山东省滕州市2022-2023学年高二上学期数学期末考试试卷含答案.pdf

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1、保密启用前保密启用前 高二年级质量检测(2,5,8)=a(3,4,4)=b+=ab(5,1,4)(3,9,12)(1,1,4)(1,9,4)22154xy=1236(2,3)A:2470lxy+=240 xy+=270 xy+=210 xy=280 xy+=na122aa+=564aa+=910aa+=2468220 xyDxEyF+=22(40)DEF+yx=0DE+=DE=DF=EF=山东省滕州市2022-2023学年PABCDABCD1PA1PAABAD60MPC|BM=33343234na1211nnaan+=110a=na1514116()222210 xyabab+=1F2F1FA

2、B2ABFI2345IBIAIF0+=55233412)32(+=+ya x()aR(2 3)，21yx=y1320 xy+=60(13)，20y=1MDCBAPnannS10a 0d 59SS=14S59SS=7SnS67SS78SS67SS56SSPABCDABCD2PA ABCD2PA=EFGABADPCAG PBDFGAB4TPBD2TA TG+=TEFGPABCD2 26+C22ypx=(0)p O225xy+=AB|4AB=lCFCMNl33|8MN=|2|MFNF+32 2+MFy6(0,)2M32(2,2)GGFM35+na22a=48a=na55S=(1,1,1)=a(1,0

3、,1)=b(1,2,)m=cm=22(1)1xy+=22106180 xyxy+=ABCD22:163xyC+=CABCDC22450 xyx+=AB(3,1)PABnSnan0na nanS2nana2,1,nnnnanbna a,.+=为为奇奇数数为为偶偶数数 nb2020T111ABCABC1AA ABCABAC11ABACAA=M11AC1BMAB1ABBCM41ABCMPABCDCDPADPADADBC22ADCDBC=EFPDPBAEFPADPCGDGAEFGCAA1C1B1BMCABPDEF1na2420aa+=38a=nambna*(0,()m mNmb5050S222:1(1

4、)xCyaa+=1F2F2FxP121sin3PFF=C1(0,)3Skl,A ByMABMxyF1F2OP高二年级质量检测 2511y=4390 xy=24710 xy+=（答案不唯一）229xy+=;18C22450 xyx+=22(2)9+=xy(2,0)C3r=ABCP1 0132CPk=1ABk=AB1(1)(3)yx=40 xy+=22nnnSaa=+1n=2111122aSaa=+0na 11a=2nnN22111222nnnnnnnaSSaaaa=+221111()()nnnnnnnnaaaaaaaa=+=+10nnaa+11nnaa=na11nan=2111 11()(2)2

5、2nna an nnn+=+2013192420()()Tbbbbbb=+1 111111(1 319)()2 24462022=+10(1 19)111()22222+=+510022=+220522=1AA ABCABAC ABC1AAAB1AAACABAC1(0,0,1)A(1,0,0)B1(1,0,1)B(0,1,0)C(0,1)Ma(0,1)a(1,1)BMa=1(1,0,1)AB=11 10 1 10BM ABa=+=1BMABBCM(,)x y z=n(1,1)BMa=(1,1,0)=BC00BMBC=nn00 xayzxy+=+=1x=(1,1,1)a=n1ABBCM4111|

6、cos,|ABABAB=nnn222|1 1|22211(1)+=+aa12a=1(1,1,)2=nCAA1C1B1BxyzM1(1,0,1)AB=1ABCM12221|1|123111()2|=+ABdn|nADOOPOBABCD/ADBC2ADBC=ODBCODBC=OBCD/OBCDCDPADOAOPPADCDOACDOPOBOAOBOPPADOADOPOAOOAOBOPxyz(1,0,0)A(0,2,0)B(1,2,0)C(1,0,0)D(0,0,3)PCABPDyzxEFO13(,0,)22E 3(0,1,)2F33(,0,)22EA=1(,1,0)2EF=AEF(,)=x y zn

7、0,0.=EAEFnn330,2210.2=+=xzxy2x=(2,1,2 3)=nPAD(0,2,0)DC=mAEFPAD|17cos|cos,|17=m nm nmnAEFPAD1717G),2,3(PGPC=0,1(,2,33)G(1,2,33)DG=+DGAEF2(1)22 3(33)0DG=+=n4=5PCGDGAEF45PGPC=na11aq31121208a qa qa q+=12=a2=q132=a12=q2nna=2nm2lognm1m=10b=12,21)kkm+mbk=kN12345732335050()()()=+Sbbbbbbbbb0 1 22 4 3 8 4 16

8、5 19=+193=0(,)P c y221ac=+201|PFya=2112|1sin|3PFPFFPF=13|PFa=21|2PFPFa+=132aaa+=2a=2212xy+=l13ykx=221312ykxxy=+=22416(21)039kkxx+=11(,)A x y22(,)B xy12243(21)kxxk+=+122169(21)x xk=+222166464(12)160999=+=+kkk(0,)Mm11(,)MAx ym=22(,)MBx ym=0MA MB=1212()()0 x xym ym+=1122)11(3()30 x xkxm kxm+=22121211(1)()()()033kx xkm xxm+=222216141(1)()()09(21)33(21)3+=+kkkmmkk2226(1)(325)0mkmm+=k210m =23250mm+=1m=(0,1)MAB