Ch06-Discrete-Probability-Distributions-商务统计学概论(英文.ppt
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1、CHAPTER 6Discrete Probability Distributionsto accompanyIntroduction to Business Statisticsfourth edition,by Ronald M.WeiersPresentation by Priscilla Chaffe-Stengel Donald N.Stengel 2002 The Wadsworth GroupChapter 6-Learning ObjectivesDistinguish between discrete and continuous random variables.Diffe
2、rentiate between the binomial and the Poisson discrete probability distributions and their applications.Construct a probability distribution for a discrete random variable,determine its mean and variance,and specify the probability that a discrete random variable will have a given value or value in
3、a given range.2002 The Wadsworth GroupChapter 6-Key TermsRandom variablesDiscrete ContinuousBernoulli processProbability distributionsBinomial distributionPoisson distribution 2002 The Wadsworth GroupDiscrete vs Continuous VariablesDiscrete Variables:Can take on only certain values along an interval
4、the number of sales made in a weekthe volume of milk bought at a storethe number of defective partsContinuous Variables:Can take on any value at any point along an intervalthe depth at which a drilling team strikes oilthe volume of milk produced by a cowthe proportion of defective parts 2002 The Wad
5、sworth GroupThe Bernoulli Process,Characteristics1.There are two or more consecutive trials.2.In each trial,there are just two possible outcomes.3.The trials are statistically independent.4.The probability of success remains constant trial-to-trial.2002 The Wadsworth GroupThe Binomial DistributionTh
6、e binomial probability distribution defines the probability of exactly x successes in n trials of the Bernoulli process.for each value of x.Mean:=E(x)=n pVariance:s2=E(x )2=n p(1 p)2002 The Wadsworth GroupThe Binomial Distribution,An Example Worked by EquationProblem 6.23:A study by the Internationa
7、l Coffee Association found that 52%of the U.S.population aged 10 and over drink coffee.For a randomly selected group of 4 individuals,what is the probability that 3 of them are coffee drinkers?Number Proportion Coffee drinkers(x)3.52 Noncoffee drinkers 1.48Totals 4 1.00So,p=0.52,(1 p)=0.48,x=3,(n x)
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