机器人学基础-第7章-机器人轨迹规划-蔡自兴.ppt





《机器人学基础-第7章-机器人轨迹规划-蔡自兴.ppt》由会员分享,可在线阅读,更多相关《机器人学基础-第7章-机器人轨迹规划-蔡自兴.ppt(53页珍藏版)》请在淘文阁 - 分享文档赚钱的网站上搜索。
1、中南大学中南大学蔡自兴,谢蔡自兴,谢 斌斌zxcai,2010机器人学基础机器人学基础第七章第七章 机器人轨迹规划机器人轨迹规划1Ch.7 Trajectory Planning of RobotsFundamentals of RoboticsCh.7 Trajectory Planning of Robots 2Ch.7 Trajectory Planning of RobotsCh.7 Trajectory Planning of Robots 3Ch.7 Trajectory Planning of Robots7.1 General Considerations in Traject
2、ory Planning 轨迹规划应考虑的问题轨迹规划应考虑的问题Basic Problem:Move the manipulator arm from some initial position to some desired final position(May be going through some via points).47.1 General considerations7.1 General Considerations in Trajectory PlanningTrajectory:Time history of position,velocity and acceler
3、ation for each DOFPath points:Initial,final and via pointsConstraints:Spatial,time,smoothness57.1 General considerationsJoint spaceEasy to go through via points(Solve inverse kinematics at all path points)No problems with singularitiesLess calculationsCan not follow straight lineCartesian spaceWe ca
4、n track a shape(for orientation:equivalent axes,Euler angles,)More expensive at run time(after the path is calculated need joint angles in a lot of points)Discontinuity problems6General Considerations-Solution Space7.1 General considerationsCartesian planning difficulties:7General Considerations-Sol
5、ution Space7.1 General considerationsInitial(A)and Goal(B)Points are reachable,but intermediate points(C)unreachable.Ch.7 Trajectory Planning of Robots 8Ch.7 Trajectory Planning of RobotsJoint-Space SchemesEach path point is converted into a set of desired joint angles by application of the inverse
6、kinematics.A smooth function is found for each of the n joints which pass through the via points and end at the goal point.Time required for each segment is the same for each joint.The determination of the desired joint angle function for a particular joint is independent with other joints.97.2 Inte
7、rpolated Calculation of Joint Trajectories 关节轨迹的插值计算关节轨迹的插值计算7.2 JointSpace SchemesChoice of interpolation function is not unique!10Joint-Space Schemes 7.2 JointSpace SchemesSeveral possible path shapes for a single joint.Some possible interpolation functions:Cubic polynomials Cubic polynomials for
8、a path with via pointsHigher-order polynomials Linear function with parabolic blendsLinear function with parabolic blends for a path with via points11Joint-Space Schemes 7.2 JointSpace SchemesIn making a single smooth motion,at least four constraints on are evident:127.2.1 Cubic Polynomials 三次多项式插值三
9、次多项式插值7.2 JointSpace SchemesCombining the four constraints yields four equations with four unknowns:137.2.1 Cubic Polynomials7.2 JointSpace SchemesThese four constraints uniquely specify a particular cubic:147.2.1 Cubic PolynomialsThe joint velocity and acceleration along this path are:7.2 JointSpac
10、e SchemesEg.7.1 A single-link robot with a rotary joint is motionless at =15 degrees.It is desired to move the joint in a smooth manner to=75 degrees in 3 seconds.Find the coefficients of a cubic which accomplishes this motion and brings the manipulator to rest at the goal.Plot the position,velocity
11、,and acceleration of the joint as a function of time.157.2.1 Cubic Polynomials7.2 JointSpace SchemesSolution:Plugging 0=15,f=75,tf=3 into(7.6),we find167.2.1 Cubic Polynomials7.2 JointSpace SchemesSolution:177.2.1 Cubic Polynomials7.2 JointSpace SchemesStarts at 15 degrees and ends at 75 degrees!Sol
12、ution:187.2.1 Cubic Polynomials7.2 JointSpace SchemesStarts and ends at rest!Solution:197.2.1 Cubic Polynomials7.2 JointSpace SchemesAcceleration profile is linear!If we come to rest at each pointuse formula from previous slideor continuous motion(no stops)need velocities at intermediate points:Init
13、ial Conditions:207.2.2 Cubic polynomials with via points 过路径点的三次多项式插值过路径点的三次多项式插值7.2 JointSpace SchemesSolutions:How to specify velocity at the via points:The user specifies the desired velocity at each via point in terms of a Cartesian linear and angular velocity of the tool frame at that instant.T
14、he system automatically chooses the velocities at the via points by applying a suitable heuristic in either Cartesian space or joint space(average of 2 sides etc.).The system automatically chooses the velocities at the via points in such a way as to cause the acceleration at the via points to be con
15、tinuous.217.2 JointSpace Schemes7.2.2 Cubic polynomials with via pointsHigher order polynomials are sometimes used for path segments.For example,if we wish to be able to specify the position,velocity,and acceleration at the beginning and end of a path segment,a quintic polynomial is required:227.2.3
16、 Higher-order polynomials高阶多项式插值高阶多项式插值7.2 JointSpace SchemesWhere the constraints are given as:237.2.3 Higher-order polynomials7.2 JointSpace SchemesSolution to these equations:247.2.3 Higher-order polynomials7.2 JointSpace SchemesLinear interpolation(Straight line):Note:Although the motion of each
17、 joint in this scheme is linear,the end-effector in general does not move in a straight line in space.257.2.4 Linear function with parabolic blends 用抛物线过渡的线性插值用抛物线过渡的线性插值7.2 JointSpace SchemesDiscontinuous velocity-can not be controlled!To create a smooth path with continous position and velocity,we
18、 start with the linear function but add a parabolic blend region at each path point.Constant acceleration is used during the blend portion to change velocity smoothly.267.2.4 Linear function with parabolic blends7.2 JointSpace SchemesAssume that the parabolic blends both have the same duration,and t
19、herefore the same constant acceleration(modulo a sign).There are many solutions to the problem-but the answer is always symmetric about the halfway point.277.2.4 Linear function with parabolic blends7.2 JointSpace SchemesThe velocity at the end of the blend region must equal the velocity of the line
- 配套讲稿:
如PPT文件的首页显示word图标,表示该PPT已包含配套word讲稿。双击word图标可打开word文档。
- 特殊限制:
部分文档作品中含有的国旗、国徽等图片,仅作为作品整体效果示例展示,禁止商用。设计者仅对作品中独创性部分享有著作权。
- 关 键 词:
- 机器人学 基础 机器人 轨迹 规划

限制150内