洞口三中高三文科数学2019年11月月考试题39083.pdf

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1、201911 1y=sin（4x2JTD.x=-12 2 2 7y2=2px1U p6 2A 2 B2 C4 D48l112I1/I2（）AI1/r i2Bh _ 2 Cl1/ri2 Di2 JTA.x=6C2800160320200120D8,16,10,6 3 11,12,13k1,k2,k 3,A.k 2k1k3 B.k 3k2k1C.k 2k3k1D.k1k3k 4l1：(3 a)x 4y=5-3a l2:2x(5 a)y=8aA-7-1 B 71 C-7 D-15f xR,XQf xU f（2）,f f（3）(Af f(_3)f(-2)(Bf(J f(_2)f(-3)(C)f(v f

2、(-3)v f(-2)(D)f(v f(-2)v f(-3)60NPABC|OAOB OC|NB NCPA P B P B PC PC,ONPABC ACB D A1224159B912127C815125 9S10-xw R,2x2-3x 4 0 x,-1,0?,2x 1 0 x N,x2 x-lx N,x2911S-ABCESAFAABCEFABC12CT2cos v-4si nrC13C1,0 xI y=x-12C 0 18ABCD PBAD=90o,AD BCAB=BC=aAD=2a PAABCD PD30oAE _L PD E(1)DPBC(2)BE PD (3)AECD19.12S

3、 Snann(n N*)Sc an 2bn24bn CnGd(d=0)Cnd2 2 20E:$=1(a b 0)FF2Pxa b(I)EP(I)M(n)MyE3 PFiE Pi2 PF2 (n)PF?E2 2 X y GC:r 2=1(m n.0)FCm n GFC,X 1=In x-1 X+1(I)f(X)In D x1 x1 m(n)x2,6 f(x)=ln In m x1(x1)(7x)*2 nNf(2)f(4)f(6)f(2n)2n 2n 201911/2 2 2 2 2(x-1)(y 2)=5(x-3)y=4 k Y T k 1 16：(I)f(x)msinx cosx(R)21f(

4、x)n,1,msi n cos 1 m=1 f(x)sirx coxs2 sXn()2 2 2 4 T=2x 2k(k：=Z)f(x)24 5:x 2k(kZ)f(x)-“2 4 BC2=AC2 AB2-2 AB AC cosA=7 BC 7 17(I)A=-2,0,1,3,M(x,y)xyA,M 4 4=16(-2,-2-2,0-2,1-2,30,-20,00,10,3 1,-21,01,11,33,-23,03,1(3,3)n)My12-2,-2-2,0(-2,1-2,3(1,-2),1,01,11,33,-23,03,1(3,3MyR=12 316 4x y-5：0IMx 0 31,11

5、,33,1 y 0 MF2 31618AAFFB,FFAAC,FABC,BCAB,BCFAB,BCAF,AFFBC,AD BC,DFBC23 J21 2/7AFBCAFFA=a，FB=a,AF=a,3 3 7t DFBCaFAAC,ABAD=ABFD,FDAE=PD7 ABE=FDBE.AD,DEG,H,HG,BGBG CD,HG AE,BGHAECDAE=a,HG=,BG2a,EH=Da BE2=A+AE=2a2,BH2=BE+EHa2 2 2 2 4/V2 42.cos BGH=-,AECD 4 4(n)f(2 si nA 12、.2 sin =./A3JIA=3；S=1ABL_ACSin

6、 A=33 2 2.AC=3 191)2%242bl=2 4n=2bn=2n-1 20:(I)：PE2a=PF)PF2=4,a=2,1 r GF 2 COR=m OMFF FGbnnTnTnn2T?n=4n?T2n=4bn Tn(2cnnRnkRn(kk=0 CnRn=nGR2n2 c 2n(2 n 1),2(2 d Rn n q.3d 2=k N*(k_4)dn (k _2)(2G _d)=0 cmd=0k=4 d=2Gdci2c!2 5 2/32 2 2 2&V 2PR 12F|F2=|PF2 PF=()2()2=4,2c=2,c=1,b=3.2 2 Ey 14 3 F1(-1,0),F2

7、(1,0)T PR F2 P(-)(n)PF2(y3)225 M 4 16 3 3 M(0,)M(0,)PF2M 4 4 5 r E4 2 y 4 0(0,0)R=2 MO|OM|=3 4=2-$R-r 4 GFCF CI 52m(m 0)GCFC 1”1 OM=GF=m GFR-rGF+GF =2mGFMM x1 21：(1).0X：1x 1 1)U(1,：)X-1 X(-：,-1)U(14)f(_x)=ln _lnf(x)f(x)JnU -X-1 X 1 X-1 X-1 X-1 x+1 m(n)x2,6f(x)=ln.In m x_1(x_1)(7_x)g(x)=(x 1)(7_x)=(x

8、_3)2 16x 2,6x 2,3 x 3,6x 2,6g(x)min g(6)=7 0：m：7 f(2)f f(6)f(2 n)=In -=ln(2 n T)1 3 5 2n1 2 x.h(x)=In(1 x)x)(x 0)h(x)2 2 x x 0 h(x)：0,h(x)=ln(1 x)-(x)(0,：)2 h(x)ch(0)=0 x=2 n n Inlh 2 r)+2(n2 2)0 2.In(1 r2)：n2 n2h(x)=Inx-(x-1)(x_1)，：ln x：x-1 x 1,：)，x=2n 1(n N)，1 n(2n 1)：2n：2n2 2n.x 1 x-1 m(x-1)(7-x)0,；x 2,6 0：m：(x 1)(7-x)x 2,6 2-x-2x x 1