Solidworks有限元分析教程.ppt
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1、有限元分析用户培训有限元分析用户培训Jim.YueDDS Software Co.1目目 录录企业需求与有限元分析企业需求与有限元分析Design Analysis更少的样机:省钱更短的周期:省时更好的质量:品质有限元分析的主要步骤有限元分析的主要步骤前处理建立分析对象的有限元模型求解对有限元模型的计算工况进行求解后处理观察分析结果,评估设计是否符合要求Cosmos/Works有限元分析的步骤有限元分析的步骤1.建立几何模型2.定义材料属性3.定义边界条件(约束和载荷)4.划分网格5.求解6.查看和评估结果修改,重新,细化Cosmos/Works的用户界面的用户界面Cosmos/Works的工
2、具条的工具条定义、修改、删除专题定义材料生成有限元网格对当前专题进行计算在几何模型/有限元模型之间进行切换显示从所选的特征中选择面元Cosmos/Works的选项对话框的选项对话框Cosmos/Works线性静力分析线性静力分析例1.支座分析例2.轴承载荷例3.壳单元,静水压例4.Motion,远端载荷线性静力分析:定义专题线性静力分析:定义专题Displacement in the radial direction:Select“Axis1”and then define displacement plot in X-direction(radial to the axis).Select
3、deformation scale=1Right-click on the displacement plot icon“plot2”and then select”List selected”-Average displacement of“pole piece lower”=-0.0019504”(decrease in radius)-Average displacement of“pole piece upper”=0.007896“(increase in radius)-Sum of these 2 displacement=0.009846”Initial interfernce
4、 of 0.01”Hoop Stress(tangential):Select“Axis1”and then define stress plot in Y-direction(radial to the axis).Select deformation scale=1Right-click on the stress plot icon“plot2”and then select”List selected”-Negative stress on“pole piece lower”(compression)-Positive stress on“pole piece upper”(tensi
5、on)线性静力分析:定义材料属性线性静力分析:定义材料属性Simulate parts which are separated by large gapsFirst run the model with small displacement option and look at the results If you see that there is a change in the orientation of the contact surfaces during loading or if the results doesnt look realistic,use large deflec
6、tion optionExample 1Example 1Example 2Example 2线性静力分析:网格划分线性静力分析:网格划分Open“RectangleGap.sldasm”Define a static study“smallcontact”Apply material“Alloy steel”to both partsApply a pressure of 725 psi on the top faceSelect the two front faces and then apply restraint.Select Flat face option and then sel
7、ect“Normal to face”Fix the left semi-circular faceHide the loads/bc symbolsDefine“Surface”contact between the top face of the bottom leg and the perpendicular faceCreate mesh and runDefine a stress plot with scale factor=1.Look at the contact surface.This problem requires large This problem requires
8、 large displacement nonlinear contact!displacement nonlinear contact!线性静力分析:定义约束线性静力分析:定义约束Define a new static study“LargeDisp”Dragn drop the material and loads/bc folders from“small contact”studyRight-click on the study name and click on properties.Select“Large displacement contact”option.Run the a
9、nalysisDefine a stress plot with scale factor=1.Look at the contact area.Looks real!Looks real!线性静力分析:定义载荷线性静力分析:定义载荷Simulate heat resistance between parts for thermal analysis Account for heat resistance of thin parts without actually modeling them!Define thermal conductivity at the contact area to
10、 model the properties of the glue between the chip and the substrate线性静力分析:求解线性静力分析:求解Open“Thermal contact resistance_transistor.sldasm”Explode the model and set preferred units to“SI”and temperature units to“Kelvin”Define a thermal study“NoRes”Apply material“AISI 304”for“Voltage regulator”and“Coppe
11、r”for Heat sinkDefine“Surface”contact with No resistance between the contact facesApply convection to all the faces of the model except the contact facesFilm coefficient=250 W/(m2.K)Bulk temperature=298 K线性静力分析:观察结果线性静力分析:观察结果Apply Heat power=25 W for“Voltage regulator”Mesh with default settings and
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