化工原理 习题解答(管国锋 第三版)第五章.docx

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1、第五章习题答案5-1解：冷凝器真空度为90kPa绝对压强：10L3-90=lL3kPa,该压强下二次蒸汽温度7； =47.3加热蒸汽绝压300kPa,对应温度T=133.3查NaOH溶液杜林图，50%NaOH溶液在11.3kPa下沸点84A =84-47.3 = 36.7 pm = p +1.3 + 1x1500x9.81 x2 = 26.0kPa查。，极=63.9 C = tpm -tp =63.9-47.3 = 16.6取解=1 = A + + A = 36.7 +16.6 +1 = 54.3 t = TK+ = 47.3 + 54.3 = 101.6 Ar = 133.3-101.6 =

2、 31.7 冷凝器真空度为30kPa,绝压10L3-30=7L3kPa,对应二次蒸汽温度，=90.3 查50%NaOH溶液在7L3kPa下沸点131Ar = 131-90.3 = 40.7 pm = p + p g/ = 71.3 + x 1500 x 9.81 x 2 = 86kPa查 =95.1C = 95.1 90.3 = 4.8 = + + A = 40.7 + 4.8 + 1= 46.5 t = TK+A = 90.3 + 46.5 = 136.8 T = 133.3 所以传热无法进行。5-2解:加热蒸汽绝压：10L3+196=297.3kPa查得 T=133, 7 = 2196%/

3、kg水溶液103,汽比热2251。/依，按/ = 2251ZJ/依原料液比热取3.90Q = KS(T-t) = wf + FC/ti-t()KS(T-t-FC St.-Qw =_ 930 义 50 ,(133 103) x 3600 /1000 2700 x 3.90 x (103 15)-2251= L820xl03%g/X-舞联“X-舞联“Dy 二KS(T -t) 930 x 50x(133-103)r= 2.32xl03%g/。21695-3冷凝器内二次蒸汽绝对压强101.3-79=22.3kPa查 T = 61.6, / = 235QkJ/kg0.150.150.35)=511 Ak

4、g/hw=F(l-) = 1000x(l- Q = KS(TtJ = Wt = T + A = 61.6 + 8 = 69.6 Tf +也KS5714X2350 xlOOO=69.6 + 二930x10=109.7查该温度饱和蒸汽压强P=143kPa5-4计算各效蒸发量、各效溶液浓度、温度差损失、有效传热温度差w =尸(1 工)=22700x(1-) = m6Qkg/h当0.5并流加料，设W：叱：% =1:1.1:12 那么叱=J-X18160 =5503Zg/。3 7W2 = Ux 18160 = 6053 左g/暝18160 = 6604/?3 Fx() 22700 xO.l niM =

5、0.132,F-W1 22700-5503=0.204_ Fx。 _22700x0.1% F-W-W2 22700 -5503-6053x3 = 0.50查 A；=6A；=0A；=l查 A；=12A；=0A；=l查 A；=38A；=0/A = Ai +A2+A3 =(6 + l) + (12 + l) + 38 = 58C加热蒸汽压强500kPa,查I； = 152 末效二次蒸汽压强14kPa,查看=52= 152-52-58 = 42。估算各效有效温度差及各效二次蒸汽温度、溶液温度11/K,1 i r-H1K K. K.28405491,1,128402840 1700 1135=8.11m

6、 = _.npo= 13.6 112840 1700 1135Aq =42 8.1 13.6 = 20.3那么 7； = 152 ct =7； M =152 8.1 = 143 .9= -A. =143.9 6 1 = 136.97； =136.9 t2=T2-At2 =136.9 13.6 = 123.3 CK = T2-A2K = T2-A2= 123.3-12-l = 110.37； =110.3 4 =4纯=110.3-20.3 = 90 = 90-38 = 52 JJ热量衡算:y.尸 Coo 4)W =。 + P1 I tr/i八n 22700x4.19x(40-143.9)=D +

7、12326=R 4249二叱Z1 （尸一叱）。（乙一 %） 1% a(22700 叱)x 4.19 义(143.9 123.3)1 +2326=叱 + (22700WJx 0.0371 =0.963W. +842(F-W,-W2)CpO(t2-t=wA+ -3(22700 - W2) x 4.19 x (123.3 - 90)TT 0 I3）2326二阴 + (22700-18160+WJx 0.0600即0.94W3=暝 + 272 JJA =A2 =4 =取（1）、（2）、（3）和叱+弘+叱=18160解得2 =9649 左g/九叱=5400Zg/z, 暝=6042Zg/z, 叱=6718

