西方经济学微观部分第三章课后习题答案之欧阳数创编.pdf

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1、 2021.03.02 1.8020MRSMRS Y XPX MRSXY=20 0.250.25o2.3-1(963-22)01231E1P2(1)(2)2(3)(4)(5)(1)130P2M2X 30=60(2)2206023(3)(1)(2)23=602(4)(3)9 20(5)MRS2=PlPl P1 9 3.BC(1)A(2)B(3)C12(4)D(1)AAA3-2(a)32(2)BminU，B 3-2(b)o(3)CC32(c)o(4)DD3-2(d)o324.33 333-3ABAB 12x*x3-3ABEoFX,xj,GUXU2o5.12540Pi=2030U=3XX2,MUI

2、P1 MU2=P2 U=3XX2dTU dTU MU=dX =3X2 MU2=6X1X2 X(1)(1)20X30X?=540,4 20+30 -=540 X=9 Xx=9Xs=12 X*=9*=12 U*=3X*(X8)2=3 X 9 X 122=3 888 3 888o6.A.Qd=20-4PQB=30 5P(1)(2)(1),(1)AQ4=20 4P,ABQB=30 5P,BAB+6B=(204(30 5P)=50 9/=50 9P3APQ020116212 384450B PQB030125220315410556()PQd=Q eq oalC*,A)+QeqoaI(d,B)05014

3、12323234145560(2)(1)33-434 P=5Qd=5PW5P5PW5Qd=Q eq 031(+Qeqoal(；J=50 9PP5Qd=Qeq oal(d,B)=30 5Po 7.U=xeq f(3,8)eq f(5,8)2,Mo12eq f(MUn MU2)eq f(Px,P2)U=xeq f(3,8)eq f(5,8)i MUx=M，eq f(rfTU,dxj eq f(3,8)x-eq f(5,8)eq f(5,8)2 MU2=m，eq f(rfTU,dx2)eq f(5,8)xeq f(3,8)Xx eq f(3,8)eq f(f(3,8)x f(5,8)1Xf(5,8)

4、2,f(5,8)xf(3,8)1X f(3,8)2)eq f(Pi,P2)eq f(3X2,5xJ eq f(Plf P2)X2=M/eq f(5PN,3Pj PN+P?XM,PiXx+P2 M，eq f(5P，3PJ=M xeq oal(*,J eq f(3M,8P J xeq oal(*,2)eq f(5M,8P2)O eq blc rc(avs4alcol(xoal(*,1)=f(3M,8P0 xoal C,2)=f(5M,8P2)8.M,Pt P2o 8MRS12=_eq f(6&2,dci)=a,eq f(P“P2)35MRS12 eq f(PPjap eq f(Pb P2)35(a

5、)Ex eq oal(,J eq f(M,Pj x eq oal(*,2)=01,35 MRS12 eq f,Pj aMz eq f(PPj35(*)Ex eq oal(,J=0,x eq oal(,2)eq f(M,Pj2,MRS2=eq f(PPja=eq f(Px,P2)35(c)x eq oal(,J20,x eq oal(,2)$0,PIX1+P2X2=MO9.U=q05+3M,q M(1)(2)p=eq f(1,12)q=4(1)MU=M，eq f(a：,=0.5qf X=eq f(dJ,dl)=3 eq f(MU,p)eq f(0.5qf,p)=3 q=eq f(l,36p)(2

6、)q=eq f(l,36p2)p=eq f(1,6r(q)(3)p=M，eq f(l,6r(q)j eq oalC,0)eq blc(rc)(avs4alcol(f(1,6r()Aq pq eq f(l,3)qeq f(1,2)eq oal(g,o)pq=eq f(l,3)q eq f(l,2)pg peq f(l,12)q=4CS=eq f(l,3)X4eq f(l,2)eq f(l,12)X4=eq f(l,3)10.U=xy,xyPy,，a0a+0=1(1)xy(2)xy(3)0 xy(1)U=xayeq blc rc(avs4alcol MUX=f(d dx)a x r y MU7=f

7、(dU,dy)=y)+Eeq blcrc(avs4alcol(f(W,MLQ=f 2)Rx+E(2)eq blcrc(avs4alcol(f(axyf Bxf,P)(3)36(3),x=Q.(4)y=B M/Py (4)(5)xy3-6(2)yA Pxx+Apyy=A#(6)Aeq blcrc(avs4alcol(f(ax Pxx+A PyA M)(7)HO,(7)eq blcrc(avs4alcol(f(ax y,0yyr)=f 2)(8)(8)(3),(4)(3)(5),a=/W9)0=10)(9)(10)y11.H=4,A=2,8012(1)1H1(2)11 (3)1137374,=2A

8、B,R=2,A=2ABr ba37(1)aoMRS12 eq f(PP2)MRS12=m，eq f(MUMUj eq f(X?,Xj eq f(Pb P2)eq f(4,2)=2,eq f(X?,Xj=2,Xeq f(l,2)X2OXx=M，eq f(l,2)X?4Xi+2X2=80,4 eq f(1,2)X2+2X2=80 X2=20 Xi=10 UXN=10X20=200 b1P=2eq f(PP eq f(X2,Xj eq f(2,2)X=X2oX2X2X?=80,X20,X2=20Oab14X1=20 10=10,P1(2)ABFG,cc,MRS12=M，eq f(PPjeq f(X2

9、,Xj eq f(2,2)Xx=X2o XU=XN=200,X=14,X2=14(ac14X1=14 10=4,1(3)cb14X1=2014=6,Pi1410AX,=4 6 12.5%10 00095%10509.5509.510 000X5%+10X95%=509.5509.513.(2)eq f(MU,P)(1)14.MRSeq f(PPj(2)MRS12=m，eq f(Pb P2)eq f(MUPj eq f(MU2,P2)(3)(2)3-8(5)38(4)(3)38(15.(2)3-93-91)b39 AB cbc(1)AAB.c3,FGABcbH(3)(4)(3)3-9 bc(3)2021.03.02