under the noise power constraint PN=2WTPNi=2WTN02=WTN0.The transmission power is allo

45、cated asPSi=PST+PN2WTN02=PS2W(25)via water-filling.Then we can obtainPSiPNi=PSWN0,(26)which is used to get Shannon formula.Fundamentals of Information Theory2017-fall TBSI21 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSum

46、maryShannon FormulaShannon FormulaTheorem 3.16 The capacity of AWGN channel isC=W log(1+PSN0W).(27)Remarks:the physical dimesions of terms in Shannon formula1.capacity Cbps bit-per-second2.bandwidth WHz or s13.signal power PSWatt4.noise spectral density N0Watt/HzTwo ways to increase the channel capa

47、city1.expand the bandwidth W,bounded bylimWC(PS)=limWPSN0log(1+PSN0W)N0WPS=PSN0loge 1.44PSN.(28)2.increase the transmission power PS,approximated asC(PS)W logPSN0W(29)at high SNR regime.Fundamentals of Information Theory2017-fall TBSI22 43Channel Capacity and its PropertiesDiscrete Memoryless Channe

48、lContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryInsights of Shannon FormulaInformation and thermal-dynamicsWhen approaching the capacity,the energy per bit isEb=PSC(J/bit).(30)The normalized SNR ratioEbN0isEbN0=PSN0C=PSN0W log(1+PSN0W)=SNRlog(1+SNR),(31)lower bounded by Shannon-li

49、mit ln2 0.693 or 1.59dB if SNRapproaches zero.Remarks:1.Shannon limit indicates the minimum required energy for 1-bittransmission.2.Thermal dynamics shows the noise power spectral density N0=kT inW/Hz,where k is Boltzmann constant and T is Kelvin temperature.Therefore,the minimum energy required per

50、 bit is Eb ln2kT 0.693kTfrom the point of view of physics.Fundamentals of Information Theory2017-fall TBSI23 43Channel Capacity and its PropertiesDiscrete Memoryless ChannelContinuous and Analog ChannelJoint TypicalityChannel CodingSummaryOutline1.Channel Capacity and its Properties2.Discrete Memory