江苏省常州一中2019届高三11月第一次练习数学理试题.doc39365.pdf

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1、-1 2019112019.11.3145701.A=0,1,3,B=a+1,a2+2A B=1a 2P X，R,X?2P3510 xP(m,2)m=_ 41nx 2X-10X0 X。3 tan A 5.ABCA,B,Ca,b,ca cos B-b cos A c y=_ 5 tan B 1 a 6.a x 2x c c8 x 72tan=2cos-2&a,blog2a+log2 b A13a+9b1 90Wx2，4xclogaXa10f(x)=x3-3ax(a R)x y=0Ry=f(x)a 11Ax|x2-5x 4 0,Bx|x2-2ax，a 2 0?BAa n*nanAkAki1,0an

2、tankk3n.12AAny=f xn(nN*)13 nn 1(n _ 2)n111111111,n(n_3)31 2 2 2 3 6 3 4 12 1314f(X)=JX(ex c1)M(tf(t)11yy1 P,QN 0,1 PQNbMb6902 5 f(x)=cosx(asin xcosx)+cos x (I)f(x)(n)ABCA,B,Ca,b,cac b f(x)0,B1a2+b2_c2 2a _c16ABCM,NAB,ACMNA BCG M G A 2 15a R fA-3 3 3 1AAMGANG3,S22y 1-Si S2 17.2a140v 2a v 420ab.10.01

3、b0.4 b3 4 18Snn 1S4,S10,S7a1,a7,a4 2S3S6-n2bn 19annSnSna Sn-an 1 aa 1,a=0-4 1an2 2bn-Snan0332G=4an 1cnnTi 12k2n-7nN k4 n-Tn 5 20f(x)=ax_lnx 1(a R)g(x)xe1(I)g(x)(0,e(n)ax0 (0,e1,ex/i=1,2)f(xjg(xo).ay=F(x)A(x1,y1),B(x2,y2)y=F(x)M(Xo,yo)(Xo=x1 QX2)F(xJ-F(X2)=F(x)(x1-x?)L f(x)L.20192019.11.3 10 2-X R,x2

4、 _2 3-2.3 3 a 1 f(-3“f(0)2 2a3.f(x)=.3sin 2x-cos2x=2sin(2 x).6 JI 31 JI TC 31 2k2x 2k;k Z x，k Z 2 6 2 6 3 JI 4-243556 4 7 8189 5 1 f 18 10a-11-1，_12 3 17 15：(I)f(x)=asinxcosx-cos2x sin2 x a.sin 2x-cos2x.131|!14 1 4 27 3-6 f(x)+k+k(kZ)!6 3-7 (n)2 2 2a c-b 2accosB ccosB c2 2 2 a b-c 2abcosC bcosC 2a _

5、c2a cosB-ccosB=bcosC 2si nAcosB si nCcosB s in BcosC=s in B C=si nA cosB=,B=XE 0,I2x I,2 3 i 36 62 f(X)0,B-1,21 GM GA 3 GM IE IE/JC sin sin6s in(:6 6 6 s=12sin(：6 1,1 144 2/|2/2 y 2 2 2sin sin y1 y2 sin a 6 6 72 3 COt 2 yymax2403 3 3 3 yymin 2162 17Xyy=(2a _x)(b 0.01bx)-0.4bx x2-2(a-70)x 2ab 100 3 a

6、 2a-x 2a 0：x=140：2a：420,70：a：210.4 2 0 a-70，70：a 140，x=a-70,y 2 f x1,2 161G1ABCAG MA(6S1 GMGAin 2 si not 12sin(：6-8 a-70，140:a 210,X,y 2 2 70 a?140,a-70,140 a 210,a，18 1anqS4 S10S7q=1200 S4 S7 -9 2a1 1 _ q _ a1 1 _ q a1 1 _ q 1-q 1-q q=01 q3=2q6 a-a1q a-i,a7,a4 1-q-2a1q6a1 a4 S3S6a-q6 21 1-q 一16 3 7

7、 1 1 q3 q a2 8 2 2b n Nbjr 1$bn+bn21 i(nc2 l 2i 2 18 1anqS4 S10S7q=1200 S4 S7 -10 62:2n 1n N n(2n 1)2n 6(2n-1)2n 1,-1 n(2n 1)2n(2n 1)2n 6 10 3”：10-1：；：103 3 10 19(1n=1 S=a(S ai+1)=1 2 Si-a Sn-an 1 i1-aSi-aan a 1-a Snj=-aan a 1a an=-aan aan 1a.=aan 4,anan 4 11 .:an 2(21bn=ana 1-an+1-a anb,a2n-an2a2n1

8、 1-a(bn?b；bi b3bi=2a2,b23=a 2a 1,b3 4 2=a 2a a 1，a3(2a+1=(2a2)a4 2a2 a 1a=；abnbn=()bn”2 bn 2(3-Tn n=4 n 4 2n，t”73k2n dn 7dn1-dn2n 5 2n 7-2n 9 2n 2n 4dn 1 dnn _4 dn 1：d n d4 1,d5 16 3 3 1 d4 wd53k k 3.32 32 32 1-12 20(i)g(x)e1*-xe1=e1_x(1-x)(0,11,e)，g(0)0,g(1)=1,g(e)=e2 0(0,1(n)mg(x)(i)m (0,1m (0,1 f

9、(x)=m1,e f(x)1,e 1 f(x)=a(1 x _ e)x 1 a0，f(x)a 0,1,ex a-1，f(x)-0,1,e1-13 0：a，f(x)：0,1,e e 1 1 1 1 1 ea：1，1,-；,ea a 1 1 0 f(X)min=f()=2 n a 0 a-a e MkAB0:：Xi:：X2 In In x2 -a 1 2f(x)MXi X2 2%_x2 Xi 2(%_%2)x2%+x2 X2 Xi 2(1-1)tX1 1 X2-2,F(t):F(1)=0 4 X2lntfr0Xi 1 F(tt 4 lnt 2=0f(x)L t+1 0F(t)(0,1)(t 1)2 t(t 1)a 1 a(-,1)f(x)ea-af(x)L F y2 _a(X1 X2)-(In Inx2)kAB _x2 Xi X2 f(Xo)=f(-)x22=a-x1 x2