8、Zg/z 计算各效面积：Dy 9649x2326x1000/42上=/3600 = 271MKM2840x8.1叱片 5400x2326x100%600 _”,K2At.1700x13.6_ 6042x2326/00%600 76MKM1135x20.3各效面积不等，重新分配有效温度差:A. Aa +1144J J271x8.1 + 151x13.6 + 169x20.3 1OO 2二 18342AA= 271x8,1 =12oc183NM 151x13.6=1 1.2 C1834 侬 33 =c183重算各效温度：T； = 52 t3 =小A3 =52 + 38 = 907； =，3+A，3

9、 =90 + 18.8 = 108.8(=108.8 = + , =108.8 + 12 + 1 = 121.8 4/4T? j+A2=121.8 + 11.2 = 133 7；= 133 0c八=l+A =133 + 6 + 1 = 140 7；=4 +八4=140 + 12 = 152 重新热量衡算：=2 +22700x4.19x(40-140)=2 40892326W2叩+(b一WJxCp。(140-121.8)=0.967 叱 +7442326F-Wx -W2)x4.19x(121.8-90)2326=% +(22700 叱 一 %) x 0.057又叱+%+吗=18160解得:解得:

10、D = 9551k g/h,W2 = 6026kg/h, 重算各效面积：叱=5462kg/hW. = 6672kg/h。名KM%MM二悬9551x2326/上=181.1疗2840x12.05462 x 232匕= 185.3m21700x11.26026x2326/= 182.5m21135x18.8相差不多，不再重算，取平均值:A=4+4+AJ8L1 + 185.3 + 182.5= 183 加 25-5 解: b= 14xll58 = 1621g/zW =/(1 9) = 16212 x (1竺)=S106kg/hx20.5设叱：% :优：%4.11.1424.11.142W = 193

11、0kg/hW = 223kg/h= 1930kg/h= 223kg/h=0.396_7%_16212x0.25” -F-W1-W4-W3 - 16212-1930-1930-2123 x2 = 0.5016212x0,25 =Q284F-W, 16212-1930=0.333=0.333Fx. _16212x0.25F-W.-W, -16212-1930-2123查图： %1 = 0.396 ； =4.5x2 = 0.50 ； = 7.2 =0.284 ； = 2.7 x4 = 0.333 A； =3.1 A = 4.5+ 7.2 +2.7+ 3.1+ 1 + 1+ 1 + 1 = 21.5查

12、 7； = 133.7 查看 = 63.5C1 加= (2-*)-加热蒸汽绝压：202.6+101.3=303.9kPa,冷凝器二次蒸汽绝压：10L3-76=25.3kPa,Z4 = 133.7 -63.5- 21.5 = 48.7 11111 1 1111-111& K2 K. K4 810 1160 1160 1280JJ_AA =Jxa%= 81 x48.7 = 16.1 0.00374 J 0.003741= 116 x48.7 = ll.2C0.00374A =112 、J1Al = 1280 * 48.7 = 10.2 4 0.00374 =133.7 t =133.4-16.1

13、= 117.37；=117.3-4.5-1 = 112.1CT2 =112.1Z2 =112.1-11.2 = 100.91 = 100.9-7.2-1 = 92.7T3 = 92.7 t3 =92.7 1L2 = 81.581.5-2.7-1 = 77.8。T4 =77.8=77.8-10.2 = 67.6 * = 67.6-3.1-1 = 63.5 查汽化热：7 =133.7 % =268kJ/kg f y = 2227 kJ/kg4 = 92.7 % =2277kJ/kgT； = 77 f 八= 23lkJ I kg* = 63.5f 片= 2347。/依叱=2区=。 = 0.974。1

14、12227片（尸的一 WC小暝鼠-，）亿2） W,1a%片（尸的一 WC小暝鼠-，）亿2） W,1a%2227=叱+227716212x3.77 (咪 +% +%)x4.193(117.3 100.9)2277=0978叱 +440-0.0302(W( +吗 +M) =0978叱 +440-0.0302(8106 用)0.97 阴=0.978吸 +195-W3=w2 = w222772311=0.985%（万。一叫。小,）（4一e 2311 (16212 x 3.77 忆 x 4.19) x (81 .5 67.6)=用 x+3 23472347=0.96% + 362又叱+%+暝=8106解得：D =1857kg/h W. = 1809kg/h W2=2Q25kg/hW. =995kg/h 也=2277 奴/z4 H J857X2168/3.6 =85 8/K4 810x16.14二见-KMKZK3M1809x2227/3.6 7=86.1160x11.22025x2277/3.6，2=98.6m1160x11.21995x2311/3.6 no 2=98. lm1280x10.2去平均值.85.8 + 86.1 + 98.6 + 98.1 C与?A = 9277r